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19:I[6549,["51","static/chunks/795d4814-710d199cb1f51304.js","183","static/chunks/183-141f39fb5cb93742.js","23","static/chunks/app/advice/%5Bid%5D/page-26686d89cc5a4cf8.js"],"CommentItemName"] 1a:I[3866,["51","static/chunks/795d4814-710d199cb1f51304.js","183","static/chunks/183-141f39fb5cb93742.js","23","static/chunks/app/advice/%5Bid%5D/page-26686d89cc5a4cf8.js"],"AdOnAdviceList1"] 1d:I[3866,["51","static/chunks/795d4814-710d199cb1f51304.js","183","static/chunks/183-141f39fb5cb93742.js","23","static/chunks/app/advice/%5Bid%5D/page-26686d89cc5a4cf8.js"],"AdOnAdviceList2"] 1e:I[3866,["51","static/chunks/795d4814-710d199cb1f51304.js","183","static/chunks/183-141f39fb5cb93742.js","23","static/chunks/app/advice/%5Bid%5D/page-26686d89cc5a4cf8.js"],"AdOnAdviceList3"] 1b:Tc2c,慶應経済の数学は独特の形式であるため、過去問を通じて対策を練る必要があります。 まず、慶應経済数学の採点の仕組みですが、マーク式の大問1-3で一定の点数(おそらく7割5分ほど)を取らないと記述式の大問4-6は採点されないことになっています。また、問題の難易度は、大問1-3は標準, 大問4-6はやや難しい場合が多いです。 これを考慮すると、時間配分と得点の取り方は  大問1-3 → 35分ほどで完答  大問4-6 → 45分ほどで2/3答 が望ましいです。 基本的に大問1-3は完答が理想です。今の段階ではまだ時間が足りないと思いますが、過去問を5年分ほど解いていくうちに身体が慣れていきます。 大問4-6ですが、誘導部分の小問は容易に解けることが多いです。誘導部分はしっかり得点を確保した上で、どれか1つは完答を目指しましょう。 2020年度の慶應経済数学について言うならば、  5分くらいで大問1-3を読む  大問2を10分で完答  大問3を12分で完答  大問1を10分で完答  5分くらいで大問4-6を読む  大問6 → 20分で完答  大問5 → (1)(2)を5分で解く  大問4 → (1)を3分で解く  残りの10分で残った問題を考える ということが実際の試験でできれば合格すると思います。 まず、大問1-3を見たときに、「1は考え方がちょっとややこしいな」「2と3はよくある考え方だから完答できそうだ」と思ってほしいです。こういう識別は過去問を解いていく内に身に付きます。1点でも多く取るためには確実に解けそうな問題から解いていくのが定石ですので、2→3→1の順番で解くと良いかと思います。 大問4-6を見たときは、「6はシンプルな考え方で解けそう」「4は座標を求めることはできそう」「5は単純な計算部分は解けそう」くらいに思えると良いです。4,5も完答できなくはないですが、そこに時間をかけて結果6に時間がまわらなくなるというのは良くないです。多少時間を掛けててでも6は完答しようと思えることが大事です。 秋以降の学習についてですが、私は標準〜応用問題を解いて思考力を磨きながら、抜けている基礎知識を確認して復習するということをやっていました。そして、自分でもある程度力がついたなと思えたら、自分の力を確認するために入試の過去問を解いていました(気晴らしに解くこともありました)。12月に入ってからは、9割を安定して取れるようになるまでセンターの対策に時間を使いました。センターの対策が終わってからは入試の過去問をひたすら解いていました。基礎知識や問題へのアプローチを身に付けておけば、この期間に得点はぐんぐん上がります。1c:Tf4d,相談拝見しました。 理系、共通テストの主な得点パターンについてお話しますね。 今の得点率を見たところ英語が得意そうなので、 ボーダー8割の場合は、 国語 7割 数学 8.5割 英語 9割 理科 8.5割 社会 7割 を目標にするといいと思います。 英語は基本的に安定してくるので、9割目安にしても大丈夫だと思いますが、数学理科はたまにブレるので、普段9割とかで、8.5割は安定して取れるようにしておくとかなり安心だと思います。 社会7割はかなり控えめに設定しました。今から暗記を進めれば、しっかりと8割超え狙っていける科目でもあると思います。 国語は、安定しないです。8割ボーダーなら、7割前後取り続けられればokだと思います。社会、数理がカバーできるようになってくると思うので 次に、この目標点に到達するための夏の過ごし方についてです。 数学は、問題パターンや時間の使い方に慣れてくれば必然的に上がってくると思うので、懸念すべきは理科だと感じています。 2次試験の事を考えても、理科はある程度点数取れる学力は必須です。 そのために、この夏で意識的に勉強すべきは理科だと考えます。 今のところ4,5割であれば、まずはセミナーやエクセルの基本問題をやるのが良いと思います。 他の勉強との兼ね合いもありますが、基本問題全範囲を1周、プラス間違えた問題をもう1周 というのを夏の理科の目標にしたいところです。 また、社会の暗記は始める必要があります。 夏が明け、秋に入り始めると、2次試験対策に力を入れ、11月ごろからは、共通テストの勉強の比重が高くなります。 なかなか社会の勉強にしっかりと時間を割けなくなっていくので、11月からの最後の追い込みに間に合うように、社会を進めていくことが必要です。 数学に関しては、学校の先生や塾予備校の指導が有れば、それに従う形で問題ないと思います。 もし、特に指導がないようでしたら、青チャート(私は使ったことありませんが focus gold)などの網羅系の問題集に取り組んでほしいです。 網羅系の問題集で、基礎を固めることは 共通テストの対策だけでなく2次試験の対策にも繋がります。また、しっかりと夏に数学の基盤が出来るようになることで、夏以降の問題演習の効率向上にも繋がります。 受験問題は、典型問題を組み合わせたような問題も多く出題されますので、秋からは そういった問題への対策に使いたいところです。そのために、まずは典型問題を解けるようにしておきたいです。 具体的には、網羅系の問題集の基本問題(青チャートなら、🧭3くらい)で、9割くらいの問題において、すぐ解法イメージが出来る、という段階までできると理想です。 国語や英語も全くやらないと学力落ちてくので、定期的にはやるようにしてください! 漢文に関しては、努力するとちゃんと比例して成績上がるのでおすすめです。 現代文・古文は、やっても伸びない人もいるのでなんとも言えないですが、まだ捨てる時期ではないです。 やるべきことはかなりたくさんあります。夏にやればいいや、って思ってると多分やりきれずに、秋に持ち越すことになるので(実体験です…)、夏休み入る前に早めに始めちゃうといいと思います!! 頑張ってください!2:["$","main",null,{"className":"px-4 pt-4 pb-4","children":["$","div",null,{"className":"max-w-3xl mx-auto w-full","children":[["$","div",null,{"className":"mb-8","children":["$","$L7",null,{"href":"https://unilink-app.onelink.me/isbO/h6xeh63x?advice=qdfVJWcBTqPwDZPuR1M5","target":"_blank","children":["$","$L8",null,{"src":"/images/web_to_app_banner.jpg","width":3660,"height":1500,"sizes":"100vw","style":{"width":"100%","height":"auto"},"alt":"UniLink WebToAppバナー画像","className":"mb-4 rounded"}]}]}],["$","h1",null,{"className":"text-xl font-semibold mb-2","children":"この数学の問題を教えて下さい🙇"}],["$","div",null,{"className":"flex justify-between mb-4","children":[["$","div",null,{"className":"text-left text-xs text-caption","children":["クリップ(",0,") コメント(",2,")"]}],["$","div",null,{"className":"text-right text-xs text-caption","children":"11/18 16:59"}]]}],["$","div",null,{"className":"coach-mark mb-4","children":"UniLink利用者の80%以上は、難関大学を志望する受験生です。これまでのデータから、偏差値の高いユーザーほど毎日UniLinkアプリを起動することが分かっています。"}],["$","div",null,{"className":"mb-4","children":["$","$L13",null,{"clientImageUrl":"https://firebasestorage.googleapis.com/v0/b/unilink-48e75.appspot.com/o/images%2Fs_gqJZ1R84SHRtqydT.jpg?alt=media&token=82c144b0-8aa1-44c4-b465-cfbcef3f826d","clientUserName":"ともくん","infoString":"高3 埼玉県 一橋大学経済学部(70)志望","adviceId":"qdfVJWcBTqPwDZPuR1M5"}]}],["$","div",null,{"className":"mb-8","children":[["$","div",null,{"className":"leading-loose whitespace-pre-wrap","children":[["$","div","consultation-part-0",{"children":[null,"問題を解いていたのですが、解説が何故そうなるか分からなかったので質問します。\n\n(問題)平方数を8で割った時、余りとして得られる数を全て求めなさい。ただし、平方数とは自然数の2乗になっている数のことである。\n\n(解説)自然数を8で割った余りは0,1,2,3,4,5,6,7のいずれかである。平方数を8で割った余りは、これらの2乗を8で割った余りに等しい。……………以下省略。\n\n何故解説のように求められるのですか?お忙しい中申し訳ありませんがよろしくお願いします。"]}]]}],["$","div",null,{"className":"pt-4","children":["$","$L14",null,{}]}]]}],["$","h1",null,{"className":"text-xl font-semibold mb-2","children":"回答"}],["$","div",null,{"className":"mb-4","children":["$","$L15",null,{"adviserImageUrl":null,"adviserName":"りーーー","adviserDepartment":"東北大学経済学部","adviceId":"qdfVJWcBTqPwDZPuR1M5"}]}],["$","div",null,{"className":"coach-mark mb-4","children":"すべての回答者は、学生証などを使用してUniLinkによって審査された東大・京大・慶應・早稲田・一橋・東工大・旧帝大のいずれかに所属する現役難関大生です。加えて、実際の回答をUniLinkが確認して一定の水準をクリアした合格者だけが登録できる仕組みとなっています。"}],["$","div",null,{"className":"mb-8","children":[["$","div",null,{"className":"leading-loose whitespace-pre-wrap","children":[["$","div","advice-part-0",{"children":[null,"自然数を8で割った余りは0〜7になるのは理解できると思います。\nそこで、nを自然数とすると、\n8で割った余りが\n0→8n\n1→8n 1\n2→8n 2\n3→8n 3\n4→8n 4\n5→8n 5\n6→8n 6\n7→8n 7\nとすることですべての自然数を表すことができます。問題で聞いているのは平方数ということなので、それぞれを2乗すると、\n\n0→64n^2=8×8n^2\n1→64n^2 16n 1=8(8n^2 2n) 1\n2→64n^2 32n 4=8(8n^2 4n) 4\n3→64n^2 48n 9=8(8n^2 6n 1) 1\n4→64n^2 64n 16=8(8n^2 8n 2)\n5→64n^2 80n 25=8(8n^2 10n 3) 1\n6→64n^2 96n 36=8(8n^2 12n 4) 4\n7→64n^2 112n 49=8(8n^2 14n 6) 1\n\nとなります。\nすべて(8n ○)^2という式になる以上、n^2とnの係数は8の倍数になるので、自然数部分である余りの2乗部分を8で割った時の余りが平方数の余りになります。\n\n長くなってすみません。わからなかったらまた質問してください。"]}]]}],["$","div",null,{"children":["$","$L7",null,{"href":"https://ck.jp.ap.valuecommerce.com/servlet/referral?sid=3364577&pid=884970531&vc_url=http%3A%2F%2Fshingakunet.com%2F%3Fvos%3Dnrmnvccp0000100","rel":"nofollow","target":"_blank","children":["$","$L8",null,{"src":"/images/document_request_banner.jpg","width":3660,"height":1500,"sizes":"100vw","style":{"width":"100%","height":"auto"},"alt":"UniLink パンフレットバナー画像","className":"mt-4 rounded"}]}]}],["$","div",null,{"className":"pt-4","children":["$","$L16",null,{"id":"adsbygoogle-init-under-advice"}]}]]}],["$","div",null,{"className":"flex justify-between","children":[["$","h1",null,{"className":"text-xl font-semibold","children":["コメント(",2,")"]}],["$","$L17",null,{"adviceId":"qdfVJWcBTqPwDZPuR1M5"}]]}],["$","div",null,{"className":"mb-8","children":["$","div",null,{"className":"divide-y","children":[["$","div",null,{"className":"flex py-4","children":[["$","div",null,{"className":"mr-2","children":["$","$L18",null,{"avatarUrl":"https://firebasestorage.googleapis.com/v0/b/unilink-48e75.appspot.com/o/images%2Fs_gqJZ1R84SHRtqydT.jpg?alt=media&token=82c144b0-8aa1-44c4-b465-cfbcef3f826d","contributorName":"ともくん","adviceId":"qdfVJWcBTqPwDZPuR1M5"}]}],["$","div",null,{"className":"flex-1","children":[["$","div",null,{"className":"flex justify-between","children":[["$","div",null,{"className":"mb-2","children":["$","$L19",null,{"contributorName":"ともくん","adviceId":"qdfVJWcBTqPwDZPuR1M5"}]}],["$","div",null,{"className":"text-xs text-caption","children":"11/18 17:08"}]]}],["$","div",null,{"className":"text-xs whitespace-pre-wrap","children":"なるほど!とても分かりやすかったです!\nお忙しい中ありがとうございました😊"}]]}]]}],["$","div",null,{"className":"flex py-4","children":[["$","div",null,{"className":"mr-2","children":["$","$L18",null,{"avatarUrl":null,"contributorName":"りーーー","adviceId":"qdfVJWcBTqPwDZPuR1M5"}]}],["$","div",null,{"className":"flex-1","children":[["$","div",null,{"className":"flex justify-between","children":[["$","div",null,{"className":"mb-2","children":["$","$L19",null,{"contributorName":"りーーー","adviceId":"qdfVJWcBTqPwDZPuR1M5"}]}],["$","div",null,{"className":"text-xs text-caption","children":"11/18 17:09"}]]}],["$","div",null,{"className":"text-xs whitespace-pre-wrap","children":"いえいえ、がんばってください!"}]]}]]}]]}]}],["$","h1",null,{"className":"text-xl font-semibold","children":"よく一緒に読まれている人気の回答"}],["$","div",null,{"className":"mb-8","children":["$","div",null,{"className":"divide-y","children":[["$","div",null,{"children":["$","$L7",null,{"href":"/advice/qdfVJWcBTqPwDZPuR1M5","children":["$","div",null,{"className":"flex items-center py-4","children":[["$","div",null,{"className":"flex-1 mr-3","children":[["$","div",null,{"className":"mb-1","children":"この数学の問題を教えて下さい🙇"}],["$","div",null,{"className":"text-xs text-caption line-clamp-2 mb-1","children":"自然数を8で割った余りは0〜7になるのは理解できると思います。\nそこで、nを自然数とすると、\n8で割った余りが\n0→8n\n1→8n 1\n2→8n 2\n3→8n 3\n4→8n 4\n5→8n 5\n6→8n 6\n7→8n 7\nとすることですべての自然数を表すことができます。問題で聞いているのは平方数ということなので、それぞれを2乗すると、\n\n0→64n^2=8×8n^2\n1→64n^2 16n 1=8(8n^2 2n) 1\n2→64n^2 32n 4=8(8n^2 4n) 4\n3→64n^2 48n 9=8(8n^2 6n 1) 1\n4→64n^2 64n 16=8(8n^2 8n 2)\n5→64n^2 80n 25=8(8n^2 10n 3) 1\n6→64n^2 96n 36=8(8n^2 12n 4) 4\n7→64n^2 112n 49=8(8n^2 14n 6) 1\n\nとなります。\nすべて(8n ○)^2という式になる以上、n^2とnの係数は8の倍数になるので、自然数部分である余りの2乗部分を8で割った時の余りが平方数の余りになります。\n\n長くなってすみません。わからなかったらまた質問してください。"}],["$","div",null,{"className":"flex mb-1","children":[["$","svg",null,{"stroke":"currentColor","fill":"currentColor","strokeWidth":"0","viewBox":"0 0 24 24","className":"text-subPrimary mr-1","children":["$undefined",[["$","path","0",{"fill":"none","d":"M0 0h24v24H0V0z","children":[]}],["$","path","1",{"d":"M12 6c1.1 0 2 .9 2 2s-.9 2-2 2-2-.9-2-2 .9-2 2-2m0 10c2.7 0 5.8 1.29 6 2H6c.23-.72 3.31-2 6-2m0-12C9.79 4 8 5.79 8 8s1.79 4 4 4 4-1.79 4-4-1.79-4-4-4zm0 10c-2.67 0-8 1.34-8 4v2h16v-2c0-2.66-5.33-4-8-4z","children":[]}]]],"style":{"color":"$undefined"},"height":16,"width":16,"xmlns":"http://www.w3.org/2000/svg"}],["$","div",null,{"className":"text-xs","children":["東北大学経済学部"," ","りーーー"]}]]}],["$","div",null,{"className":"flex 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items-center py-4","children":[["$","div",null,{"className":"flex-1 mr-3","children":[["$","div",null,{"className":"mb-1","children":"数学マークで8割取れない"}],["$","div",null,{"className":"text-xs text-caption line-clamp-2 mb-1","children":"こんにちは。回答させて頂きます。\n\nまず、マークで8割いかない状況でプラチカをやるのはかなり悪手だと思います。\nなぜならプラチカはマークで9割、記述で偏差値65くらいを取れてから更に上に行くために有効な参考書だからです。\n\n質問者様には一度基礎問題精巧をやることをオススメします。\nおそらく8〜8.5割ほどの問題は簡単に解けると思います。\nしかし、残りの1〜1.5割は解けない問題があると思います。そこにセンターで点数を取りきれない原因があると思います。"}],["$","div",null,{"className":"flex mb-1","children":[["$","svg",null,{"stroke":"currentColor","fill":"currentColor","strokeWidth":"0","viewBox":"0 0 24 24","className":"text-subPrimary mr-1","children":["$undefined",[["$","path","0",{"fill":"none","d":"M0 0h24v24H0V0z","children":[]}],["$","path","1",{"d":"M12 6c1.1 0 2 .9 2 2s-.9 2-2 2-2-.9-2-2 .9-2 2-2m0 10c2.7 0 5.8 1.29 6 2H6c.23-.72 3.31-2 6-2m0-12C9.79 4 8 5.79 8 8s1.79 4 4 4 4-1.79 4-4-1.79-4-4-4zm0 10c-2.67 0-8 1.34-8 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items-center py-4","children":[["$","div",null,{"className":"flex-1 mr-3","children":[["$","div",null,{"className":"mb-1","children":"下手な質問ですが、得点調整と得点率について"}],["$","div",null,{"className":"text-xs text-caption line-clamp-2 mb-1","children":"得点調整は平均点によってどのくらい調整されるかが変わります。ですので、7割取れても平均点が高いとダメだったりします。\n年度によって平均点と変化量は変わらないので自分の自己採点はあまり参考になりませんが、英7.5 国7 世8くらいでした。\n\nここで、得点調整の方法を一つ紹介します。\n\n得点調整は様々な方式で為されているそうなので一概には言えませんが、ものすごく簡略化してその求め方はこれだと自分は確信しています。\n\n\n調整後の得点=自分の得点-(平均点-満点/2)\n(各教科ごとに計算してください)\n\n平均点を下回るとこれよりもさらに下げられ、、大きく上回ると下げられた方が緩やかになりますが、大体この式に当てはめれば大丈夫です。\n\n例えば英語の平均点を2016年度の36点とします。満点は80点で自分の得点を50点として先ほどの式に当てはめると、\n54点=50-(36-80/2) になります。\n\nこれは得点が上昇しているケースで、平均点の値が独立変数であることが分かると思います。\n\n商学部の平均点は大体英6割 国5割 歴6割くらいで\nすので、この数式を使うと確かに6〜6.5割では落ちる可能性があります。それが7割程度必要と言われる理由です。\n長々しくてすみません。読んでおいて損はないと思うので是非参考にしてみてください。"}],["$","div",null,{"className":"flex mb-1","children":[["$","svg",null,{"stroke":"currentColor","fill":"currentColor","strokeWidth":"0","viewBox":"0 0 24 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items-center py-4","children":[["$","div",null,{"className":"flex-1 mr-3","children":[["$","div",null,{"className":"mb-1","children":"英語を捨てる選択はありか"}],["$","div",null,{"className":"text-xs text-caption line-clamp-2 mb-1","children":"英語がそこまで苦手なら共テ対策だけでいいと思います!\nただ、共テで8割は取りたいですね、\n\n正直、共テで8割取れるくらいになれれば私立でも英語で大きなディスアドバンテージを背負うこともないかと思います(きついところもありますが、、😅)駿台模試を見る限り、数学が相当できるということなので、私立の数学受験でいけば全然合格できると思いますね!もし早慶も受かりたいなら慶應の商はおすすめですね。英語は量が多いのですが一つ一つはそこまで難しくないので、そもそもの解く量を絞ってやれば大コケすることもないですし、数学の平均点が本当に低いのでそこで大差つけれます!社会もそこまで難しくないです👍\n\n共テ利用だけの併願は危険かもです。浪人覚悟で横国に集中したい!という考えなら全然アリなのですが、どこか合格がほしいなら一般も考えた方がいいですね。共テ利用で良いところ受かったら一般は出願だけで受験しないというのもお金はもったいないですが、受験戦略としてはアリだと思いますよ🫣\n\n最後に共テ英語8割いくために!みたいなテーマで少し書こうと思います🤏\nまずは単語です。本当に1冊で大丈夫です。何かやってください🙇🏻それだけで単語で困ることはあんまないと思うので!単語帳を何も持ってないということはないと思うのでそれをやってもらえばいいのですが、一応僕が使ってたのは東進のセンター1800ってやつでした。今は共通テスト1800って名前だったと思います。いい単語帳でしたよ👍\nあとは、共テは時間配分ですね。8割とはいえ基本は全問題にチャレンジしたいです。なので時間配分が鍵になるわけですが、これは練習しかありません。でもただ闇雲に解きまくっても効果は薄いでしょう。大問ごとに時間を決めて、大問ごとに演習を行ってみてください。大問の配分と言われてもピンとこないと思うので僕の配分を書いておきますね。ただ、僕は英語得意で共テは2年とも97だったので少し速めです😂あくまで参考にして自分の配分を考えてみてください!!😉\n1a 1.5分\n1b 2分\n2a 3分\n2b 4分\n3a 4分\n3b 5分\n4 15分\n5 12分\n6a 10分\n6b 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mb-1","children":"お久しぶりです。\n\nこれに全く乗っかる必要はないですが、共通テスト全振りもしくは9割でもいいというか、その方がいいかもしれません。あくまで私は、ですが、12月はセンター全振りでした。\n\nリーディング→時間を測って過去問を解いてはやり直し。読むスピードが上がってくれば点数も上がってくる。問題形式に慣れることが大事。\nリスニング→YouTube、ラジオやリスニング対策用の参考書を買ってできるだけ毎日英語に触れる\n数1A→時間を測って過去問を解いてはやり直し\n数2B→時間を測って過去問を解いてはやり直し\n(数学は過去問から攻略するしかないと思う。誘導に乗って答えを導く練習を過去問でやり込むしかない。)\n国語→時間を測って過去問を解いてはやり直しをする。国語を安定させたいならばやり直しはどの科目よりも時間をかける。どのように選択肢を絞れば正解にたどりつけたかを考える。\n物理基礎→教科書を一周又は何周かする。過去問もしくは参考書でひたすら問題演習をする。\n地学基礎→教科書を何周も読む。知識が頭に入った段階で過去問を解く。常に満点を目指す。\n日本史(私は世界史選択だったのでこれを基に)→学校の教科書やレジュメ全てを読み、何周も読んで知識を頭に入れる。知識を頭に入れつつ並行して過去問を回す。間違えたところは覚え直す。本番までに知識の詰め込みは2~3周したい。\n倫政→学校の教科書、資料集(黄色本でも良い)を読み込む。過去問を解く度に満点を目指す。特に最初は倫理分野の点数が安定しない(と思われる)ので、倫理分野を重点的に満点を取れるような知識の詰め込みをする。政経は知識を詰め込む。常に満点を目指すことが大事。\n\n極論、過去問を解く度に常に満点を目指して下さい。満点が取れなかったら、次解く時に満点を目指し、それを取るためにやり直しをして下さい。そうやっているうちに、過去問の点数は段々と上がってくると思います。\n直近3年分くらいは、各科目の点数を把握して、何割取れたかを測るために直前まで置いておくこともいいと思います。"}],["$","div",null,{"className":"flex 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items-center py-4","children":[["$","div",null,{"className":"flex-1 mr-3","children":[["$","div",null,{"className":"mb-1","children":"4技能試験 英検2級では受からないって本当ですか?"}],["$","div",null,{"className":"text-xs text-caption line-clamp-2 mb-1","children":"英検2級だから受からないのではなく、英検2級で出願して合格する人が少ないorほぼいないのだと思います。理由は2つです。\n\n⑴そもそも2級で2200はハードルが高い\n→調べた所、2級の合格ラインは1次が1520で、2次が460点、合計1980点のようです。はい。2200はかなりハードルが高いことがわかると思います。推測ですが各分野で9割近くの正答率が求められるのかと。\n\n2200という数字は英検準一にギリギリ届かないくらいのラインなので、だったら最初から準一を狙うという人が多いのでしょう。\n\n⑵英検2級レベルの英語力では、早稲田どころかマーチにも届かない\n→タイトル通りです。なので、英検2級を完璧にするための勉強は非常にコスパが悪いと感じます。故に最初から2級を使って受験するという人が上位層にはいないのだと思われます。\n\n以上、2つの理由から2級を使って合格を狙う人の母数がそもそも少ないと思われます。"}],["$","div",null,{"className":"flex mb-1","children":[["$","svg",null,{"stroke":"currentColor","fill":"currentColor","strokeWidth":"0","viewBox":"0 0 24 24","className":"text-subPrimary mr-1","children":["$undefined",[["$","path","0",{"fill":"none","d":"M0 0h24v24H0V0z","children":[]}],["$","path","1",{"d":"M12 6c1.1 0 2 .9 2 2s-.9 2-2 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