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としても、この解にダミー解は含まれません。これはどうしてでしょうか。後者では分母のtが消えて整数がでてくるのに対し、前者では元の式の両辺にtをかけることで、t(t2乗-2t-8)=0となり、新たなダミー解0が導かれるというのはわかるのですが、元の式の文字同士の次数の開きは同じなのに、(前者では0乗〜2乗、後者では-1〜1乗)と思うと、なんとなく腑に落ちません。初歩的な質"}],["$","link","4",{"rel":"icon","href":"/favicon.ico","type":"image/x-icon","sizes":"48x48"}],["$","link","5",{"rel":"icon","href":"/icon.png?2c0dc65a59843333","type":"image/png","sizes":"180x180"}],["$","link","6",{"rel":"apple-touch-icon","href":"/apple-icon.png?2c0dc65a59843333","type":"image/png","sizes":"180x180"}],["$","meta","7",{"name":"next-size-adjust"}]] 1:null 13:I[3903,["51","static/chunks/795d4814-710d199cb1f51304.js","183","static/chunks/183-141f39fb5cb93742.js","23","static/chunks/app/advice/%5Bid%5D/page-26686d89cc5a4cf8.js"],"ClientInfo"] 14:I[2798,["51","static/chunks/795d4814-710d199cb1f51304.js","183","static/chunks/183-141f39fb5cb93742.js","23","static/chunks/app/advice/%5Bid%5D/page-26686d89cc5a4cf8.js"],"AdUnderConsultation"] 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1a:I[3866,["51","static/chunks/795d4814-710d199cb1f51304.js","183","static/chunks/183-141f39fb5cb93742.js","23","static/chunks/app/advice/%5Bid%5D/page-26686d89cc5a4cf8.js"],"AdOnAdviceList1"] 1b:I[3866,["51","static/chunks/795d4814-710d199cb1f51304.js","183","static/chunks/183-141f39fb5cb93742.js","23","static/chunks/app/advice/%5Bid%5D/page-26686d89cc5a4cf8.js"],"AdOnAdviceList2"] 1e:I[3866,["51","static/chunks/795d4814-710d199cb1f51304.js","183","static/chunks/183-141f39fb5cb93742.js","23","static/chunks/app/advice/%5Bid%5D/page-26686d89cc5a4cf8.js"],"AdOnAdviceList3"] 1c:Tc93,数学と化学に関しては私も現役の時は心当たりがあります。特に数学はセンス的な要素が強いと思っていたので、解ける解けないの差が激しかったです。 さて、少しひねった問題が来ると解けないのが悩みということですが、まず、最低限の勉強ができていることが大事です。おそらくそこらへんはテスト期間で補っているので大丈夫かと思います。 その中で同じような問題で少しひねっている問題というのはどうすればいいかわからないと思うかもしれませんが、解き方としてはひねる前の解き方と同じようなのに気づくことはできているでしょうか?そのような問題の模範解答をじっくり吟味しているでしょうか?その時解けなかった問題はしょうがないですが、そのあとのフィードバックが大事です。そして、この解法やったことがあるなと感じることが大切です。 具体的に述べるのは難しいですが、例えば二次方程式の2解が正の値をとるための条件は f(0)>0 軸>0 判別式≧0 で必要十分ですよね。これは大丈夫でしょうか? これの少しひねった問題が例えば二次方程式の解が00 f(1)>0 0<軸<1 判別式≧0 で必要十分です。これと先ほどの上の条件と比較すると同じような感じですよね?つまり端点のみに具体的な数字の条件があるときにこのような条件で進めていくのがセオリーです。 上の解法を知識ゼロから解けと言われたら厳しいものがあるかと思いますが、一通り通っていることなら問題を見たときに「あっ、この問題はこの解法かな?」と瞬時に判断できるはずです。その感覚が大事です。「あー、これどうすればいいんだっけ…?」みたいな感じになっているのは良くないです。 これは勉強する時は問題を解き始める前に一瞬立ち止まって考えください。これを意識するしないとでは雲泥の差です。これは私自身、現役の時には気づかなかったことですが、浪人してからはこのことを意識するだけで、解ける問題のレパートリーが増えました。 闇雲にただ問題をこなすだけなら、むしろその場しのぎになってしまいます。それなら、数学の問題とかは時間がないのなら問題をみてこのような解法でいけばいいかなと思えるなら解かなくていいです。 要は、解き方に“意識“して問題演習を行ってください。時間のかける方はこっちの方です。 模試の前とかは、全国模試であれば定期テストなどでできなかった問題の教科書レベルの類題を確認する感じでいいと思います。高校生は部活等で時間がないと思われますので。1d:T13f3,こんにちは!RIZと申します。 問題集の問題は解けるけれど初見の問題では解けなくなるということですね。 まずとても当たり前の話をしますが、数学は問題文から解答を考えなければなりません。現在の、問題集の問題は解けるけれども初見の問題では手が止まってしまうというのは、単に問題集の答えを覚えているだけに他なりません。そこで、今回は初見の問題でも解けるようにするためにはどのようにすれば良いかについてお話しします。 前提として、数学の公式や定義はしっかり学習しているとします。もし質問文に書かれている数学用語というのがこうした公式や定義であるなら、定義はまずしっかり覚えてください。そして公式についてはできれば丸暗記するより、導出できるようにしたほうが良いです。ただもう時間があまりないので最悪丸暗記でもいいですが、導出できるようにすることで、なぜその公式が成り立つのか理解できるので覚えやすくもなりますし、もし忘れてしまっても対応できるようになるのでおすすめです。例えば三角関数の2倍角とか3倍角なんかは加法定理とか、数3ですがド・モアブルの定理などから簡単に導出できますよね。加法定理を毎回導出するのは流石に面倒ですが、2倍角や3倍角を加法定理から導出するのは少しの時間でできますよね。このようにあまり覚えていなくても簡単に導出できる公式はなるべく導出できるようにした方が良いです。 さて、話を戻しますが、以上のように公式や定義が頭に入っていることを前提として、初見の問題でどのように対処するべきかについてお話しします。まず冒頭でもお話ししたように、数学は問題文だけから解答を考えなければなりません。そこでまず、問題文の条件に着目します。条件というのはいろいろあります。例えばnを自然数とするとか、x、yが円の方程式を満たしているとか、垂直に交わるとか、さまざまです。他にも、直接的には書かれていないけれども重要な条件もあります。例えば与えられた式が対称式であるとかです。こうした条件から、解答を考えていきます。例えば上の例で言えば、nを自然数として、かつnに関する命題が与えられて証明しなさいといった問題であれば、自然数かつ証明問題であることから数学的帰納法が浮かびますし、x、yが円の方程式を満たしていて、かつx、yの2変数からなる関数の最大最小を考えたい時、xとyが円の方程式を満たすという条件から、θを媒介変数としてx、yをcosθとsinθで置くとかが考えられます。他にも、垂直に交わるという条件があれば、例えばその垂直に交わる直線の傾き同士の積は−1とか、内積0とか、あるいは図形的に三平方の定理を利用することも可能かもしれません。以上のように、条件を見たときにいろいろなことが考えられるようになることで、初見の問題で同じような条件が出てきたときに対応できます。もちろん入試問題というのは問題集には載っていない初見の問題である場合がほとんどです。なので普段解いている問題と全く同じでないのは当たり前ですが、条件に関して言えば部分的に共通していますよね。なのでこうしたことが想起できるようになれば、初見の問題でも対応できるようになるわけです。しかしこのように、条件を見てそこから解法を想起するというのは初見では無理ですよね。それを問題集から学ぶわけです。つまり、ただ問題を解いて、解けなかったら答えを見て覚えて終わりではなく、解法を見たとき、それが「なぜ」そうなるのかを考えます。そして、もし自分が初見でその問題を解くとしたら、まず問題文のどの条件に着目するのかを考えます。このようにすることで、解法のストックを増やしていくわけです。とにかく、解答を見たものでも初見だったらどうするのか、そして「なぜ」そうするのかまで説明できるようになることで、初見の問題でも、それまでストックした解法の引き出しから解法を想起でき、対応できるようになるわけです。なのでまずは今までやった問題集で、問題文のどの条件に着目して、「なぜ」その解答になるのか考えながら学習するようにしてみてください。以上になります。ご質問などありましたらコメント欄の方でお願いします!1f:Teab,こんにちは😃 現代文を解く上で最も大事なことはその文章が何を言いたいのかということを掴むことだと思います。 特に評論文などは筆者の主張が言葉を変えて、何回も登場してきます。だから、キーワードとなる語や繰り返し出てくる語にはチェックを付けて読んでいました。 また、二項対立で論じられている文章では一方の事柄については普通に線を引いて、もう一方の事柄については波線を引いていました。同じように筆者の中でプラスの事とマイナスの事も後から見て分かるように違うマークを付けて区別していました。共通テスト模試は時間制限も厳しく、丁寧な読解はなかなか厳しいですが、練習の中で主張の言い換えを見つけたり、対立軸を意識する事が大事になってくると思います。あと、当然ですが接続詞や文意を変えたりする表現には気をつけて読みましょう! なので、現代文を解く上で身につける力としては、その文章の言いたいことをできるだけ早く見抜くことです。 なかなか難しいことですが、これに関しては問題演習をして経験値を積むしかないです。実際にペンを持って言葉と言葉をつなげたり、文章にマークや線を引く練習をしていくことが最初の内はベストだと思います。 とにかく、自分の中で筆者の意見や考えが分類できていることが分かり、整理されていれば大丈夫です🙆‍♂️ また、完璧に筆者の言いたいことが分からなくても全然オッケーです。あくまで、問題に正解することがやるべきことで、主張を理解するのはそのための足掛かりですから。 あと、選択肢を消す際に数字や記号のところを消すのではなく、間違っている箇所に印を付けるクセも大切です。一発で答えが出せる設問もありますが、共通テストレベルの問題でもイヤらしい問題が多く、その場合消去法でしか消せない時があり、わずかな違いが大切になってくるからです。 それから、質問者さんがどのような形で現代文を取り組んでるか分かりませんが設問を先に読んで問われることを先に分かっておくことは共通テストの現代文を速く解く秘訣だと思います。選択肢までは見ないですが、共通テスト特有の図表やグラフの問題は先に見ておくと結構すぐに解けることがあります。 最後に、私もいつもできたわけではないですが、自分と文の筆者、そして作問者の3者を問題を解く際に意識してました。なぜこの文章を大学側が出し、ここに傍線部を持ってきているのか、共通テストであれ、個別入試であれ国語という入学試験である以上必ず意味があるはずです。問題を作っている人の意図や大学側の伝えたいメッセージを考えながら俯瞰して読めことができるようになれば現代文に関しては大丈夫です。 現代文の読解は人それぞれなので私の読み方が必ずしも正しいとは限りませんが、是非参考にして下さい! 受けておいた方がいい模試に関しては河合塾の早慶レベル模試や代ゼミの早大入試プレなどです。 やはり冠模試は実際の受験者が多く受けるので、自分の立ち位置を知る上で非常に役に立ちます。 また、質問があればぜひ聞いてください! 2:["$","main",null,{"className":"px-4 pt-4 pb-4","children":["$","div",null,{"className":"max-w-3xl mx-auto w-full","children":[["$","div",null,{"className":"mb-8","children":["$","$L7",null,{"href":"https://unilink-app.onelink.me/isbO/h6xeh63x?advice=ncC2I2YBTqPwDZPur3al","target":"_blank","children":["$","$L8",null,{"src":"/images/web_to_app_banner.jpg","width":3660,"height":1500,"sizes":"100vw","style":{"width":"100%","height":"auto"},"alt":"UniLink WebToAppバナー画像","className":"mb-4 rounded"}]}]}],["$","h1",null,{"className":"text-xl font-semibold mb-2","children":"方程式の両辺文字倍について"}],["$","div",null,{"className":"flex justify-between 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としても、この解にダミー解は含まれません。\nこれはどうしてでしょうか。\n後者では分母のtが消えて整数がでてくるのに対し、前者では元の式の両辺にtをかけることで、t(t2乗-2t-8)=0\nとなり、新たなダミー解0が導かれるというのはわかるのですが、元の式の文字同士の次数の開きは同じなのに、(前者では0乗〜2乗、後者では-1〜1乗)と思うと、なんとなく腑に落ちません。\n初歩的な質問で申し訳ありません(T_T)\n回答よろしくお願い致します。(.. )"]}]]}],["$","div",null,{"className":"pt-4","children":["$","$L14",null,{}]}]]}],["$","h1",null,{"className":"text-xl font-semibold mb-2","children":"回答"}],["$","div",null,{"className":"mb-4","children":["$","$L15",null,{"adviserImageUrl":null,"adviserName":"くまぷー","adviserDepartment":"九州大学医学部","adviceId":"ncC2I2YBTqPwDZPur3al"}]}],["$","div",null,{"className":"coach-mark mb-4","children":"すべての回答者は、学生証などを使用してUniLinkによって審査された東大・京大・慶應・早稲田・一橋・東工大・旧帝大のいずれかに所属する現役難関大生です。加えて、実際の回答をUniLinkが確認して一定の水準をクリアした合格者だけが登録できる仕組みとなっています。"}],["$","div",null,{"className":"mb-8","children":[["$","div",null,{"className":"leading-loose 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items-center py-4","children":[["$","div",null,{"className":"flex-1 mr-3","children":[["$","div",null,{"className":"mb-1","children":"河合塾のTテキストについて"}],["$","div",null,{"className":"text-xs text-caption line-clamp-2 mb-1","children":"240あったらほぼ確実にTだと思います。正直あのテキスト、特に英文解釈はめちゃくちゃレベルたかいです。よくポレポレが難しいと言われますがそれをを凌駕してると自分は思ってます。自分は前年にポレポレつかってましたが浪人生の時Tが十分すぎてほとんどポレポレは開きませんでした。ただあのレベルの文章を毎週解いて、読み込めばものすごく力はつきます!あと英文解釈と長文Tは音声ついてるのでそれを使ってガンガン音読しましょう。\n英文解釈Tは元々東大、京大、阪大の難しい和訳問題を、ターゲットにあててつくられています。なのでよくそこいらへんの大学の問題もでてきますが、多くの早慶合格者が乗り越え糧にしてきたものです。てかむしろT使えない人達からは早慶ほぼでないです。自信もってください!てかTじゃないテキストの問題とか多分簡単すぎてやりごたえなくてつまんないと思います。"}],["$","div",null,{"className":"flex mb-1","children":[["$","svg",null,{"stroke":"currentColor","fill":"currentColor","strokeWidth":"0","viewBox":"0 0 24 24","className":"text-subPrimary mr-1","children":["$undefined",[["$","path","0",{"fill":"none","d":"M0 0h24v24H0V0z","children":[]}],["$","path","1",{"d":"M12 6c1.1 0 2 .9 2 2s-.9 2-2 2-2-.9-2-2 .9-2 2-2m0 10c2.7 0 5.8 1.29 6 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items-center py-4","children":[["$","div",null,{"className":"flex-1 mr-3","children":[["$","div",null,{"className":"mb-1","children":"三角関数の変形の使い分けについて"}],["$","div",null,{"className":"text-xs text-caption line-clamp-2 mb-1","children":"質問者様は高2ということなので、数Ⅱまでの範囲で回答させていただきます。\n\n\n【三角関数を変形する目的】\n\nまず、三角関数を変形するのは必ず目的があります。\n①三角関数を含んだ方程式・不等式を解くため\n②三角関数を含んだ関数の最大値・最小値を求めるため\nなどがよくある目的ですね。\n\n《①について》\n方程式や不等式ははじめに因数分解で攻めます。\n(因数)(因数)=0\nといった形になれば、あとは簡単ですね。\n因数分解しない場合は②の考え方をそのまま借りましょう\n\n《②について》\nsinのみ、cosのみ、tanのみ、の式に帰着させます。そしたら見たことある関数(一次関数、二次関数など)になります。\nそのための手段として\n*三角関数の相互関係\n*加法定理を用いた公式\nなどが存在します。\n\n\n---------\n\n【質問主様の弱点と思われるところ】\n\n数Ⅱの三角関数に入ってからうまくいかなくなった高校生は加法定理を用いた公式につまづいている人が多いです。\n公式自体覚えていても、問題でうまく活用出来ないことがよくあります。\n\n先程の項目で書きました、変形のそもそもの目的を意識して演習してみてください。\n使い分けパターンは青チャートなどのテキストに詳しく記載されています。これを身につけることが大切です。\n\nパターンを繰り返しの演習で身につける際に、\n「因数分解を目指す!」\n「sinのみ、cosのみ、tanのみの式を目指す!」\nという意識を持って取り組むことで、何故その式変形を使うのかが体感出来ます。\n\n\n---------\n\n【最後に】\n\n問題のゴールから逆算して考えることが数学においては大切です。\n初めから逆算して考えることなんて出来ないから、パターンを演習によって身につけるわけですが、ゴールを意識してパターンを身につけなければ、何のためのパターンなのかがわかりません。\n必ず、式変形の目的を意識した演習を心掛けてください。"}],["$","div",null,{"className":"flex 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items-center py-4","children":[["$","div",null,{"className":"flex-1 mr-3","children":[["$","div",null,{"className":"mb-1","children":"法政AO落ち、一般で受けたい"}],["$","div",null,{"className":"text-xs text-caption line-clamp-2 mb-1","children":"間に合うかは確かにわかりません。それでも、自己推薦でダメだったけど志望校に行きたいと考え、前を向こうとしているあなたは素敵だと思います。その気持ちがあれば、仮に困難な道だったとしても、あと少し進んでいけると思います。\n\nここからは私の個人的な考えです。私は法政の受験経験もないですし、軽く調べただけなので、最終的には塾や学校、親御さんなどと相談してくださいね。\nおそらく質問者さんは、3教科よりも2教科のほうが対策しやすいから、という理由でT日程に決めたのではないかと思います(違ったらごめんなさい)。ただ、他の人も同じことを考えるんですね。そのため倍率も高くなりやすいですし、法政のT日程は英語が難しい、と聞いたことがあります。もし英語が得意なら、質問者さんにあっているかもしれませんね。\n\nもしほかの大学も受けたい、もしくはほかの学部も受けたい、というのが出てくる可能性があるのなら、社会科目にも手を付けたほうが確立が上がる可能性もあります。自己推薦がだめでもそこから社会科目も頑張って合格した人はいるので、相当の覚悟が必要なのはもちろんですが、全く可能性がないと悲観することはありません。ただ先ほども言った通り、これは私が考えたことでしかないので、周りの方にも相談して決めてください!\n\nそれでも、まだあと2か月以上あることですし、ここから巻き返すことは十分可能です。私自身、冬休みに相当巻き返した一人ですし、行きたい!という強い気持ちがあれば、納得のいく結果が得られると思います。\n\n質問者さんの意図とは違う答えでしたら申し訳ありません。少しでもお役に立てたらうれしいです。応援しています!"}],["$","div",null,{"className":"flex 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