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1c:Taee,初めまして、情報科学研究科の修士です。

簡単に言うと、三角比だけで定義すると汎用性がないから、座標を用いて拡張したためです。

　三角比というのはもともと直角三角形の「辺の比」として定義されました。例えば、cosθなら「隣辺/斜辺」、sinθなら「対辺/斜辺」というように、辺の長さの比をもとに求めるものです。
しかし、これだけでは第一象限（右上）しか表現することができず、汎用性がありません。そこで、三角比を90°以上にも拡張するためには、単位円という考え方を取り入れる必要があります。直角三角形は90°を超えると作れなくなってしまうので、これまでの「辺の比」だけでは説明ができません。そこで、半径1の円（単位円）を使い、x座標とy座標をもとに sin, cos, tan を定義する方法が導入されました。
単位円では、ある角θに対応する円周上の点の座標 (x, y) を使って三角比を考えます。具体的には、cosθ を「その点の x座標」、sinθ を「y座標」とし、tanθ は「sinθ / cosθ」、つまり「y座標 / x座標」と定義されます。すると、θが90°を超えた場合でも、単位円上の点の座標から sin, cos, tan を求めることができるようになるのです。
この考え方を用いると、θが90°を超えたとき、点 (x, y) は単位円の第2象限に入ります。このとき、x座標は負の値をとるため、cosθ（=x）は負になります。そして、tanθは「y/x」なので、xが負になることで tanθ も負になるわけです。一方、sinθは y座標に対応するため、第2象限（左上）では正の値を保ちます。こうして、三角比の値がマイナスになる理由が説明できます。

　つまり、もともと三角比は直角三角形の「辺の比」として考えられていましたが、それを90°以上にも拡張するために、単位円という座標の概念を使うようになったのです。単位円を使うことで、θの範囲を 0°～360°、さらには負の角やラジアンにも広げることができ、三角比の概念がより汎用的になりました。
したがって、「三角比は辺の比ではないのか？」という疑問に対しては、「もともとは辺の比として定義されたが、現在は単位円を使って拡張され、x座標・y座標をもとに考えるものになった」と理解するのがよいでしょう。これなら、cosθやtanθが負になる理由も納得できるはずです。

頑張ってください、健闘を祈っています。1d:Tf72,数学の応用問題を解くには二種類の力が必要です。
㊀定石 公式等の理解
㊁定石 公式等を使ってどう問題を解くか考える力

もし㊀ができていないと感じているならば チャートやその他の問題集を使って 分野別に勉強しましょう。

㊀はできているならば 融合問題を解くことで 考える力を養いましょう。
もし融合問題が見つからないというならば
Googleで 電数と調べてみてください。
各大学の過去問などが載っている 数学のサイトがあります。活用してみてください。

しかし”考える力”とはなんなのか 次の問題を解く際の僕の思考回路をお伝えしながら解いていこうと思います。

問題 Tan1°は有理数かどうか(2006年 京大)

僕の頭の中
㊀「三角関数かー 確信はないけどおそらく無理数やろうなあ、、 背理法かなんかで証明すればええんかな、、？」
ここまでは誰でも閃きそうですね。

㊁「有理数と無理数の話やから 分数うまく使って背理法やろうなぁ」
この発想は rute2の無理数証明での定石から思いつきます。

㊂「tan=a/bでおいてもどうしようもないなあ。 cos=b/rute a2 b2になるだけやしなあ。」
この発想から逃れるのは少し難しいかもしれませんが、何度か試すと これじゃダメだと気づくはずです。

㊃「ならどうやって分数の話に持ち込もうかな、、 あっ！ tanの加法定理って分数じゃなかったっけ！」
これは日常的にしっかりとtanの加法定理を意識できているかどうかですね。

㊄「じゃあどーせ背理法やし tan1°を有理数として 加法定理使ってみよかな。
 tan(1-0)=tan1-tan0/1-tan1tan0=tan1
あれ 元に戻ってもた。」
ここでのポイントはtan1を有理数として背理法を使うことですが、これは㊁から明らかですよね。rute2=a/bっておいて背理法するでしょ？

㊅「次tan2はどうやろか
tan2=tan(1 1)=tan1 tan1/1-tan1tan1
あれっ？ tan1が有理数なら tan2も有理数になってもたぞ！？」
ここが最大のポイント！
整数の問題全般に言えることですが、方針がたちづらい時は 数を増やしたりして実験しましょう。
∴例えば nが関わる問題なら n=1やn=2を代入してみるのです。

㊆「tan3=tan(1 2)=...  tan6=tan(3 3)
これ続けてったらtan@全部有理数になんね？   ってことはtan60も有理数なってまうやん！」
決定的な一打です。
㊇「ならtan1が有理数ならtan60も有理数なるってこと示して終了やな！」


僕の思考回路を砕いて説明しました。
この問題は入試において有名な難問ですが、 所詮はこの程度です。
思考回路に特別なセンスが感じられるところありましたか？ ないでしょう？
多くの定石を身につけていれば必然的にこのように解くことができるはずです。


自習で融合問題を解く際、わかってもわからなくても 自分で思考のフローチャートを書きながら解いてみてください。 
もし問題が解けたなら 解答をみて 自分のフローチャートと見比べてみましょう。 
問題が解けていないならば どこの発想が足りなかったのかしっかり分析しましょう。

長くなりましたが最後にまとめるならば
 「この問題解けない！ 解答みよ！ 」だけはやめましょう。 
「この問題 ここまではフローチャートかけたけど どうしてもここから進まない、、 
解答みて どの思考が足りなかったか確認しよう、」  こうしましょう。
まだまだ時間はあるので 頑張ってください！1e:Tcc2,こんにちは！
まず北大の冠でA判定が出る地点で、いわゆる基礎は問題ないどころか素晴らしいと思います。
一橋の問題って、どうにもこうにも問題が短すぎて意味わかんないの多いですもんね。

少し僕の話になってしまいますが、僕は理系から経済学部に進んだため一橋の問題も単元の確認で使ってました。

この時に一橋の問題について感じたのは、他大学とは異なり、条件を自分で絞らなければならないという傾向があまりにも強いと言うことです。
A問題は結構条件書いてあったりしますけどね。
あんじさんも薄々気づいているかとは思いますが、文章が短い分、解答に必須な条件は必ずと言っていいほど削ぎ落とされています。その条件を見つけ出すことさえできて仕舞えば、B問題くらいならあんじさんの手にかかればボッコボコに完答できると思います。

じゃあその条件とやらはどうすれば見つかるんだとお思いだと思います。

簡潔にいえば解法を絞らなければふわっと出てきます。

何を言っているんだと言われると少し難しいのですが、あんじさんが基礎完璧だからこそ言えることです。

例えば2005年の京大文系後期の三角比というか三角関数っぽい問題。(調べてみてくださいね)

一橋に似て、問題が圧倒的にキモいです。
ただ、今回の問題では三角関数の公式、和積とか積和を駆使すれば綺麗になります。
そうすると不思議なことに不等式の条件が出てくるんですね。(詳しくはMathmatics Monsterで三角関数のところに同様の問題がありますので見てみてくださいね)

このように、不等式→整数問題
　　　　　　sincos→三角関数
というような単調な問題は出ませんので、表面的に分かる情報をこねくりこねくりしてなんとか不等式などの情報を編み出す必要があります。

長々と何を言っているんだとお思いでしょうか？
やることはわかっているのだからあとは場数を踏むしかないということです。正直数学で点数を稼ぐのはおすすめできません。手の出ないようなB.Cの問題でも、一旦30分-60分くらい考えてこねくり回して、無理なら模範解答を見る。出来なくて不安なのは痛いくらいよく分かりますが、そういうものです。できる方がおかしいくらいの気持ちでいいと思います。

過去問は、複数回解くことでその大学の傾向を肌で覚えることを可能にし、気付きにくいでしょうけど合格への距離を相当近くしてくれます。なので解けないことにビビらず、どんどん解きましょう。そしてひたすらに解き直し、再現を何度もしましょう。これで基本はどうとでもなります。

なかなか難しく厳しい受験勉強、約半年後ある合格発表であんじさんが笑顔を浮かべられるよう、心からお祈りしています。1f:Tfc1,あるぶるさん、こんにちは。

今回は英語の和訳問題、説明問題の大きく2つに分けて解説していければと思います。

◎和訳問題

なぜいつも和訳で減点されてしまうのでしょうか。逆に、"減点されない"和訳とはなんでしょうか？まず初めに、"減点されない"和訳というのを説明したいと思います。

★"減点されない"和訳
①原文と違わない(構文把握、単語)
②原文なしで分かる(文脈)
③日本語として正しい

①、減点の多くはここです。構文がとれてなかった、単語の訳を間違えた、などなどキリがないです。単語を間違えれば当然減点されますし、構文も取れていなければ減点されます。

②、単語、構文は分かっているのに点がこない。それは文脈がとれていないからです。試しに、次の一文を訳してみてください。
I don't like him because he is rich.

どのように訳したでしょうか。
･彼は金持ちなので私は彼が好きではない
このように訳しましたか？これは正解です。ですがこのようにも訳せるのではないでしょうか。

･彼が彼を好きなのは彼が金持ちだからではない
これも正解です。これは所謂"否定の範囲"というやつですが、何が言いたいかというと文脈で英語の訳はいくらでも変化するということです。これだけでなく代名詞が何を指すのか、なども意識しなければ当然減点対象です。

③、傍線部中に"black-and-white television"と出てきたらどう訳しますか？当然、"白黒テレビ"と訳すと思います。しかし英語を直訳すれは"黒白テレビ"のはずです。これが"日本語として正しい"ということです。

英語の訳に意訳、直訳などというものはなくて、すべては上の3点です。上の3点がクリアされていれば減点されることは絶対にありません。とくに②、③は以後気をつけてみてください。

◎説明問題

説明問題については、回答作成の手順を解説したいと思います。

★説明問題の回答作成手順
①該当箇所の発見
②字数調整
③文末表現チェック

①、説明問題で点がこない大半はここが間違えています。説明問題の基本のキは該当箇所の発見です。どの模試の解説を読んでも、どの過去問を解いても、ほぼ必ず回答の根拠となる"該当箇所"があります。ここを外せば点はまず来ません。ですが心配することはありません。逆に言えば、該当箇所さえ発見してしまえばあとはそこをうまく訳すだけです。見つけた瞬間、"しめた！"と思ってください。

②、多くの説明問題にはこんな条件がついているのではないでしょうか。"𓏸𓏸字以内で" "𓏸𓏸字程度で"
これらの条件は、"ヒント"です。問題作成者がこのくらいかな、という目安をつけてくれているということです。これは該当箇所の発見に大きく役立ちます。また、"𓏸𓏸字以内"とは"-1割~ちょうど"、"𓏸𓏸字程度"とは"±1割"が一般的です。

③、ここで減点されてはもったいない。
「~な理由はなぜか」ときたら「~だから。」と書かなければいけないし、「~とはどういうことか」ときたら「~ということ。/~こと。」と書かなければいけません。最後に必ず文末表現のチェックを行いましょう。

和訳、説明問題はこれさえ押さえれば必ず得点源になります。ぜひ今回紹介したことを頭に入れたうえで模試などの解き直しを再度してみてください。こうすればよいのか、というのが分かるはずです。

応援してます、頑張ってください。2:["$","main",null,{"className":"px-4 pt-4 pb-4","children":["$","div",null,{"className":"max-w-3xl mx-auto w-full","children":[["$","div",null,{"className":"mb-8","children":["$","$L7",null,{"href":"https://unilink-app.onelink.me/isbO/h6xeh63x?advice=e1l3RibQK5KbKKDXkXST","target":"_blank","children":["$","$L8",null,{"src":"/images/web_to_app_banner.jpg","width":3660,"height":1500,"sizes":"100vw","style":{"width":"100%","height":"auto"},"alt":"UniLink WebToAppバナー画像","className":"mb-4 rounded"}]}]}],["$","h1",null,{"className":"text-xl font-semibold mb-2","children":"三角比の変換は45度以下にして解くのはなぜ"}],["$","div",null,{"className":"flex justify-between mb-4","children":[["$","div",null,{"className":"text-left text-xs text-caption","children":["クリップ(",1,") コメント(",4,")"]}],["$","div",null,{"className":"text-right text-xs text-caption","children":"3/19 18:14"}]]}],["$","div",null,{"className":"coach-mark mb-4","children":"UniLink利用者の80%以上は、難関大学を志望する受験生です。これまでのデータから、偏差値の高いユーザーほど毎日UniLinkアプリを起動することが分かっています。"}],["$","div",null,{"className":"mb-4","children":["$","$L13",null,{"clientImageUrl":"https://firebasestorage.googleapis.com/v0/b/unilink-48e75.appspot.com/o/images%2Fs_5cWSjwl8nNNx07dPzCZo4Z4IWvL2.jpg?alt=media&token=ff0fd940-a746-4acf-8fb6-23d4362180de","clientUserName":"かやの","infoString":"中学 兵庫県 京都大学工学部(65)志望","adviceId":"e1l3RibQK5KbKKDXkXST"}]}],["$","div",null,{"className":"mb-8","children":[["$","div",null,{"className":"leading-loose whitespace-pre-wrap","children":[["$","div","consultation-part-0",{"children":[null,"三角比の変換を利用してsin,cos,tanの値を求める問題で例として\nsin140°+cos130°+tan120°を求める問題で、私はsin(90°+50°)-cos(180°-50°)-√3=-√3とやって答えはあっていたのですが、解説では45°以下にするためにsin(180°-40°)+cos(90°+40°)-√3\nとしていました。\n他の問題も45°以下に揃えると解説されているのですがこういう類の問題はすべて45°以下にするのでしょうか？\nそれとも、その解説者の好みで45°以下にしているだけで別に私のようにその問題ごとに都合のいい値(引き算してゼロになるなど)を見つけるやり方でいいのでしょうか？"]}]]}],["$","div",null,{"className":"pt-4","children":["$","$L14",null,{}]}],null]}],["$","h1",null,{"className":"text-xl font-semibold mb-2","children":"回答"}],["$","div",null,{"className":"mb-4","children":["$","$L15",null,{"adviserImageUrl":"https://firebasestorage.googleapis.com/v0/b/unilink-48e75.appspot.com/o/images%2Fs_MHGnZRybHfZHeLicXrTl9HYdhPB2.jpg?alt=media&token=93666ae3-ac67-4528-be2c-7d8d8edb6c7a","adviserName":"清水","adviserDepartment":"東京大学工学部","adviceId":"e1l3RibQK5KbKKDXkXST"}]}],["$","div",null,{"className":"coach-mark mb-4","children":"すべての回答者は、学生証などを使用してUniLinkによって審査された東大・京大・慶應・早稲田・一橋・東工大・旧帝大のいずれかに所属する現役難関大生です。加えて、実際の回答をUniLinkが確認して一定の水準をクリアした合格者だけが登録できる仕組みとなっています。"}],["$","div",null,{"className":"mb-8","children":[["$","div",null,{"className":"leading-loose whitespace-pre-wrap mb-4","children":[["$","div","advice-part-0",{"children":[null,"もちろんその解説通りにやらなくても答えを合わせることができるなら大丈夫です！ただそのように解説を書かれた解説者さんの意図をご説明します。\n\n　結論から言うと45°以下に絞ることで三角比に一意性が生まれます。表し方が一通りに絞られるということです。\n\n　例えば今回の問題を借りさせてもらうと、sin140°という値は他にsin40°、−cos130°、cos50°とも表せます。（説明は割愛させて頂きます。）これが45°以下にするという縛りを課すとこの値を三角比で表す方法はsin40°のみになります。\n　cos130°も他に−cos50°、−sin40°、−sin140°の表し方ができますが、45°以下にすれば−sin40°になるわけです。\n　30°、45°など直接三角比を求める事ができる有名角以外の角度が出てくる問題は計算していけば必ず打ち消し合うようになっているので、45°以下の制限により表し方を一通りに絞ることで符号だけ違う同じものが出てきて消えてくれるよねっていうことです。他のやり方をしても、結局頭の中では同じことをしていることになると思います。\n\n\n　確実で再現性が高い方法を身につけるのは凄く大事なことですから、解説者さんもそれなりに意図があってその書き方を選択されたのだと思います。このくらいの問題ならわざわざ解説に従って解答を書かなくてもいいですが、難しい問題でこういった方針を採用することで問題が見えやすくなったりすることもあるので役立ててみてください！"]}]]}],["$","div",null,{"className":"mb-4","children":["$","$L16",null,{"adviserImageUrl":"https://firebasestorage.googleapis.com/v0/b/unilink-48e75.appspot.com/o/images%2Fs_MHGnZRybHfZHeLicXrTl9HYdhPB2.jpg?alt=media&token=93666ae3-ac67-4528-be2c-7d8d8edb6c7a","adviserName":"清水","adviserDepartment":"東京大学工学部","adviceId":"e1l3RibQK5KbKKDXkXST","numberOfFan":11,"clipsAvg":1.15,"adviceRateAvg":5,"profile":"予備校浪人と仮面浪人を両方経験しているので、独自の視点でアドバイスができると思います！\n回答が少しでも役に立ちましたら📎して頂けると大変励みになります🙏\nなるべく生感のある情報をお伝えします！\n気に入って頂けたら遠慮なく直接ご質問ください！\n\n広島中高一貫→駿台広島→早稲田理工→東大理科II類→東大工学部"}]}],["$","div",null,{"children":["$","$L7",null,{"href":"https://ck.jp.ap.valuecommerce.com/servlet/referral?sid=3364577&pid=884970531&vc_url=http%3A%2F%2Fshingakunet.com%2F%3Fvos%3Dnrmnvccp0000100","rel":"nofollow","target":"_blank","children":["$","$L8",null,{"src":"/images/document_request_banner.jpg","width":3660,"height":1500,"sizes":"100vw","style":{"width":"100%","height":"auto"},"alt":"UniLink 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text-caption","children":"4/4 10:37"}]]}],["$","div",null,{"className":"text-xs whitespace-pre-wrap","children":"すみません、今日復習していて思いました。\nどの問題においても、45度以下で表して解くというのはありでしょうか？\nそれとも最初からその心構えではなく、45度以下に出来そうだなー、という心構えでやるべきでしょうか？"}]]}]]}],["$","div",null,{"className":"flex py-4","children":[["$","div",null,{"className":"mr-2","children":["$","$L19",null,{"avatarUrl":"https://firebasestorage.googleapis.com/v0/b/unilink-48e75.appspot.com/o/images%2Fs_MHGnZRybHfZHeLicXrTl9HYdhPB2.jpg?alt=media&token=93666ae3-ac67-4528-be2c-7d8d8edb6c7a","contributorName":"清水","adviceId":"e1l3RibQK5KbKKDXkXST"}]}],["$","div",null,{"className":"flex-1","children":[["$","div",null,{"className":"flex justify-between","children":[["$","div",null,{"className":"mb-2","children":["$","$L1a",null,{"contributorName":"清水","adviceId":"e1l3RibQK5KbKKDXkXST"}]}],["$","div",null,{"className":"text-xs text-caption","children":"4/4 17:26"}]]}],["$","div",null,{"className":"text-xs whitespace-pre-wrap","children":"ありだと思います！\n三角比の大半の問題はそうすることで見やすくなるかそのまま答えが出せるはずなので。（ただ、三角関数の分野まで行くと、45°以下に縛ることの効果がないことが多いです。）必ずその解き方を使うというよりは、三角比の問題でパッと解き方や方針が見えなかったりした時に一旦45°以下に縛って計算を進めてみるのが良いかと思います！"}]]}]]}],["$","div",null,{"className":"flex py-4","children":[["$","div",null,{"className":"mr-2","children":["$","$L19",null,{"avatarUrl":"https://firebasestorage.googleapis.com/v0/b/unilink-48e75.appspot.com/o/images%2Fs_5cWSjwl8nNNx07dPzCZo4Z4IWvL2.jpg?alt=media&token=ff0fd940-a746-4acf-8fb6-23d4362180de","contributorName":"かやの","adviceId":"e1l3RibQK5KbKKDXkXST"}]}],["$","div",null,{"className":"flex-1","children":[["$","div",null,{"className":"flex justify-between","children":[["$","div",null,{"className":"mb-2","children":["$","$L1a",null,{"contributorName":"かやの","adviceId":"e1l3RibQK5KbKKDXkXST"}]}],["$","div",null,{"className":"text-xs text-caption","children":"4/5 8:56"}]]}],["$","div",null,{"className":"text-xs whitespace-pre-wrap","children":"ありがとうございます！\n数学の問題の解き方の勉強にもなりました！"}]]}]]}]]}]}],["$","h1",null,{"className":"text-xl font-semibold","children":"よく一緒に読まれている人気の回答"}],["$","div",null,{"className":"mb-8","children":["$","div",null,{"className":"divide-y","children":[["$","div",null,{"children":["$","$L7",null,{"href":"/advice/jBDlO4nqFfOSXxhK6xb5","children":["$","div",null,{"className":"flex items-center py-4","children":[["$","div",null,{"className":"flex-1","children":[["$","div",null,{"className":"mb-1","children":"三角比のcos(tan)がマイナスになる理由が分からない"}],["$","div",null,{"className":"text-xs text-caption line-clamp-2 mb-1","children":"勉強お疲れ様です。\n中学生で高校数学をやっているなんて\nびっくりです。\n\nまず、三角比は直角三角形の鋭角に対して\n定義されています。\nなので、三角比においてはsin、cos、tanは\nすべて正の値となります。\n\nそれに対し、三角関数は単位円の座標から\n求めるものです。\n\nなので三角関数では、sin、cos、tanは\n負になる事もあるという事です。\n\n\nただ、三角関数は三角比の考え方を\n拡張したものなので、\n三角関数を考える際に直角三角形を\n用いる事ができます。\n(むしろその方が分かりやすいです。)\n\n例えばcos150°が何になるかを考えて見て下さい。\n\n単位円上では、cosはx座標に対応しますね。\n単位円で30°の直角三角形と、\n150°~180°の間で形成される30°を\nひとつの角とした直角三角形を\n書いてみてください。\nこの時、これらの三角形がy軸を中心に\n線対称となっている事がわかります。\n\nこの事から、cos150°にマイナスをつけて\n正の値にしたものはcos30°に等しくなる事が\nわかります。\n\nつまり\ncos150°=－cos30°=－√3/2\nと求められます。\n\n\nこのように考える事で、\n第二象限、第三象限、第四象限の三角関数を\n第一象限の三角比から求める事ができます。\n\n理解していただけたでしょうか。\n少しでも参考になれば幸いです。\n何か質問があれば遠慮なく聞いて下さいね。\n勉強頑張って下さい！！"}],["$","div",null,{"className":"flex mb-1","children":[["$","svg",null,{"stroke":"currentColor","fill":"currentColor","strokeWidth":"0","viewBox":"0 0 24 24","className":"text-subPrimary mr-1","children":["$undefined",[["$","path","0",{"fill":"none","d":"M0 0h24v24H0V0z","children":[]}],["$","path","1",{"d":"M12 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items-center py-4","children":[["$","div",null,{"className":"flex-1","children":[["$","div",null,{"className":"mb-1","children":"三角比のcos(tan)がマイナスになる理由が分からない"}],["$","div",null,{"className":"text-xs text-caption line-clamp-2 mb-1","children":"まず、三角比では、直角三角形を用いた定義を考えるのですが、0°＜θ＜90°での定義を考えると、単純に辺の比になります。(これはあなたがご存知の通りだと思います) \n\nしかし、90°より大きくなるとどうなるんだろう？という疑問が出てくるわけです。90°より大きいと直角三角形で考えることはできませんよね。\n\nそこで、単位円が出てくるわけです。単位円を用いることで、90°より大きい角に関しても考えられるようになるわけです。(この時にマイナスが出てくるわけです)\n\nこれらを踏まえて答えると、三角比が辺の比だから正というのは、あくまで0°から90°の時だけ。それ以外の時はこの考えは通用しません。\n\n単位円が優れているのは、辺の比で考えられる0°から90°を含むどんな角に対しても有効だということです。\n\nですから、数Ⅱで学ぶ三角関数を視野に入れると、「基本的に三角比は単位円で考えるものと考えておくもので、0°から90°という『特殊』な時は辺の比で考えることもできる」という意識でいると良いでしょう。\n\nあなたのご質問に回答するとき、誤魔化さない勉強は大事だと、筆者自身再認識出来ました。お互い精進していきましょう！！"}],["$","div",null,{"className":"flex mb-1","children":[["$","svg",null,{"stroke":"currentColor","fill":"currentColor","strokeWidth":"0","viewBox":"0 0 24 24","className":"text-subPrimary 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items-center py-4","children":[["$","div",null,{"className":"flex-1","children":[["$","div",null,{"className":"mb-1","children":"三角比のcos(tan)がマイナスになる理由が分からない"}],["$","div",null,{"className":"text-xs text-caption line-clamp-2 mb-1","children":"こんにちは！私もここの単元の同じところで悩んだことがあるのでお答えします！\n\n結論から言いますと、辺の比というよりも座標の値からsinθ、cosθ、tanθのを求めるという考え方に近いと思います。厳密にいうと「辺の比と\"向き\"」を考慮して三角比を算出しているため正負が存在します。分かりやすくいうと、平面座標（単位円上）で考えると三角関数は角度や長さのみではなく「座標の正負」も関与している、ということです！\n\n例えば、\n・cosであればx座標。（底辺の長さの座標）\n　　θ＝π/4の場合　x＝1/√2 \n　　θ＝3π/4の場合　x＝−1/√2\n\n・sinであればy座標。（高さの座標）\n　　θ＝π/3の場合　y＝√3/2\n          θ＝4π/3の場合　y＝−√3/2\n\n・tanであれば斜辺の傾き\n　　θ＝π/4の場合は　傾き＝1\n　　θ＝3π/4の場合は　傾き＝−1\n\n以上のようになります。\n三角関数は、「長さの比」というよりも「座標上の値の比」として考えた方がしっくりくると思います！！"}],["$","div",null,{"className":"flex mb-1","children":[["$","svg",null,{"stroke":"currentColor","fill":"currentColor","strokeWidth":"0","viewBox":"0 0 24 24","className":"text-subPrimary mr-1","children":["$undefined",[["$","path","0",{"fill":"none","d":"M0 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items-center py-4","children":[["$","div",null,{"className":"flex-1","children":[["$","div",null,{"className":"mb-1","children":"助けてくださいby三角比でつまづいた高1文一志望"}],["$","div",null,{"className":"text-xs text-caption line-clamp-2 mb-1","children":"　何がわかんないのかわかんないんでなんとも言えないんですが、正直難しい単元ではないので集中的に3.4日程度時間取ればほぼ仕上げることはできると思いますよ。高一なら苦手単元に時間を割いてもあまり痛くないですし、むしろ極端な苦手は気合入れて一気に直しちゃった方がいいですから、4日くらい三角比(関数？)漬けになってみてください。きっとできるようになります。\n　ちなみにそれでも完璧にならない！って場合でも、基礎さえできてれば正直三角比(関数)はほっといても良いです。後々数学に接してると死ぬほど出てくるんで勝手にできるようになります。ただし基礎さえできてれば、ですよ！　僕も昔は苦手でした。\n\n　一つ大事なのは、焦らずに落ち着いて勉強することです。わかんない！やばい！って思いながら勉強してると、不思議なことにどんだけやってもわかんないので、落ち着いて、噛み締めるように勉強していってください。まだ高一ですから焦らずに。"}],["$","div",null,{"className":"flex mb-1","children":[["$","svg",null,{"stroke":"currentColor","fill":"currentColor","strokeWidth":"0","viewBox":"0 0 24 24","className":"text-subPrimary mr-1","children":["$undefined",[["$","path","0",{"fill":"none","d":"M0 0h24v24H0V0z","children":[]}],["$","path","1",{"d":"M12 6c1.1 0 2 .9 2 2s-.9 2-2 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