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an-1)=bnと置き換えたのですがan-1の項があるせいでb1とb2が求められませんでした。表記が見にくく申し訳ありません。お答えいただければ幸いです。an-1は第n-1項のような取り方で見てください。"}],["$","link","4",{"rel":"icon","href":"/favicon.ico","type":"image/x-icon","sizes":"48x48"}],["$","link","5",{"rel":"icon","href":"/icon.png?2c0dc65a59843333","type":"image/png","sizes":"180x180"}],["$","link","6",{"rel":"apple-touch-icon","href":"/apple-icon.png?2c0dc65a59843333","type":"image/png","sizes":"180x180"}],["$","meta","7",{"name":"next-size-adjust"}]] 1:null 13:I[3903,["51","static/chunks/795d4814-03346c8d233b4adb.js","212","static/chunks/212-70508e17017a12c2.js","231","static/chunks/231-5dc9f3acdba63b0c.js","54","static/chunks/54-f848f8ba1c362ca7.js","23","static/chunks/app/advice/%5Bid%5D/page-186819a87df201a3.js"],"ClientInfo"] 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1a:I[6549,["51","static/chunks/795d4814-03346c8d233b4adb.js","212","static/chunks/212-70508e17017a12c2.js","231","static/chunks/231-5dc9f3acdba63b0c.js","54","static/chunks/54-f848f8ba1c362ca7.js","23","static/chunks/app/advice/%5Bid%5D/page-186819a87df201a3.js"],"CommentItemName"] 1c:I[3866,["51","static/chunks/795d4814-03346c8d233b4adb.js","212","static/chunks/212-70508e17017a12c2.js","231","static/chunks/231-5dc9f3acdba63b0c.js","54","static/chunks/54-f848f8ba1c362ca7.js","23","static/chunks/app/advice/%5Bid%5D/page-186819a87df201a3.js"],"AdOnAdviceList1"] 1b:Tc1f, こういった問題独自の定義は、だいたい文字を含んでいることが多いです。例えば、 ・「nを正の整数とし、3^nを10で割った余りをanとする。」(東京大2016文系) ・「正の整数nの各位の数の和をS(n)で表す。」(一橋大2018) ・「nを2以上の整数とする。金貨と銀貨を含むn枚の硬貨を同時に投げ、裏が出た金貨は取り去り、取り去った金貨と同じ枚数の銀貨を加えるという試行の繰り返しを考える。初めはn枚すべてが金貨であり、n枚すべてが銀貨になった後も試行を繰り返す。k回目の試行の直後に、n枚の硬貨の中に金貨がj枚だけ残る確率をPk(j)(0≦j≦n)で表す。」(東北大2019文系) のように。あなたが挙げて下さった例でもそうですね。  ご存知のように、数学で文字が使われるのはそこに入る値が不特定であるときなので、逆にいえば、自分で具体的な値を代入して実験してみれば良いわけです。k-連続和でいえば、m=1、k=2とすると、3=1+2という等式になり、3は2-連続和であることになります(相談文のk+1はおそらくkー1の間違いですね。でなければ、nはk+2個の連続する自然数の和になってしまうので)。ちゃんと、n(3)がk(2)個の連続する自然数(1→2)の和であるという定義に則ってますね。2019年文系の確率も、例えばk=1を代入してみると、P1(j)は「n枚の金貨を同時に投げ、そのうちj枚が表で他が裏になる確率」のことを言っているのだとわかります(ちなみにこれは小問⑴)。反復試行の確率を考えればすぐ解けますね。すると、次はk=2、その次はk=3、と実験数をどんどん増やしていけば、Pk(j)の内容もいずれわかるはずです。試行の手順上、残るj枚は必ず全ての試行において表でなければならず、他方それ以外の金貨はすべて、k回のうちのどこかで裏が出ればいい(全て表で残る場合の余事象)わけですから、「n枚の金貨のうち、k回の試行の直後に残るべきj枚はk回とも全て表が出て、それ以外のn−j枚はk回の試行で少なくとも一回裏が出る確率」とわかります。ここまで日本語として簡略化できれば、Pk(j)(特に、k≧2)の値もそこまで苦戦せずに出せそうですね(ちなみにこれは小問⑵)。  このように、なるべく簡単な値から代入して実験を繰り返すことで、独自の定義が何を言っているのかは帰納的に理解できることが多いです。文字が多かったり、分かりにくい表現だったりして、複雑で難しく感じる定義が出てきたら、まずは実験してみることを心がけると良いと思います。文系の問題ですが、もしまだ解いてない場合はネタバレになってしまい申し訳ございません。1d:Tcc2,こんにちは! まず北大の冠でA判定が出る地点で、いわゆる基礎は問題ないどころか素晴らしいと思います。 一橋の問題って、どうにもこうにも問題が短すぎて意味わかんないの多いですもんね。 少し僕の話になってしまいますが、僕は理系から経済学部に進んだため一橋の問題も単元の確認で使ってました。 この時に一橋の問題について感じたのは、他大学とは異なり、条件を自分で絞らなければならないという傾向があまりにも強いと言うことです。 A問題は結構条件書いてあったりしますけどね。 あんじさんも薄々気づいているかとは思いますが、文章が短い分、解答に必須な条件は必ずと言っていいほど削ぎ落とされています。その条件を見つけ出すことさえできて仕舞えば、B問題くらいならあんじさんの手にかかればボッコボコに完答できると思います。 じゃあその条件とやらはどうすれば見つかるんだとお思いだと思います。 簡潔にいえば解法を絞らなければふわっと出てきます。 何を言っているんだと言われると少し難しいのですが、あんじさんが基礎完璧だからこそ言えることです。 例えば2005年の京大文系後期の三角比というか三角関数っぽい問題。(調べてみてくださいね) 一橋に似て、問題が圧倒的にキモいです。 ただ、今回の問題では三角関数の公式、和積とか積和を駆使すれば綺麗になります。 そうすると不思議なことに不等式の条件が出てくるんですね。(詳しくはMathmatics Monsterで三角関数のところに同様の問題がありますので見てみてくださいね) このように、不等式→整数問題       sincos→三角関数 というような単調な問題は出ませんので、表面的に分かる情報をこねくりこねくりしてなんとか不等式などの情報を編み出す必要があります。 長々と何を言っているんだとお思いでしょうか? やることはわかっているのだからあとは場数を踏むしかないということです。正直数学で点数を稼ぐのはおすすめできません。手の出ないようなB.Cの問題でも、一旦30分-60分くらい考えてこねくり回して、無理なら模範解答を見る。出来なくて不安なのは痛いくらいよく分かりますが、そういうものです。できる方がおかしいくらいの気持ちでいいと思います。 過去問は、複数回解くことでその大学の傾向を肌で覚えることを可能にし、気付きにくいでしょうけど合格への距離を相当近くしてくれます。なので解けないことにビビらず、どんどん解きましょう。そしてひたすらに解き直し、再現を何度もしましょう。これで基本はどうとでもなります。 なかなか難しく厳しい受験勉強、約半年後ある合格発表であんじさんが笑顔を浮かべられるよう、心からお祈りしています。1e:T13f3,こんにちは!RIZと申します。 問題集の問題は解けるけれど初見の問題では解けなくなるということですね。 まずとても当たり前の話をしますが、数学は問題文から解答を考えなければなりません。現在の、問題集の問題は解けるけれども初見の問題では手が止まってしまうというのは、単に問題集の答えを覚えているだけに他なりません。そこで、今回は初見の問題でも解けるようにするためにはどのようにすれば良いかについてお話しします。 前提として、数学の公式や定義はしっかり学習しているとします。もし質問文に書かれている数学用語というのがこうした公式や定義であるなら、定義はまずしっかり覚えてください。そして公式についてはできれば丸暗記するより、導出できるようにしたほうが良いです。ただもう時間があまりないので最悪丸暗記でもいいですが、導出できるようにすることで、なぜその公式が成り立つのか理解できるので覚えやすくもなりますし、もし忘れてしまっても対応できるようになるのでおすすめです。例えば三角関数の2倍角とか3倍角なんかは加法定理とか、数3ですがド・モアブルの定理などから簡単に導出できますよね。加法定理を毎回導出するのは流石に面倒ですが、2倍角や3倍角を加法定理から導出するのは少しの時間でできますよね。このようにあまり覚えていなくても簡単に導出できる公式はなるべく導出できるようにした方が良いです。 さて、話を戻しますが、以上のように公式や定義が頭に入っていることを前提として、初見の問題でどのように対処するべきかについてお話しします。まず冒頭でもお話ししたように、数学は問題文だけから解答を考えなければなりません。そこでまず、問題文の条件に着目します。条件というのはいろいろあります。例えばnを自然数とするとか、x、yが円の方程式を満たしているとか、垂直に交わるとか、さまざまです。他にも、直接的には書かれていないけれども重要な条件もあります。例えば与えられた式が対称式であるとかです。こうした条件から、解答を考えていきます。例えば上の例で言えば、nを自然数として、かつnに関する命題が与えられて証明しなさいといった問題であれば、自然数かつ証明問題であることから数学的帰納法が浮かびますし、x、yが円の方程式を満たしていて、かつx、yの2変数からなる関数の最大最小を考えたい時、xとyが円の方程式を満たすという条件から、θを媒介変数としてx、yをcosθとsinθで置くとかが考えられます。他にも、垂直に交わるという条件があれば、例えばその垂直に交わる直線の傾き同士の積は−1とか、内積0とか、あるいは図形的に三平方の定理を利用することも可能かもしれません。以上のように、条件を見たときにいろいろなことが考えられるようになることで、初見の問題で同じような条件が出てきたときに対応できます。もちろん入試問題というのは問題集には載っていない初見の問題である場合がほとんどです。なので普段解いている問題と全く同じでないのは当たり前ですが、条件に関して言えば部分的に共通していますよね。なのでこうしたことが想起できるようになれば、初見の問題でも対応できるようになるわけです。しかしこのように、条件を見てそこから解法を想起するというのは初見では無理ですよね。それを問題集から学ぶわけです。つまり、ただ問題を解いて、解けなかったら答えを見て覚えて終わりではなく、解法を見たとき、それが「なぜ」そうなるのかを考えます。そして、もし自分が初見でその問題を解くとしたら、まず問題文のどの条件に着目するのかを考えます。このようにすることで、解法のストックを増やしていくわけです。とにかく、解答を見たものでも初見だったらどうするのか、そして「なぜ」そうするのかまで説明できるようになることで、初見の問題でも、それまでストックした解法の引き出しから解法を想起でき、対応できるようになるわけです。なのでまずは今までやった問題集で、問題文のどの条件に着目して、「なぜ」その解答になるのか考えながら学習するようにしてみてください。以上になります。ご質問などありましたらコメント欄の方でお願いします!1f:Tf02,センター試験の集合は、実数の集合を扱うことが多いため、数直線上に図示するのが有効なことが多いです。 目盛の間隔を正確に図示する必要はなく、それぞれの端の大小と、黒丸白丸があっているかが重要です。(黒丸の場合はその点を含む、白丸の時はその点を含まないことを表します。不等号に=が入っているかどうかの違いとも言えます。) 例えば、 p: x>1 q:x≦2 のように与えられていた時、右向きの数直線上に左から1と2の点を書きます。 pについては、x>1(つまり「xは1より大きい」)であることから、先ほど書いた1の点に白丸を書き、そこから右上がりに少し直線を書き、そこから右向きに直線を伸ばします。新幹線のような形になります。この形は、1の点を含まないことを表すもので、白丸と同じ意味ですが、ぱっと見で分かるように両方使います。また、この線がpであることをどこかに書いておいてください。 qについては、x≦2(つまり「xは2以下」)であるので、2の点に黒丸を書き、そこから真下に少し直線を書き、左向きの直線を伸ばします。こちらは、電車のような形になります。この形は、2を含むことを表すもので、黒丸と同じ意味です。こちらの線にも、qであることを書いておいてください。 このように、範囲を一つ一つ図示していくと、次のようになります。 _______________ p / 2 ---------○-----●------->x 1 | q --------------- これを見れば、「pかつq」や、「pまたはq」「p⇒q は真か偽か」はすぐに分かるはずです。たとえば「pかつq」なら、pとqが重なっているところなので、1-(1/2)<(an)/2^n>=2\n\nとなります。\n\n(an)/2^nをcnとすると、(cn+1)=(1/2)(cn)+2\n\nこれを変形して、(cn+1)-4=(1/2)<(cn)-4>\n\nつまり(cn)-4=(-7/2)・(1/2)^n-1=(-7)・(1/2)^n\n\nよってcn=4-7・(1/2)^n\n\nこの両辺に2^nをかけてan=4・2^n-7 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items-center py-4","children":[["$","div",null,{"className":"flex-1","children":[["$","div",null,{"className":"mb-1","children":"参考書の進め方どっちがいい?教えてください!"}],["$","div",null,{"className":"text-xs text-caption line-clamp-2 mb-1","children":"結論から言うと③です。\n名大等の旧帝大と言われる難関大の数学では主に数三が合格の肝となります。\n\n数Aの確率\n数Bの数列\n数Cのベクトル・複素数\nは特に典型問題より発想を必要とする問題が出てくる可能性が高いと思います。\n入試においては全員が得点を取る問題を確実に点数とし、応用系の問題の部分点を取るというのが基本ベースになります。\n\n逆に、数三の微積分は演習を重ねるとある程度点数が取れるようになり安定もしてきます。\nですが得点を取るためには相当量(おそらく数1A2BCと同じまたもっと)が必要になってきます。\n\n長くなりましたが、このため私がお勧めする演習方法は、\nチャート数2BC→文系の数学 実践力向上編\n→数3 うかる計算→1対1ですかね、、、\n特に数3は計算演習が大切なので基礎的な問題でも時間をかけて解いていきましょう。\n秋口には過去問に取り組みたいので少しスピードアップして行くと良いと思います!!\nわからないことがあればいつでも相談ください"}],["$","div",null,{"className":"flex mb-1","children":[["$","svg",null,{"stroke":"currentColor","fill":"currentColor","strokeWidth":"0","viewBox":"0 0 24 24","className":"text-subPrimary mr-1","children":["$undefined",[["$","path","0",{"fill":"none","d":"M0 0h24v24H0V0z","children":[]}],["$","path","1",{"d":"M12 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