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1c:T126b,ずんだこんにちは！
  初めて解いた過去問が2021年度なんですか😱
心配しなくてもその年の共通テストは難しすぎて(特に数学は受験生の平均が30点台)初めて解くにはあんまりよろしくないセットでした。
リアルな話普通のレベルだったら全体的にもう少し取れる実力はあると思います！あんまりショックを受けずにさっと切り替えて受験生モードに入っていきましょう！とはいえ、確かに志望校を考えると国語、数学、英語は7〜8割程度は取りたいですね、、、とりあえずちょうど1年前となる同日模試に向けて取り組んでもらいたいことをまとめますね。その同日模試での成績を踏まえてもう一度ご相談いただきたいなと思います。正直1年後のずんださんがどれくらいの成績を取れるかなんてわかりません、、🙏ただひとつだけ言えることは本当に本気で取り組めば全教科の総得点で9割以上取ることだって可能だし、逆に少しでも途中で怠けてしまえば4割くらいしか取れないかもしれないです。いい意味でも悪い意味でも可能性は無限大です。

・同日までにやるべきこと
　2023年度の共通テストまではあと2週間ほどですが、まだ2年生の場合この2週間はだいぶやれることが多いです。国語と数学、英語に分けて紹介します！理科はまあまだ学校でもノータッチでしょうしまだ大丈夫です笑
①国語
　国語は時間配分がけっこう大事です！80分で4題大問がありますが、何も考えずに取り組めば時間が絶対足りないとはずです。まずは自分の中で作戦を考える。調べてみると色々な作戦があると思います。例えば古漢から解くとか、選択肢を先に読んでから本文を解くとか。
これに正解はないのでまずは自分で考え、1月13日、試してみましょう！！(あくまでも自分の場合は漢文→古文→評論→小説の順で解き、評論は問題文を読んでから本文を読み、他は本文を読んでから解いてました)
②数学
　国立志望なら共テ対策なんていらないと思ってます。(今の段階では！！)
高3になるまでにⅠAⅡBは青チャートの最低でもコンパス3つ、できたらコンパス4つレベルの問題は完璧にしましょう。完璧にするというのはその問題を見たときに解法がぱっと浮かび、全て何も見ずにすらすらと記述解答できるようになることです。私の以前の回答に青チャートの取り組み方について書いてあるものがありますのでよかったら参考にしてみてください。個別の相談もお待ちしております！！
　確かに同日ではあまり点数が取れずに不安になるかもしれませんが、1年後のことを考えたときに現時点では、解法が縛られてしまい誘導に乗る力が必要とされる共通テスト対策よりは自分で1から解答を組み立てられる力をつけていた方が絶対にいいです。
③英語
　英語はまずは単語がかなり重要になってきます。高3までに1周目はやるようにしましょう。私の場合は鉄壁を1月ごろに1周、3月ごろには3周ほどやり、高3の夏休み以降は単語帳自体は開かなかったです。それくらい今のうちから単語力を固め、受験生活の大詰めになった際に単語覚えなきゃ！ということにならないようにすることが大切です。また共通テストだけに限らず、最近の英語の問題は情報処理をかなり早く、正確に行う必要があります。英語アレルギーにならないためにも、今のうちから英語長文によく触れておきましょう。共通テストではあまり文法などには細かく触れる必要がないのでとにかく英文に触れ、1日に1回は英文を聞くようにできると、かなり成長できると思います。
私は『study now』というアプリをよく使ってスキマ時間に学習していました。おすすめです！

　とりあえずはこんなところだろうと思います！あまりあせらず、目先のことばかりを目標にせずに着実に成長していきましょう💪
いつでも相談やお悩みなどにございましたらコメント欄やDMでご相談くださいね。応援しています。1年あればいくらでも伸びます！1e:Tefe,こんにちは！

ここでは
⭐️① おすすめの教科の比率
⭐️② 高3までに日本史の通史どこまで進めるか
⭐️ ③ 高3の5月の模試の偏差値の目安

⭐️① まず科目の配分についてですが私立文系の3教科の中で英語が一番大切なのは言うまでもないと思います。
早稲田大学のだいたいの学部（教育と人間科学部の2つは3教科同じ配点）では英語の配点がもっとも高いです。
慶應大学でも文系学部では全て英語の配点が最も高いためやはり私立文系の中では英語が最も重要です。
その中で具体的な教科の比率ですが自分は

英語4.5現代文1古文漢文1.5選択科目3（自分は日本史でした。）
ではなぜこのような配分にしてたかというと英語がまず最もやることが多く受験生が早慶レベルまで届かない人が多いです。そのため英語に全体の半分弱くらいの労力をかけていました。また国語は暗記とかではあまりないので当日の運も必要だなと思っていました。また、選択科目は自分は日本史でしたがこれはとにかくやればやるだけ点数が上がるので非常に大切だと思います。

⭐️② 通史は高3の8月（もちろん早ければ早いだけいい）までにある程度終わらせることが大切です！ですので高3になるまでに明治時代に入る手前くらいまで終わらせればいいのかなと思います！！基本用語をまずは押さえていきましょう！！

⭐️③ まず偏差値何までいけば受かるとか言うことは言えないので自分の話になってしまうのですが自分はおそらく東進の6月の模試で偏差値は60くらいはあったと思います。高2の夏くらいは偏差値は50も無かったですがそこからはかなりどの教科も上がっていました。（ただ国語に関してはかなり模試によってばらつきがあり、最後まで安定しなかったです。）

具体的な各教科ごとの偏差値ですが自分は英語60国語55日本史65みたいな感じだったと思います。
ただ、ここまで偏差値について話してきましたがぶっちゃけあまり気にする必要はないです。その理由は早慶やMARCHの私大を受ける方には共通テストの模試や記述模試というのはあくまで目安にしかならなくて、結局最後に志望校の合格点が取れるかどうかにかかっています。ここを必ず肝に銘じて欲しいなと思います。どんな偏差値でも大切なのは最後に過去問に太刀打ちできるかどうかにかかっています。
では模試を受ける意義ですが自分の立ち位置が少しわかるとともに1番大切なのは弱点を発見するということです。今古文ができてないとか、日本史、世界史のこの時代が弱いなとかそういうのをわからせてくれるのが模試の役割だと思っています。模試を受けてやる気をなくしたり、ネガティブになるのではなく、弱点を発見したと思ってポジティブに考えて欲しいなと思います。
長くなりましたがゴール（志望校の過去問を解けるようになる）というのを決して見失わずに頑張ってください！！

参考になれば幸いです！！また、いつでも何か聞きたければこちらのコメントでお答えするのでお気軽にどうぞ！（答えられる範囲で答えます！）

また、UniLink パートナーのオンライン受験相談も実施しています！興味がある方はメッセージよろしくお願いします！！！2:["$","main",null,{"className":"px-4 pt-4 pb-4","children":["$","div",null,{"className":"max-w-3xl mx-auto w-full","children":[["$","div",null,{"className":"mb-8","children":["$","$L7",null,{"href":"https://unilink-app.onelink.me/isbO/h6xeh63x?advice=TWCWs7sAwPradPWAChx8","target":"_blank","children":["$","$L8",null,{"src":"/images/web_to_app_banner.jpg","width":3660,"height":1500,"sizes":"100vw","style":{"width":"100%","height":"auto"},"alt":"UniLink WebToAppバナー画像","className":"mb-4 rounded"}]}]}],["$","h1",null,{"className":"text-xl font-semibold mb-2","children":"間違っているとおもう。"}],["$","div",null,{"className":"flex justify-between mb-4","children":[["$","div",null,{"className":"text-left text-xs text-caption","children":["クリップ(",0,") コメント(",1,")"]}],["$","div",null,{"className":"text-right text-xs text-caption","children":"5/14 18:10"}]]}],["$","div",null,{"className":"coach-mark mb-4","children":"UniLink利用者の80%以上は、難関大学を志望する受験生です。これまでのデータから、偏差値の高いユーザーほど毎日UniLinkアプリを起動することが分かっています。"}],["$","div",null,{"className":"mb-4","children":["$","$L13",null,{"clientImageUrl":null,"clientUserName":"ズンクス","infoString":"高1 北海道 京都大学工学部(65)志望","adviceId":"TWCWs7sAwPradPWAChx8"}]}],["$","div",null,{"className":"mb-8","children":[["$","div",null,{"className":"leading-loose whitespace-pre-wrap","children":[["$","div","consultation-part-0",{"children":[null,"友達に問題を出されました。自作だそうです。\n「π^2が3の倍数でないことを示せ。」\n条件足りなくないですか？友達が間違っている気がします。\n私はやってみたんですが、なんか間違っている回答ができました。あまり証明とかやっていないので回答自体が変かもしれません。\n三の倍数だと仮定する。\nπ^2=3kとおく。\nk=π^2/3\nよってkは三の倍数\nk+1=π^2+3/3\nよってk+1は三の倍数\n矛盾が生じるのでk、k+1は三の倍数ではない。\nこのことよりπ^2は三の倍数でない。\n\nわかる方。間違っているとわかる方教えてください。"]}]]}],["$","div",null,{"className":"pt-4","children":["$","$L14",null,{}]}]]}],["$","h1",null,{"className":"text-xl font-semibold mb-2","children":"回答"}],["$","div",null,{"className":"mb-4","children":["$","$L15",null,{"adviserImageUrl":null,"adviserName":"黒澤","adviserDepartment":"京都大学工学部","adviceId":"TWCWs7sAwPradPWAChx8"}]}],["$","div",null,{"className":"coach-mark mb-4","children":"すべての回答者は、学生証などを使用してUniLinkによって審査された東大・京大・慶應・早稲田・一橋・東工大・旧帝大のいずれかに所属する現役難関大生です。加えて、実際の回答をUniLinkが確認して一定の水準をクリアした合格者だけが登録できる仕組みとなっています。"}],["$","div",null,{"className":"mb-8","children":[["$","div",null,{"className":"leading-loose whitespace-pre-wrap","children":[["$","div","advice-part-0",{"children":[null,"答えさせていただきます。まず、ズンクスさんの解答で言えば、k=(π^2)/3が3の倍数になっている点がまず正しくないです。ここでは、π^2が3の倍数(3k)であるという仮定があるので、kは3の倍数かどうか不明な整数になるはずです。おそらく、「3の倍数」を、「なにかの数を3で割ってできる数」と誤解されているのだと思われます。3の倍数とは、「3で割り切れる整数」のことです。\n\nこれを踏まえ、以下に簡潔な解答を示させていただきます。その前に、ヒントを残しますので、先にヒントを読んで考えてみて、それから解答を確認してみて下さい。\nヒント:π=3.141592…は、そもそも二乗して整数にならないのではないか？\n\n以下解答です。\n\nまず、3<π<3.15により、\n 9<π^2<3.15^2=9.9225<10である。\n従って、π^2は9と10の間にあるから、整数でない。よって、π^2は3の倍数でない。(証明終)\n\n厳密には、π<3.15を示す必要があるのですが、高校一年生の範囲での証明は難しく、今回は省略させていただきます。π>3については、半径1の円に内接する正六角形の周の長さと円周を比べていただければほとんど自明です。\n\nおそらく、そのお友達の出題の背景には、かつてゆとり教育で「円周率を3として扱う」場面があったことへの皮肉があると思われます。もしそうであれば、π^2は9で、当然3の倍数になります。\n\n話がそれましたが、ある数が整数でないことを示すには、その数に近そうな整数との大小を比較してあげるのが非常に効果的です。"]}]]}],["$","div",null,{"children":["$","$L7",null,{"href":"https://ck.jp.ap.valuecommerce.com/servlet/referral?sid=3364577&pid=884970531&vc_url=http%3A%2F%2Fshingakunet.com%2F%3Fvos%3Dnrmnvccp0000100","rel":"nofollow","target":"_blank","children":["$","$L8",null,{"src":"/images/document_request_banner.jpg","width":3660,"height":1500,"sizes":"100vw","style":{"width":"100%","height":"auto"},"alt":"UniLink パンフレットバナー画像","className":"mt-4 rounded"}]}]}],["$","div",null,{"className":"pt-4","children":["$","$L16",null,{"id":"adsbygoogle-init-under-advice"}]}]]}],["$","div",null,{"className":"flex justify-between","children":[["$","h1",null,{"className":"text-xl font-semibold","children":["コメント(",1,")"]}],["$","$L17",null,{"adviceId":"TWCWs7sAwPradPWAChx8"}]]}],["$","div",null,{"className":"mb-8","children":["$","div",null,{"className":"divide-y","children":[["$","div",null,{"className":"flex py-4","children":[["$","div",null,{"className":"mr-2","children":["$","$L18",null,{"avatarUrl":null,"contributorName":"ズンクス","adviceId":"TWCWs7sAwPradPWAChx8"}]}],["$","div",null,{"className":"flex-1","children":[["$","div",null,{"className":"flex justify-between","children":[["$","div",null,{"className":"mb-2","children":["$","$L19",null,{"contributorName":"ズンクス","adviceId":"TWCWs7sAwPradPWAChx8"}]}],["$","div",null,{"className":"text-xs text-caption","children":"5/14 21:07"}]]}],["$","div",null,{"className":"text-xs whitespace-pre-wrap","children":"ありがとうございます！勘違いしていたことが発見できてよかったです。\n証明もしてくださり勉強になりました。\n友達に教えてもらった回答とほぼ一緒だったので安心しました。\nこれからも勉強頑張ります。\n"}]]}]]}]]}]}],["$","h1",null,{"className":"text-xl font-semibold","children":"よく一緒に読まれている人気の回答"}],["$","div",null,{"className":"mb-8","children":["$","div",null,{"className":"divide-y","children":[["$","div",null,{"children":["$","$L7",null,{"href":"/advice/TWCWs7sAwPradPWAChx8","children":["$","div",null,{"className":"flex items-center py-4","children":[["$","div",null,{"className":"flex-1 mr-3","children":[["$","div",null,{"className":"mb-1","children":"間違っているとおもう。"}],["$","div",null,{"className":"text-xs text-caption line-clamp-2 mb-1","children":"答えさせていただきます。まず、ズンクスさんの解答で言えば、k=(π^2)/3が3の倍数になっている点がまず正しくないです。ここでは、π^2が3の倍数(3k)であるという仮定があるので、kは3の倍数かどうか不明な整数になるはずです。おそらく、「3の倍数」を、「なにかの数を3で割ってできる数」と誤解されているのだと思われます。3の倍数とは、「3で割り切れる整数」のことです。\n\nこれを踏まえ、以下に簡潔な解答を示させていただきます。その前に、ヒントを残しますので、先にヒントを読んで考えてみて、それから解答を確認してみて下さい。\nヒント:π=3.141592…は、そもそも二乗して整数にならないのではないか？\n\n以下解答です。\n\nまず、3<π<3.15により、\n 9<π^2<3.15^2=9.9225<10である。\n従って、π^2は9と10の間にあるから、整数でない。よって、π^2は3の倍数でない。(証明終)\n\n厳密には、π<3.15を示す必要があるのですが、高校一年生の範囲での証明は難しく、今回は省略させていただきます。π>3については、半径1の円に内接する正六角形の周の長さと円周を比べていただければほとんど自明です。\n\nおそらく、そのお友達の出題の背景には、かつてゆとり教育で「円周率を3として扱う」場面があったことへの皮肉があると思われます。もしそうであれば、π^2は9で、当然3の倍数になります。\n\n話がそれましたが、ある数が整数でないことを示すには、その数に近そうな整数との大小を比較してあげるのが非常に効果的です。"}],["$","div",null,{"className":"flex mb-1","children":[["$","svg",null,{"stroke":"currentColor","fill":"currentColor","strokeWidth":"0","viewBox":"0 0 24 24","className":"text-subPrimary mr-1","children":["$undefined",[["$","path","0",{"fill":"none","d":"M0 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items-center py-4","children":[["$","div",null,{"className":"flex-1 mr-3","children":[["$","div",null,{"className":"mb-1","children":"三角比はある程度理解してとばしたほうがいいのか？"}],["$","div",null,{"className":"text-xs text-caption line-clamp-2 mb-1","children":"こんにちは！受験勉強お疲れ様です！\n\nまず数Ⅱで習う三角関数ですが、これは数Ⅰで習う三角比を関数として拡張したものになります。そのため、三角比との用途はある程度異なるものになります。三角関数は関数としての側面が重視されますが、三角比は図形問題に置ける使用がほとんどです。\n\n計算問題としての三角比の応用問題であれば、三角関数を理解することで十分対応が可能であると考えられますが、三角比を用いた図形問題になれることも大切でしょう。そしてこれら、三角比を用いた図形問題は、共通テストでも必ず出題されます。そのため、三角比の問題をしっかりこなすことは必ず意味がある行為です。\n\n三角比を用いた図形問題に早いうちから触れておくことは重要ですし、三角比をきちんと理解することで三角関数の正確な理解にも繋がります。\n\nそして、一般に受験生としては先取りを早く進めることも重要ですが、その都度分野を深く理解することが大切です。\n\n私自身、先取りを高一で数Ⅲまで行っていましたが、経験上、その都度先取りした分野はある程度完璧にしておかないと、先取りの意味があまり無くなってしまいます。先取りが終わった後あまり完成度が高くなければ、本末転倒です。\n\nとはいえ、分野を周回しているうちに、習熟度も上がっていくのも事実です。そのため、図形的な応用はもちろん、三角比についてきちんと理解しながら、先取りを進めていくことがベストでしょう。\n\n私のおすすめの勉強法は先取りをしつつ、勉強した分野を定期的に復習するという勉強法です。学校の定期テストや模試などをペースメーカーにして復習するのも良いでしょう。そうすることで先取りかつ取りこぼしなく勉強できます。\n\n長くなりましたが、まとめると\n1.三角比には図形問題という側面が大きく三角関数が完全に互換性のあるものではないということ\n2.先取りは分野ごとにある程度仕上げる必要があり、復習とのバランスが大切だということ\n3.復習のペースメーカーには定期テストや模試を有効活用できるということ\n以上3点です。\n\n受験勉強頑張ってくださいね！志望校合格をお祈りしています✨"}],["$","div",null,{"className":"flex 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items-center py-4","children":[["$","div",null,{"className":"flex-1 mr-3","children":[["$","div",null,{"className":"mb-1","children":"(sinx)^2 - (sinx)^4の積分について"}],["$","div",null,{"className":"text-xs text-caption line-clamp-2 mb-1","children":"公式というほどでもないですが\nIn=∫(0→π/2)(sinx)^n dxと置き、(sinx)^nをsinx(sinx)^n-1に分けて部分積分をすると\nIn=(n-1)/n × In-2という関係式が成り立ちますので\nそれを利用していると思われます。\nこの漸化式は数3でよく出てくるので覚えていてもいいかもしれません。"}],["$","div",null,{"className":"flex mb-1","children":[["$","svg",null,{"stroke":"currentColor","fill":"currentColor","strokeWidth":"0","viewBox":"0 0 24 24","className":"text-subPrimary mr-1","children":["$undefined",[["$","path","0",{"fill":"none","d":"M0 0h24v24H0V0z","children":[]}],["$","path","1",{"d":"M12 6c1.1 0 2 .9 2 2s-.9 2-2 2-2-.9-2-2 .9-2 2-2m0 10c2.7 0 5.8 1.29 6 2H6c.23-.72 3.31-2 6-2m0-12C9.79 4 8 5.79 8 8s1.79 4 4 4 4-1.79 4-4-1.79-4-4-4zm0 10c-2.67 0-8 1.34-8 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items-center py-4","children":[["$","div",null,{"className":"flex-1 mr-3","children":[["$","div",null,{"className":"mb-1","children":"数3を高2のいつまでに終わらせるのが理想か"}],["$","div",null,{"className":"text-xs text-caption line-clamp-2 mb-1","children":"最低高3の春には終わらせるべきですね。東大は数3が好きなので数3のウェイトは数1A2Bと4:6くらいは少なくともあるのではないでしょうか？計算力が要求される一方、解法のパターンは割と限定的なので努力次第で点の取れる分野とも言えます。独学で学ぶならチャートのようなタイプの問題集をこなしてネットでオススメされているような演習書をこなした後で過去問を回せば点を伸ばせると思います。やはりある程度過去問に慣れる必要はあると思うので"}],["$","div",null,{"className":"flex mb-1","children":[["$","svg",null,{"stroke":"currentColor","fill":"currentColor","strokeWidth":"0","viewBox":"0 0 24 24","className":"text-subPrimary mr-1","children":["$undefined",[["$","path","0",{"fill":"none","d":"M0 0h24v24H0V0z","children":[]}],["$","path","1",{"d":"M12 6c1.1 0 2 .9 2 2s-.9 2-2 2-2-.9-2-2 .9-2 2-2m0 10c2.7 0 5.8 1.29 6 2H6c.23-.72 3.31-2 6-2m0-12C9.79 4 8 5.79 8 8s1.79 4 4 4 4-1.79 4-4-1.79-4-4-4zm0 10c-2.67 0-8 1.34-8 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mr-2","children":23}],["$","svg",null,{"stroke":"currentColor","fill":"currentColor","strokeWidth":"0","viewBox":"0 0 24 24","className":"text-subPrimary mr-1","children":["$undefined",[["$","path","0",{"fill":"none","d":"M0 0h24v24H0z","children":[]}],["$","path","1",{"d":"M16.5 3c-1.74 0-3.41.81-4.5 2.09C10.91 3.81 9.24 3 7.5 3 4.42 3 2 5.42 2 8.5c0 3.78 3.4 6.86 8.55 11.54L12 21.35l1.45-1.32C18.6 15.36 22 12.28 22 8.5 22 5.42 19.58 3 16.5 3zm-4.4 15.55-.1.1-.1-.1C7.14 14.24 4 11.39 4 8.5 4 6.5 5.5 5 7.5 5c1.54 0 3.04.99 3.57 2.36h1.87C13.46 5.99 14.96 5 16.5 5c2 0 3.5 1.5 3.5 3.5 0 2.89-3.14 5.74-7.9 10.05z","children":[]}]]],"style":{"color":"$undefined"},"height":16,"width":16,"xmlns":"http://www.w3.org/2000/svg"}],["$","div",null,{"className":"text-xs mr-2","children":5}]]}],["$","div",null,{"className":"text-xs rounded-lg border border-text px-4","children":"理系数学"}]]}]]}],["$","div",null,{"children":["$","div",null,{"className":"bg-caption w-20 h-20 rounded-sm 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items-center py-4","children":[["$","div",null,{"className":"flex-1 mr-3","children":[["$","div",null,{"className":"mb-1","children":"倍率は気にすべきでしょうか。"}],["$","div",null,{"className":"text-xs text-caption line-clamp-2 mb-1","children":"倍率は気にするべきではないです。はっきり言ってしまえば気にしても仕方がないからです。自分が以前から志望していた大学であれば、向き合うべきは目の前の問題です。\n以下少し冗長かもしれませんが個人的な「倍率」観です。\n\n今年の受験生はあることないこと様々な情報に振り回され、ただでさえ勉強でメンタルが弱っているところにやれ共通テストだコロナだと、本当に大変だと思います。あなたもそんな一人かもしれません。\n\n一つ言えることがあります。\nそれは今年のようなイレギュラーな年は皆が弱気になりがちだということです。弱気な人は受験期になって焦って志望校や併願校を変えます。MARCHのなかで変えることもあれば早慶からランクを下げるつもりで出願する人もいます。\n立教や青学、早慶志望者がMARCHに来たら門が狭まってしまうでしょうか？\n\n必ずしもそうではありません。\n元々自信のある人なら焦って受験校を変えたり増やしたりはしません。もちろん初めから私大を多めに受ける人は多くいますが、それは元々いる層なので例年と変わりません。つまり「微妙」な人たちが倍率を動かすわけです。経験上、自分で「微妙」と感じる人の多くは実力で合格点に届かない人たちです。合格点に届かない人がいくら増えて倍率を増やしたところで、自分が合格点以上を取ればいいことに変わりはありません。\n\nとは言え、どうしても気になってしまうのはある程度仕方がないと思います。私も第一志望の倍率が例年よりかなり高いと知った時は正直それなりにビビりました。でもビビったところでやはり勉強以外にできることはありません。自分の実力とやって来たことを信じて、不安な気持ちを切り替えて迷わず進んでください。応援しています。"}],["$","div",null,{"className":"flex mb-1","children":[["$","svg",null,{"stroke":"currentColor","fill":"currentColor","strokeWidth":"0","viewBox":"0 0 24 24","className":"text-subPrimary 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items-center py-4","children":[["$","div",null,{"className":"flex-1 mr-3","children":[["$","div",null,{"className":"mb-1","children":"文系数学で高2のうちにやっておくべきこと"}],["$","div",null,{"className":"text-xs text-caption line-clamp-2 mb-1","children":"私も青チャートを使っていました！\n基本的に、高2だろうと高3だろうと勉強法は変わりません。\n青チャートが解ければ、他の問題は怖くありません。\n\n以下、勉強の極意です。\n\n1.まずは一通り例題を解き、公式の使いどころを覚える。（基本問題）\n→数学には解法パターンがあります。こういう問題が来たら、こういう方法で解く、というのが反射的にわかる、身につく、というところまでもっていきます。\nこの時、公式がわからない、理解できないときは教科書を開いて理解するようにしましょう。\n\n2.例題の下にある問題を解く（標準問題）\n→わからなくてもすぐに答えなどみずに、10分は考えるようにしましょう。この時色々な公式や解法が頭に浮かべば、知識は身についている証拠です。\n逆に標準問題で手も足も出ないなら、教科書に立ち返りましょう。\nここまでできれば、定期テストや模試である程度の得点は見込めます。（青チャートなら国立大やマーチレベル）\n\n3.章末問題を解く（応用、発展問題）\n→数学を得点源にしたい人、難関国立大や早慶を狙う人は最終的に解けるようにしましょう。\nこのレベルだとさまざまな公式を合わせて使う、複合タイプの問題になります。\nこの問題をやるときは、「自分がどこまでわかっていて、どこからがわからないのか」をしっかり把握するようにしてください。復習するときはできないところの例題などを見返し、できるようにしましょう。\nこれが解ければ模試の大問もほぼ完投できます。\n\n\nこのように、大事なことはとにかく、\n理論を理解する\nことです。\n闇雲にやって量をこなすのではなく、丁寧に時間をかけて勉強してください。\n"}],["$","div",null,{"className":"flex mb-1","children":[["$","svg",null,{"stroke":"currentColor","fill":"currentColor","strokeWidth":"0","viewBox":"0 0 24 24","className":"text-subPrimary 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items-center py-4","children":[["$","div",null,{"className":"flex-1 mr-3","children":[["$","div",null,{"className":"mb-1","children":"この数学の問題を教えて下さい🙇"}],["$","div",null,{"className":"text-xs text-caption line-clamp-2 mb-1","children":"自然数を8で割った余りは0〜7になるのは理解できると思います。\nそこで、nを自然数とすると、\n8で割った余りが\n0→8n\n1→8n 1\n2→8n 2\n3→8n 3\n4→8n 4\n5→8n 5\n6→8n 6\n7→8n 7\nとすることですべての自然数を表すことができます。問題で聞いているのは平方数ということなので、それぞれを2乗すると、\n\n0→64n^2=8×8n^2\n1→64n^2 16n 1=8(8n^2 2n) 1\n2→64n^2 32n 4=8(8n^2 4n) 4\n3→64n^2 48n 9=8(8n^2 6n 1) 1\n4→64n^2 64n 16=8(8n^2 8n 2)\n5→64n^2 80n 25=8(8n^2 10n 3) 1\n6→64n^2 96n 36=8(8n^2 12n 4) 4\n7→64n^2 112n 49=8(8n^2 14n 6) 1\n\nとなります。\nすべて(8n ○)^2という式になる以上、n^2とnの係数は8の倍数になるので、自然数部分である余りの2乗部分を8で割った時の余りが平方数の余りになります。\n\n長くなってすみません。わからなかったらまた質問してください。"}],["$","div",null,{"className":"flex mb-1","children":[["$","svg",null,{"stroke":"currentColor","fill":"currentColor","strokeWidth":"0","viewBox":"0 0 24 24","className":"text-subPrimary 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items-center py-4","children":[["$","div",null,{"className":"flex-1 mr-3","children":[["$","div",null,{"className":"mb-1","children":"高二夏で数3が終わる。それからは。"}],["$","div",null,{"className":"text-xs text-caption line-clamp-2 mb-1","children":"世界一わかりやすい阪大理系数学など、旧帝大レベルの過去問に移るのは高三春からでも十分だと思いますよ。\n\nそれよりもむしろFGの二週目をしてください。一周目に解けなかった問題の中で、答えを見たその時はわかったつもりでも、時間をおくと解けなくなっているものが大半でしょう。それはつまり「答えを見てわかったつもり」になっているだけで、結局その問題を解けるようにはなっていないということです。そんな状態(一周目終了しただけでFGの中に解けない問題が残っている)のまま、FGよりも難しい問題が揃った旧帝大レベルの過去問に移ってもきっと解けないでしょうし、背伸びしてることになってずっと頭に定着しないでしょう。\n\nですので、一通り高2の夏に終わるとはいえ、すぐに難しい応用のいる過去問に移るのではなく、FGの二週目などで基礎＋標準の力を確実に蓄えた方が、結局過去問レベルが解けるようになるまでが早いと思います。急がば回れです。無理に早いうちから過去問に手を出しても、その前に必要な土台がないと、「早く始めたはずなのにいつまで経っても過去問解けない」という状態になってしまうと思うので、上のような提案をさせていただきました。\n\nもし「いや高2の夏でFGも完璧に解けるようになってる前提です」ということでのこの質問でしたらまたその旨を教えてください。その時はその時でまた回答させていただければなと思います。\n\n参考になれば幸いです。"}],["$","div",null,{"className":"flex 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