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1a:T11e6,私立の科目と基礎固めについて話します。

英語、数学、物理の順に基礎固めについて話しました。
文系の方は英語、数学でも良いので読んでみてください！

可能な限り丁寧に書きました。
そのため、長文になってしまったので時間のある時に少しずつ読んでみてください！

では、以下回答です。

まず、私立の科目について
明治大学ならば英、数、物理
慶應大学ならば英、数、物理、化学
のように受験校により科目が異なる時ですが

まずは英、数、物理に力を入れて頑張りましょう！
頑張った結果、成績が伸びて上を目指せる段階に来たら追加の科目に取り組んでみる方が良いと思います。

そうする理由ですが、偏差値が志望校に足りていない時から
多くの科目に手を出すと、本来受かるところも危なくなってくるからです。

次に基礎固めについて
英語、数学、物理の順に話しますね。

まずは英語の基礎固めについて
英語が苦手だと感じている場合
まずやるべきことは『単語』、『文法』です。

単語はいきなりスペルまで覚える必要はないです。
英語→日本語がすぐに出てくる状態にしましょう！

オススメの覚え方ですが、大雑把で良いので毎日多くの単語を見て覚えるようにしましょう。
例えば、毎日100語をざっとみることを1週間繰り返すようなイメージです。
オススメしない覚え方は毎日10語ずつ確実に覚えてをそれを1週間繰り返す方法です。
この方法だと、長期記憶になりにくく、1ヶ月経った時に見返してみても覚えていないことがよくあります。

文法は
アップグレードを解く
↓
解説を読む
↓
それでもわからなければ、英語の文法参考書を読む

を繰り返してください。

この繰り返しの際に意識すべきことは
・なぜその選択肢が正しいか
・なぜ他の選択肢は間違えているのか
・間違いの選択肢をどう訂正すれば正解になるのか
の3点です。

丸暗記するのではなく、考えながら解いてください。

『単語』、『文法』は集中して短期的に終わらしましょう。
例えば、完成度は8割で良いので1〜2ヶ月で終わらしてしまいましょう。

『単語』、『文法』がほぼ完成したら次は『長文』です。
英語長文レベル別問題集をガンガン解いていきましょう。
読めば読むほど英語は読むスピードが早くなります。
問題演習をできるだけ多くこなしましょう。

次に数学の基礎固めについて
数学が苦手だと感じるならば
『青チャートの基本例題』を完璧にしましょう！

勉強方法ですが

問題文を読む
↓
問題を解く
↓
解けたなら目印なしで次の問題へ
解けないなら目印をつけ、解答を読む
↓
解けない問題の解答を理解する
理解できないならば恥ずかしがらずに質問する
↓
解けなかった問題を解答を見ずに
再度解答を自力で再現する
↓
次の問題へ行く
↓
1周目が終わったら目印をつけた問題について
上のサイクルを繰り返す！

この方法で基本例題について
問題文を読むだけで解き方が浮かぶようになったら
重要例題を同じサイクルで取り組みましょう！

最後に物理の基礎固めについてですが
挙げてもらった参考書で私はリードαしかやったことがないので、リードαについて話します。

物理が苦手だと感じるならば
リードαのA問題を重点的に解きましょう！
解き方は数学の時と同じサイクルです！

ただし、リードαは考え方があまり載っていないので
参考書として『物理のエッセンス』を使うことをオススメします。
物理のエッセンスでは考え方を教えてくれるので
わからない時にエッセンスを読みましょう！

リードαが肌に合わないと感じる場合は
基礎固めなら『良問のの風』がオススメです。

基礎固めが終わったなら
リードαのB問題又は『名問の森』がオススメです！

参考になれば幸いです。
やり方を忘れた時は見返してください！
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items-center py-4","children":[["$","div",null,{"className":"flex-1 mr-3","children":[["$","div",null,{"className":"mb-1","children":"化学基礎からが全くわからない"}],["$","div",null,{"className":"text-xs text-caption line-clamp-2 mb-1","children":"こんにちは。\n\nmolの計算がよくわからない為に、その後の計算(中和やph、電池の問題など)も解けないという推測のもとに回答しますね。そうではなく、単元ごとに意味のわからない部分があると言うことであれば、個別にご質問なさると良いと思います。\n\nまず、モルを難しく考えすぎてはいないですか？\n6.02×10^23個＝1 mol にしよう！と決めただけです。12個で1ダースと同じですね。\nそして、同じ原子を6.02×10^23個集めると、[その原子の原子量]g になります。\n同じ原子を6.02×10^23個集めたときの重さ、といちいち書くのは面倒なので、モル質量と呼びましょう。単位は1molで○gを分数にして g/mol ですね。\n\n炭素の原子量が12とします。いま、炭素が24 gあります。炭素の原子は何molありますか？ 簡単ですね、2 molです。個数でいえば2×6.02×10^23個ですね！\n(分子の時は少し気をつけて下さい。水素の原子量を1とします。水素ガスが4 gあります。このとき水素原子は4 mol存在しますが、水素ガス(分子)は2 molです。)\n\nこのくらいは分かってる！とお思いかも知れませんが、mol計算が苦手な方は単位変換が苦手な印象です。計算の時、単位同士も掛け算、割り算していますか？ 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