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1a:Tc62,演習の際、用意している教材は問題集のみでしょうか？
もしそうなら、必ず教科書や図録を見ながら取り組みましょう。
教科書や図録を使わずに学習をする人は、丸暗記に陥りがちです。
解説が的を絞ったことしか書いていないからです。

以下詳細な回答です。

＊丸暗記では勝てない
＊暗記の心得3カ条
＊人に教えて理解を深める
＊まとめ

－－－－－－－－－－－－

【丸暗記では勝てない】

京大の化学は丸暗記で挑む人を叩きのめす構造になっています。
基本的な事柄に対しても「なぜか？」を理解して説明できる力が必要です。

大問1…酸化還元や物質の構造に関する問題
大問2…溶液や気体の化学平衡に関する問題
大問3…有機化学に関する問題
大問4…高分子化合物に関する問題

が例年のパターンです。

計算問題や有機化学のパズルは一見論証と関わりなさそうですが、立式導出過程を問題文から理解するということが必要になってくるので、丸暗記が習慣になっている人は苦戦を強いられます。

－－－－－－－－－－－

【暗記の心得3カ条】

駿台化学科の石川正明先生は、
「論理性」
「意味性」
「感動性」
を大切に理解暗記していきましょう、と指導されています。

「論理性」
何故そうなるのかを説明できると、自信をもって理解暗記できます。
(例)
過マンガン酸イオンが、酸性溶液中で酸化剤としてはたらく半反応式
MnO4(-)   8•H( )   5•e(-) → Mn(2 )   4•H2O
これは何故このような式になるのか、自分なりにわかりやすく説明できるようになっている人の方が自信を持って暗記できます。
教科書と化学図録を用いて詳しく調べながら学習を進めると良いです。

「意味性」
それを理解すると何が得られるのかを知ると、理解暗記する意欲が増します。
例)
ステアリン酸×3とグリセリンから成る油脂は分子量890で、これを覚えておけば高分子化合物の分子量絡みの計算が速くなる。

「感動性」
面白い、すごい、ひどい、と心動くことで暗記しやすくなります。
例)
「水兵リーベ僕の船…」に代表されるような語呂合わせ。


－－－－－－－－－－－－
【人に教えて理解を深める】

重要問題集で自分が出来た問題でも、誰かにわかりやすく解説することは出来ますか？
「論理性」「意味性」「感動性」を意識して、人に教えてみてください。
これは僕が実践してきた化学勉強法です。
友達同士で質問し合いっこしましょう。
特に模試の復習でこれをやると効果的です。

－－－－－－－－－－－－

【まとめ】

問題集 教科書 図録で演習。
人と教えあいっこで理解を深める。
京大相手に丸暗記では太刀打ちできない。1c:T17da,回答させていただきます。ただ、私は受験生時代にサイトで紹介されていた暗記量を減らす方法を使っていたため、その方法を解説するサイトのリンクを貼らせていただくという形にさせていただきます。ご了承ください。

・酸化還元、電池の暗記
　酸化還元については、酸化剤と還元剤にはどんなものがあって、反応でそれらが何になるかは丸暗記する必要があります。(例:濃硫酸→二酸化硫黄)ただ、半反応式を全て覚える必要はなく、元の物質が何になるかさえ知っていれば半反応式を組み立てることができます。私は受験生時代、次のサイトを見てやり方を理解しました。
(https://kimika.net/r5hanhannousiki.html　化学のグルメ-半反応式・酸化還元反応式（作り方・覚え方・問題演習など）)
　また、電池についても上のサイトで全て事足ります。既に授業動画で予習されているということなので、事前知識込みで見ていただくと非常に分かりやすいです。

・構造決定の学習法
構造決定はやればやるほど点が伸びますし、できるようになるとパズルみたいで楽しいのでとにかく量をこなしてください。ただし、構造式は問題の指示に従って書くように意識してください。これを習慣づけると理不尽な減点を防げます。
　既に新演習に手を出されているということで、ある程度骨のある練習問題として東北大学の有機をおすすめします。東北大学の第3問は伝統的に構造決定が出題されますが、非常に問題の質が良いです。難易度で見てもちょうど良く大問の中で勾配があるため、基礎知識の定着と思考力の養成にうってつけです。

・無機の暗記
　イオン化傾向列を使うと覚えやすい部分があります。例えば、イオン化列で横並びの亜鉛鉄ニッケルは濃硝酸と反応して不動態を形成するというように、イオン化列で近い位置にあるものは近い性質を持ちます。また、色の暗記では既にされているように資料集を読んで写真で覚えるのがよいです。

・理論の計算
　溶解度については、出した質量が溶液のものなのか、溶質のものなのか、溶媒のものなのかを考えて解いてください。
　例えば、食塩の溶解度が20g/水100gであれば、食塩:水の質量比は1:5ですが、食塩:溶液なら1:6になります。これを混同すると正解できなくなるので気をつけましょう。
　気液平衡については、気体の量を体積でなく物質量で捉えると混乱しにくいです。ヘンリーの法則では標準状態基準の体積を考えることがありますが、分かりにくいので全て物質量で統一してしまいましょう。(物質量に直すとき、分数のままにしておくと多少計算が楽)

・合成高分子の暗記
　そもそも京大には合成高分子は大問としてはほとんど出題歴がありません。しかし、理論の方でイオン交換膜が出題されたりはするので、そこは暗記必須です。ただ、結局共通テストには合成高分子は出題されるので、その対策として繊維やゴムについて覚える必要はあります。
　合成高分子はそれまでの化学よりも更に生活に身近になります。身の回りのものと結びつけて覚えてみましょう。例えば、アラミド繊維は強度が非常に強いため防弾チョッキに使われているといった感じで、物質の種類、性質、使用例を一気に暗記してしまいましょう。
　また、反応機構に触れると、ほぼ例外のないパターンがいくつかあるだけなので無機に比べて楽に覚えられるはずです。

・各分野の学習比、京大化学の傾向
　まず、京大化学は大問4つ(2科目で180分、1課目なら90分)で、大問1は理論と無機の複合か純粋な理論、大問2は純粋な理論、大問3は有機、大問4は高分子(ほとんど天然高分子)が出題されています。これは10年間変わっていません。
　全体を通して、知識を前提に思考力を問われています。記述問題だけでなく、グラフを選択したり、範囲外の内容(マルコフニコフ則やラウールの法則など)を誘導付きで出題してきます。また、数値計算の煩雑さもありますが、物理の問題のように文字のままで計算する問題が多くあり、慣れが必要です。
　京大化学では、まず有機と高分子で得点を稼ぐ必要があります。比較的難易度が低く、そうでなくても誘導が丁寧なことが多いです。有機は構造決定と立体化学、高分子は糖ペプチドアミノ酸が多く出題されます。
　理論は、結晶構造、電離平衡、気体が多く出題され、中でも結晶は出題頻度が高いです。
　無機は全く出題されない年もありますが直近は3年連続で出題されています。対策を怠ることはできません。
　以上を踏まえると、有機>理論>無機の順で重視したほうがいいと考えられます。比率に関してはなんとも言えないですが、高2から化学を勉強されているということで、受験前には全分野完成する(化学で7〜8割が目指せる)と思われます。なので比率というよりは不安な分野を都度穴埋めするぐらいでよいでしょう。

　最後になりますが、暗記分野は演習をこなしていくうちにいずれ覚えていくと思ってください。演習の比重を大きくしていって、最終的に過去問にまで到達できるようにしましょう。健闘を祈ります。2:["$","main",null,{"className":"px-4 pt-4 pb-4","children":["$","div",null,{"className":"max-w-3xl mx-auto w-full","children":[["$","div",null,{"className":"mb-8","children":["$","$L7",null,{"href":"https://unilink-app.onelink.me/isbO/h6xeh63x?advice=FcNz8DtHt9cGVLkMfoYA","target":"_blank","children":["$","$L8",null,{"src":"/images/web_to_app_banner.jpg","width":3660,"height":1500,"sizes":"100vw","style":{"width":"100%","height":"auto"},"alt":"UniLink WebToAppバナー画像","className":"mb-4 rounded"}]}]}],["$","h1",null,{"className":"text-xl font-semibold mb-2","children":"式のたて方がよく分かりません"}],["$","div",null,{"className":"flex justify-between mb-4","children":[["$","div",null,{"className":"text-left text-xs text-caption","children":["クリップ(",1,") コメント(",0,")"]}],["$","div",null,{"className":"text-right text-xs text-caption","children":"8/7 0:21"}]]}],["$","div",null,{"className":"coach-mark 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1.2となり、xが求められます。また、xが与えられた酸化銅以下なので、過不足なく反応が進行したとわかります。（酸化銅を未知数とするとき、炭素は全て消費されたと仮定することになります。この問題ではその仮定は正しいですが、もし炭素を未知数とした場合、与えられた量以上の炭素が必要な計算になり、不適となります。）"}],["$","div",null,{"className":"flex mb-1","children":[["$","svg",null,{"stroke":"currentColor","fill":"currentColor","strokeWidth":"0","viewBox":"0 0 24 24","className":"text-subPrimary mr-1","children":["$undefined",[["$","path","0",{"fill":"none","d":"M0 0h24v24H0V0z","children":[]}],["$","path","1",{"d":"M12 6c1.1 0 2 .9 2 2s-.9 2-2 2-2-.9-2-2 .9-2 2-2m0 10c2.7 0 5.8 1.29 6 2H6c.23-.72 3.31-2 6-2m0-12C9.79 4 8 5.79 8 8s1.79 4 4 4 4-1.79 4-4-1.79-4-4-4zm0 10c-2.67 0-8 1.34-8 4v2h16v-2c0-2.66-5.33-4-8-4z","children":[]}]]],"style":{"color":"$undefined"},"height":16,"width":16,"xmlns":"http://www.w3.org/2000/svg"}],["$","div",null,{"className":"text-xs","children":["京都大学理学部"," ","有為の罪"]}]]}],["$","div",null,{"className":"flex 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items-center py-4","children":[["$","div",null,{"className":"flex-1 mr-3","children":[["$","div",null,{"className":"mb-1","children":"ほんとに化学がヤバい😭"}],["$","div",null,{"className":"text-xs text-caption line-clamp-2 mb-1","children":"おはようございます。\n\n文系の方ということで、化学基礎の内容について以下記述します。もし、化学基礎ではなく化学の方でしたらすみません。\n\n参考書について。私がオススメするものは理系向け(化学基礎と化学の両方載っているもの)になるのでご了承ください。『化学の新研究』『解法の焦点　理論化学編』\nただ、後者の方であれば文系の方で高得点を狙っている方にもオススメできると思います。\n\n学習法について。\n物質の構造(molの前まで)：この単元は知識問題です。覚えるのが中心となります。\n\nmol：molは単位です。みかんなどを一箱もらったという時、みかんなどを何個もらったというわけではないですが、たくさんもらったと容易に想像できることでしょう。それと同じように、原子はとても小さいので、炭素何粒子(何原子)というよりも炭素何molというわけです。\n\n化学法則：覚えてください。\n\n酸-塩基：中和の原理とどの溶液が強酸、弱酸、弱塩基、強塩基かは覚えてください。化学反応式は作れるようにしてください(覚えなくて結構です)。反応式を作る際は、生成される水に注目すると良いでしょう。中和反応する物質(例えば塩酸と水酸化ナトリウム)と与えられた場合に化学反応式が書けるようにします。\n\n酸化還元：酸化還元の原理とどの物質が酸化剤、還元剤かは覚えてください。あと、酸化剤や還元剤として働く物質の半反応式は覚えてください。イオン反応式や化学反応式は半反応式の組み合わせで作ることができます。\n\nこんな回答でよろしかったでしょうか。少しでも参考になれば幸いです。"}],["$","div",null,{"className":"flex 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items-center py-4","children":[["$","div",null,{"className":"flex-1 mr-3","children":[["$","div",null,{"className":"mb-1","children":"化学をやるか他教科のセンター対策をするか"}],["$","div",null,{"className":"text-xs text-caption line-clamp-2 mb-1","children":"私も北大総合理系で入学しました。\n\n模試の結果を見ると、確かに倫政は伸ばす必要があるかなと思います(配点も大きいはず？)\n倫政は知識を入れればちゃんと点数につながりますし、最後の最後まで点数を伸ばせる教科です。まだ時間はあるのでまた弱い分野を重点的にべんきょうしてみてはどうでしょうか。\n\n数ⅡBは時間が足りなくなる場合がほとんどだと思いますので、スピードをつけるために普段から時間をはかりながら勉強する機会を設けるといいかなと思います。\n\nさて、化学ですが、二次試験でも必要になる教科ですよね。やはり苦手意識を克服してもらいたいと思います。\n無機化学に苦手意識を持っているようですが、無機化学も最後まで点数の伸ばせる分野です。ただ、暗記がかなり必要な分野になるので今から努力する必要はあります。\n\n覚えるべきは\n沈殿の色、気体の性質・発生法、アルカリ金属・アルカリ土類金属・ハロゲンの性質、酸素・硫黄・窒素・リン・炭素などの性質、鉄・アルミ・銅などの性質と精製\n…たくさんありますね。\nしかし、特徴的なものだけ覚えると実は覚えるべきものは想像より少なくなるはずです。\n例えば、沈殿はほとんどが白色ですよね。だから色のついたものだけ覚える、など工夫しながらおぼえていきます。\n\n私は全て語呂合わせで覚えていました。(バ(Ba)カ(Ca)な(Pb)硫酸白沈(白色沈殿)など)\nイメージがつきにくいときは化学図表などを使って視覚的に覚えるのも効果的です。\n無機化学は狙われるところがだいたい決まっているので、模試で出てきた選択肢などは全て確認しておくことをオススメします！\n\n頑張ってください！！\n"}],["$","div",null,{"className":"flex 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items-center py-4","children":[["$","div",null,{"className":"flex-1 mr-3","children":[["$","div",null,{"className":"mb-1","children":"化学反応式やその計算を得意にするには"}],["$","div",null,{"className":"text-xs text-caption line-clamp-2 mb-1","children":"こんにちは。\n\n化学反応式の係数を合わせるのが苦手、ということでしょうか？\n具体的に書かれていないのであまりわかりませんが、そういうことだと思って回答させていただきます。\n\n化学反応式の係数合わせに関しては、左辺と右辺でそれぞれの元素種の数が等しくなるようにすればいいです。\n文字を使って連立方程式を解くだけで簡単に導くことができます。\n\nまた、物質量や濃度の計算に関しては「単位」を意識して考えてみましょう。\n例えば、密度[g/m^3]に体積[m^3]をかければ質量[g]が出てきます。\nこれは覚えることではなく、単位に注目すれば一目でわかります。\nその考え方が身につけば、そういった計算は簡単にできるようになると思いますよ。"}],["$","div",null,{"className":"flex mb-1","children":[["$","svg",null,{"stroke":"currentColor","fill":"currentColor","strokeWidth":"0","viewBox":"0 0 24 24","className":"text-subPrimary mr-1","children":["$undefined",[["$","path","0",{"fill":"none","d":"M0 0h24v24H0V0z","children":[]}],["$","path","1",{"d":"M12 6c1.1 0 2 .9 2 2s-.9 2-2 2-2-.9-2-2 .9-2 2-2m0 10c2.7 0 5.8 1.29 6 2H6c.23-.72 3.31-2 6-2m0-12C9.79 4 8 5.79 8 8s1.79 4 4 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items-center py-4","children":[["$","div",null,{"className":"flex-1 mr-3","children":[["$","div",null,{"className":"mb-1","children":"中和滴定に電離度がなぜ関係ないのか"}],["$","div",null,{"className":"text-xs text-caption line-clamp-2 mb-1","children":"それは確かに私も不思議に思っていました。\n\n私は化学の専門家ではないので、あくまで一つの考え方として見て下さい。詳しいことは、化学の先生などにうかがったほうがいいと思います。\n\n後々習うとは思いますが、物質は電離するとき、電離平衡というバランスをとります。たとえばアンモニアでは、\nNH3 H2O ⇌NH4  OH-\nとなります。\n矢印が両方向にあることからも分かると思いますが、反応は右にも左にも進みます。NH3とNH4 ,OH-の濃度の比が一定になるように反応が起こります。\n\n塩酸を加えると、H とOH-が反応して、H2Oが生成します。すると、OH-の濃度は減少するわけです。そうなると先ほどの電離式の左右の比が崩れてしまうため、それを補うように反応が右に進みます。すると、アンモニアがさらに電離します。\nこれが続いていくと、アンモニアは続々と電離していき、最終的には全て電離することになります。\n\nこう考えると、少し納得がいく気がします。\n\nちなみに、電離度というのは、先ほどの電離式のそれぞれの濃度の比から導き出された値になります。高3になると、その算出の仕方も学ぶと思いますので、楽しみにしておいて下さい。"}],["$","div",null,{"className":"flex mb-1","children":[["$","svg",null,{"stroke":"currentColor","fill":"currentColor","strokeWidth":"0","viewBox":"0 0 24 24","className":"text-subPrimary 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items-center py-4","children":[["$","div",null,{"className":"flex-1 mr-3","children":[["$","div",null,{"className":"mb-1","children":"化学基礎の問題が分かりません！解き方を教えてください。"}],["$","div",null,{"className":"text-xs text-caption line-clamp-2 mb-1","children":"H₂SO₄ + 2KOH→ K₂SO₄ + 2H₂O\n\r\n希硫酸の水素イオン[H+]のmol数と水酸化カリウムの水酸化物イオン[OH-]のmol数が同じになった時に中和されるよ！\n\nmol数ってどうやって出すか覚えてるかな？\n\n\n＊希硫酸について\n\n分子量っていうのはもともと1molあたりの重さだから、希硫酸19.6gのmol数は19.6÷98=0.20molだね！\n\nでも、これ10%の希硫酸なんだよね。だから19.6gのうち1.96gが希硫酸であとは水だね。\n\nだから正しくは1.96÷98=0.020molだね！\n\n\n\n＊水酸化カリウムについて\n\n希硫酸の[H+]0.020molと同じ量の水酸化カリウムの[OH-]を用意しよう！\n\n2KOHだから2倍、つまり0.040molの[OH-]を用意するにはどうすれば良いかな？\n\n1Lつまり1000mlで1molだから、何mlで0.040molになるかは自分で考えてみよう！"}],["$","div",null,{"className":"flex mb-1","children":[["$","svg",null,{"stroke":"currentColor","fill":"currentColor","strokeWidth":"0","viewBox":"0 0 24 24","className":"text-subPrimary mr-1","children":["$undefined",[["$","path","0",{"fill":"none","d":"M0 0h24v24H0V0z","children":[]}],["$","path","1",{"d":"M12 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