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・「nを2以上の整数とする。金貨と銀貨を含むn枚の硬貨を同時に投げ、裏が出た金貨は取り去り、取り去った金貨と同じ枚数の銀貨を加えるという試行の繰り返しを考える。初めはn枚すべてが金貨であり、n枚すべてが銀貨になった後も試行を繰り返す。k回目の試行の直後に、n枚の硬貨の中に金貨がj枚だけ残る確率をPk(j)(0≦j≦n)で表す。」(東北大2019文系) のように。あなたが挙げて下さった例でもそうですね。  ご存知のように、数学で文字が使われるのはそこに入る値が不特定であるときなので、逆にいえば、自分で具体的な値を代入して実験してみれば良いわけです。k-連続和でいえば、m=1、k=2とすると、3=1+2という等式になり、3は2-連続和であることになります(相談文のk+1はおそらくkー1の間違いですね。でなければ、nはk+2個の連続する自然数の和になってしまうので)。ちゃんと、n(3)がk(2)個の連続する自然数(1→2)の和であるという定義に則ってますね。2019年文系の確率も、例えばk=1を代入してみると、P1(j)は「n枚の金貨を同時に投げ、そのうちj枚が表で他が裏になる確率」のことを言っているのだとわかります(ちなみにこれは小問⑴)。反復試行の確率を考えればすぐ解けますね。すると、次はk=2、その次はk=3、と実験数をどんどん増やしていけば、Pk(j)の内容もいずれわかるはずです。試行の手順上、残るj枚は必ず全ての試行において表でなければならず、他方それ以外の金貨はすべて、k回のうちのどこかで裏が出ればいい(全て表で残る場合の余事象)わけですから、「n枚の金貨のうち、k回の試行の直後に残るべきj枚はk回とも全て表が出て、それ以外のn−j枚はk回の試行で少なくとも一回裏が出る確率」とわかります。ここまで日本語として簡略化できれば、Pk(j)(特に、k≧2)の値もそこまで苦戦せずに出せそうですね(ちなみにこれは小問⑵)。  このように、なるべく簡単な値から代入して実験を繰り返すことで、独自の定義が何を言っているのかは帰納的に理解できることが多いです。文字が多かったり、分かりにくい表現だったりして、複雑で難しく感じる定義が出てきたら、まずは実験してみることを心がけると良いと思います。文系の問題ですが、もしまだ解いてない場合はネタバレになってしまい申し訳ございません。1b:T10ea,受験数学にひらめきは全く必要ありません。 実際、数学者と数学の得意な高校生が、受験数学で勝負すると高校生が圧勝します(実話です)。一体何が、高校生を勝たせるのだと思いますか? 受験数学には、確かに、「ひらめきのようなもの」を要求する場面があります。特に整数問題などで顕著ですが。しかし、ほとんどの問題は、今まで身につけてきた解法で対応できてしまうんですね。 例えばですが、多変数関数 f(x,y)の最大値、最小値を求めよという問題が出たとします。(f(x,y)の中身は、例えば、x^2 3xy y^2などですね。ここではそれは本質ではないのでスルーします。)その時、方針が何通りかあるんですが、それを列挙できますか? あるいは、図形問題に対して、どのようなアプローチを考えるべきか説明できますか? (答えはどちらも回答の最後に載せますね) もし1つも分からない場合や、何個かしか挙げられない時は、少し補充的な勉強をする必要があります。 問題ごとに、それを解くための最適な方針がありますね。それをメモ程度で十分なので、どんどんまとめていってください。すると、多種多様に見える問題も、スタートは必ず同じことをしていたり、何個かのパターンの方針しか使っていなかったりします。本当はこういうことを分かっていくのは、問題演習を通してだんだん培っていくべきものなんでしょうが、99%の人は出来ないでしょう。僕も全然出来ませんでしたし。 なんにせよ、こういう「解法の整理」をしていくと、全く手が付かない問題はほとんどなくなってきます。途中までは行けるようになるんですね。そして、「ひらめき」は大抵こういう場面で使うものですね。例えば最後の最後に有名不等式を使ったりなどでしょうか。しかし、これすらも、方針としてカテゴライズすることが可能です。いわゆる純粋なひらめきは、受験数学においてはあり得ないといって良いでしょう。大抵、「閃かない」時は、解法が浮かばない時です。かなり具体的な問題に帰着できましたね。 僕は、ノートの見開き1ページに、この問題が来たら、この方針がよく登場する!というフローチャートのようなものを作っていましたね。頭の中が整理されていく感じがして楽しいですよ。 ちなみに、基礎ができていないということは、多少あるにせよ直接的な原因ではなく、いくら固めたところで、成果が微々たるものしか出ないので、気をつけましょう。青チャート、フォーカスゴールド、どちらも持っている時点でフル装備なので、多少の復習はもちろん必要といえども、頑張る必要はありません。 さて、先ほどの問題、わからずじまいは良くないですから簡単に 多変数関数の最大最小問題: ・等式があればxかyに代入してそれを消去する(いわゆる文字消去) ・xかyのどちらかを定数とみなし、ただの1変数関数とみなして考える(いわゆる文字固定) ・有名不等式の利用(相加相乗平均の関係、コーシーシュワルツの不等式、三角不等式など) ・逆像法 ・線型計画法 ・グラフを書いて考える Etc. 図形問題のアプローチ ・まずは初等幾何で解けないか考える。 ・次に、位置ベクトルを導入することで、内積などを利用して解けないか考える。 ・もし対称性の高い図形だったら、座標平面を設定するのも考える。 僕がこの解法整理についての対策を編み出し、始めたのは12月の半ばです。今なら相当早いタイミングから対策できますから、ぜひ過去問での得点をぐんぐん挙げて、自信をつけていってほしいと思います。 では、有意義な秋をお過ごしください!2:["$","main",null,{"className":"px-4 pt-4 pb-4","children":["$","div",null,{"className":"max-w-3xl mx-auto w-full","children":[["$","div",null,{"className":"mb-8","children":["$","$L7",null,{"href":"https://unilink-app.onelink.me/isbO/h6xeh63x?advice=72kZ0w7VpUKkp6CEnOvy","target":"_blank","children":["$","$L8",null,{"src":"/images/web_to_app_banner.jpg","width":3660,"height":1500,"sizes":"100vw","style":{"width":"100%","height":"auto"},"alt":"UniLink WebToAppバナー画像","className":"mb-4 rounded"}]}]}],["$","h1",null,{"className":"text-xl font-semibold mb-2","children":"数Ⅲ 微分"}],["$","div",null,{"className":"flex justify-between mb-4","children":[["$","div",null,{"className":"text-left text-xs text-caption","children":["クリップ(",0,") コメント(",0,")"]}],["$","div",null,{"className":"text-right text-xs text-caption","children":"3/27 16:23"}]]}],["$","div",null,{"className":"coach-mark mb-4","children":"UniLink利用者の80%以上は、難関大学を志望する受験生です。これまでのデータから、偏差値の高いユーザーほど毎日UniLinkアプリを起動することが分かっています。"}],["$","div",null,{"className":"mb-4","children":["$","$L13",null,{"clientImageUrl":"https://firebasestorage.googleapis.com/v0/b/unilink-48e75.appspot.com/o/images%2Fs_K4jBf98MLxQq5ARslyCq4ist4xA2.jpg?alt=media&token=4d2f76e8-f701-4b6d-a02b-6ece30ccf67c","clientUserName":"里桜","infoString":"高3 東京都 東京医科歯科大学歯学部(59)志望","adviceId":"72kZ0w7VpUKkp6CEnOvy"}]}],["$","div",null,{"className":"mb-8","children":[["$","div",null,{"className":"leading-loose whitespace-pre-wrap","children":[["$","div","consultation-part-0",{"children":[null,"y=3x-2sinxの関数の増減を調べよ\nという問題が分からないので教えて欲しいです。"]}]]}],["$","div",null,{"className":"pt-4","children":["$","$L14",null,{}]}],null]}],["$","h1",null,{"className":"text-xl font-semibold mb-2","children":"回答"}],["$","div",null,{"className":"mb-4","children":["$","$L15",null,{"adviserImageUrl":"https://firebasestorage.googleapis.com/v0/b/unilink-48e75.appspot.com/o/images%2Fs_twi3NOvi2XNuQQ9sk07nPUPysYF2.jpg?alt=media&token=7d03a1e6-6009-417a-8aa7-fc0cf8326f31","adviserName":"Titania","adviserDepartment":"東京工業大学物質理工学院","adviceId":"72kZ0w7VpUKkp6CEnOvy"}]}],["$","div",null,{"className":"coach-mark mb-4","children":"すべての回答者は、学生証などを使用してUniLinkによって審査された東大・京大・慶應・早稲田・一橋・東工大・旧帝大のいずれかに所属する現役難関大生です。加えて、実際の回答をUniLinkが確認して一定の水準をクリアした合格者だけが登録できる仕組みとなっています。"}],["$","div",null,{"className":"mb-8","children":[["$","div",null,{"className":"leading-loose whitespace-pre-wrap mb-4","children":[["$","div","advice-part-0",{"children":[null,"f(x)=3x-2sinx と置く.\nf'(x)=3-2cosx>0(∵|cosx|≦1)\nよって,f(x)は単調増加.\n以上のようになります.\n\n一般に,f(x)=ax-bsinx の増減は,\nf'(x)=a-bcosx\nとなるので,a>b のときf(x)は極値を持たず単調増加し,a-(1/2)<(an)/2^n>=2\n\nとなります。\n\n(an)/2^nをcnとすると、(cn+1)=(1/2)(cn)+2\n\nこれを変形して、(cn+1)-4=(1/2)<(cn)-4>\n\nつまり(cn)-4=(-7/2)・(1/2)^n-1=(-7)・(1/2)^n\n\nよってcn=4-7・(1/2)^n\n\nこの両辺に2^nをかけてan=4・2^n-7 (n≧1)\n\nとなります。\n分かりにくくてすいません!\n\n"}],["$","div",null,{"className":"flex mb-1","children":[["$","svg",null,{"stroke":"currentColor","fill":"currentColor","strokeWidth":"0","viewBox":"0 0 24 24","className":"text-subPrimary mr-1","children":["$undefined",[["$","path","0",{"fill":"none","d":"M0 0h24v24H0V0z","children":[]}],["$","path","1",{"d":"M12 6c1.1 0 2 .9 2 2s-.9 2-2 2-2-.9-2-2 .9-2 2-2m0 10c2.7 0 5.8 1.29 6 2H6c.23-.72 3.31-2 6-2m0-12C9.79 4 8 5.79 8 8s1.79 4 4 4 4-1.79 4-4-1.79-4-4-4zm0 10c-2.67 0-8 1.34-8 4v2h16v-2c0-2.66-5.33-4-8-4z","children":[]}]]],"style":{"color":"$undefined"},"height":16,"width":16,"xmlns":"http://www.w3.org/2000/svg"}],["$","div",null,{"className":"text-xs","children":["名古屋大学医学部"," ","メイメイ"]}]]}],["$","div",null,{"className":"flex 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mb-1","children":"こんにちは!\nこうしんと申します!\n\n指数関数…というと範囲が難しいので、\n最大最小問題の解き方→指数関数の処理方法\nという形で話を進めていきますね!\n\nまず最大最小問題ですが、これは方程式・関数を扱う分野で出てきます。\nこの分野の攻略方法は以下の通りです\n・文字を見分ける\n・解答法を知る\n(方程式として解く、関数として解く、不等式として解く)\n\n一つずつ説明していきますね。\n\n・文字を見分ける\n文字は、定数と変数があります。物理ではこれがはっきり決まってますが、数学では全く別の性質で、定数でさえ値を動かすことがあります。\nなので\n定数…中心にはない文字\n変数…中心に扱っていく文字(〜と解く、微分する、といった文字の中心となります)\nこれをまず見分ける必要があります。\n見分け方は、定数が「分布(どういう値をとるのか?)を知りたい文字」であるという性質がある点です。他には、定数の方が次元が高い、扱いづらいという特徴がありますね。\nこうして、変数を絞り込んでおきます。\n変数は1個にしてください。\n\n・解答法を知る\n解答法は3つに分かれます。\n\n方程式としてみる\n→解の配置(0より大小となる点を探す)・座標・対称式\n関数としてみる\n→微分してグラフを描く\n不等式としてみる\n→実数の2乗は0以上を使う、コーシーシュワルツ、相加相乗平均\n(不等式は難しいので、関数としてみた方が早いです)\n\nこれらの解答法を調べてみてください!完璧にすると対応ができます!\n\n\n最大値というのは、\n・関数がそれ以上に増えない値\n・それを満たすxが一つ定義域に存在する値\nであるという性質を持ちます。\n最小値は、反転した性質ですね。\n\nそのため最大値の候補は絞られます\n→①極大値 ②区間の端\nこの2点を調べてみましょう。(最小値は反転です)\n\n最後に、最大最小を論じる際に、よく出てくる言葉があるので、それを押さえておきましょう。\n・領域→「接する時」「端の時」に最大最小\n・接する→最短距離があります、注意です\n\nポイントはこんな感じです!\nよく分かんないかもしれませんが、演習しながら見てください!意味がわかってくるはずです!\n頑張ってください!応援してます!"}],["$","div",null,{"className":"flex mb-1","children":[["$","svg",null,{"stroke":"currentColor","fill":"currentColor","strokeWidth":"0","viewBox":"0 0 24 24","className":"text-subPrimary mr-1","children":["$undefined",[["$","path","0",{"fill":"none","d":"M0 0h24v24H0V0z","children":[]}],["$","path","1",{"d":"M12 6c1.1 0 2 .9 2 2s-.9 2-2 2-2-.9-2-2 .9-2 2-2m0 10c2.7 0 5.8 1.29 6 2H6c.23-.72 3.31-2 6-2m0-12C9.79 4 8 5.79 8 8s1.79 4 4 4 4-1.79 4-4-1.79-4-4-4zm0 10c-2.67 0-8 1.34-8 4v2h16v-2c0-2.66-5.33-4-8-4z","children":[]}]]],"style":{"color":"$undefined"},"height":16,"width":16,"xmlns":"http://www.w3.org/2000/svg"}],["$","div",null,{"className":"text-xs","children":["京都大学理学部"," ","こうしん"]}]]}],["$","div",null,{"className":"flex 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items-center py-4","children":[["$","div",null,{"className":"flex-1","children":[["$","div",null,{"className":"mb-1","children":"数三独学予習"}],["$","div",null,{"className":"text-xs text-caption line-clamp-2 mb-1","children":"範囲によるとしか言えないところです。\n\n数3は複素数平面 2次曲線 極限 微分法 積分法 と範囲がそれぞれ分かれています。\n\n\n複素数平面は単独の範囲なので教科書の内容を入れたら次の範囲に進んでもいいと思いますし、傍用問題集で固めるのもいいと思います。複素数平面に関しては現役生はどうしても後の微積に時間を取られ、演習不足になりがちなので、周りと差をつける意味でも後者をおすすめします。\n(東北大はけっこうでてると思う)\n\n\n2次曲線に関しては微分法などでも若干登場はあるものの微積に時間を割くべきなので教科書ので理解で十分だと思います。入試でもこれ単独での出題はけっこう少ないです。\nこればっかりは時間をどれだけ割けるかによります。\n\n\n極限 微分法 積分法に関しては入試でも頻出分野なので、理解を疎かにしないためにも、教科書→ 傍用問題集の流れにしてください。この分野は演習量がものを言います。特に微積は大事!\n\n\n頑張ってください、応援してます。\n\n\n"}],["$","div",null,{"className":"flex mb-1","children":[["$","svg",null,{"stroke":"currentColor","fill":"currentColor","strokeWidth":"0","viewBox":"0 0 24 24","className":"text-subPrimary mr-1","children":["$undefined",[["$","path","0",{"fill":"none","d":"M0 0h24v24H0V0z","children":[]}],["$","path","1",{"d":"M12 6c1.1 0 2 .9 2 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