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17:I[7060,["51","static/chunks/795d4814-03346c8d233b4adb.js","212","static/chunks/212-70508e17017a12c2.js","231","static/chunks/231-5dc9f3acdba63b0c.js","54","static/chunks/54-f848f8ba1c362ca7.js","23","static/chunks/app/advice/%5Bid%5D/page-186819a87df201a3.js"],"AdUnderAdvice"] 18:I[3194,["51","static/chunks/795d4814-03346c8d233b4adb.js","212","static/chunks/212-70508e17017a12c2.js","231","static/chunks/231-5dc9f3acdba63b0c.js","54","static/chunks/54-f848f8ba1c362ca7.js","23","static/chunks/app/advice/%5Bid%5D/page-186819a87df201a3.js"],"CommentPostButton"] 19:I[3866,["51","static/chunks/795d4814-03346c8d233b4adb.js","212","static/chunks/212-70508e17017a12c2.js","231","static/chunks/231-5dc9f3acdba63b0c.js","54","static/chunks/54-f848f8ba1c362ca7.js","23","static/chunks/app/advice/%5Bid%5D/page-186819a87df201a3.js"],"AdOnAdviceList1"] 1a:T12ba,普遍的なことだけを説明しても中々伝わりづらいと思うので、具体的に問題を1問出しながら説明させてください! まず前提として、応用の問題が解けるようになるためには以下のことが必要になります。(結論です) ・基本的な解法がすぐに出てくるようにする ・問題を見た時、前の問題との関連性から考えていく ・誘導に乗っていくのに慣れるのにはとにかく演習量が必要 1つ目は恐らく大丈夫だと思います。また、3つ目もこれから2次試験向けの演習を重ねるうちに「あの時の誘導に似てるなー」というような感覚で段々できるようになってくるものです。つまりは慣れです。自分自身もこれを強く感じています。最初は中々誘導に乗れず辛いかもしれませんが、まずは量をこなしましょう。 おそらく問題は2つ目です。 これは分かりやすく言うと、「こうやってやっていって…あ、(1)(2)ここで使う?」という考え方ではなく、「(1)や(2)の問題の考え方を上手く使えないかな〜」「今までやったことのある基本問題の考え方が何か使えないかな〜、あ、文章のこの部分前にやったあの問題文と似てるな〜」と言ったような、初めから誘導や基本問題などのヒントの方から答えを探っていくように考えていくことです(長くてごめんなさい)。 実際に問題を見て考えていきましょう!以下は2015年の九大の問題です。 以下の問いに答えよ。 (1)nが正の偶数のとき、2^n-1は3の倍数であることを示せ。 (2)pを素数とし、kを0以上の整数とする。2^(p-1)-1=p^kを満たすp,kの組を全て求めよ。 (※^の後は指数を表します。2^n-1は2のn乗-1、2^(p-1)-1は2のp-1乗-1です) (1)は割愛しますが、n=2l(lは自然数)とかと置いて二項定理で分解して3で括ったり、帰納法を使えばいいと思います。とにかく2^n-1が3の倍数だと分かればいいです。 問題は(2)ですね。先程言った通り、誘導を上手く使えないかという点からとにかく問題を見ましょう! まず見るべき点は式の形が左辺と似ている所です。誘導が使えそうですよね。 誘導を上手く使うコツですが、「誘導の部分と問題文の該当部分の違いを上手く見分けること」です。今回であればnがp-1に変わっています。また、(1)でnは"正の偶数"でしたが、p-1は"素数-1"ですよね。 ここの違いは何かあるでしょうか?? まず整数問題で素数が出たら、「2とそれ以外」という見方をするのは演習量をこなせば分かってきます。素数の中でも2だけ偶数で稀有、と認識できていればOKです。(ここは基本問題的な解法暗記の部分) 素数-1は、素数が2のときだけ奇数、素数が2以外のときは偶数になりますよね! ですので、2か2じゃない素数かで分けます。2じゃない素数のときは(1)の条件と一致するので使えそうですよね。まずは使いましょう! ○pが2以外の素数のとき (1)より左辺は3の倍数です。ということは右辺も3の倍数になります。p^k、つまり素数の累乗が3の倍数ということはpは3以外ありえないですよね。ここは素数ならではです。 ですのでp=3から左辺に代入するとk=1と決まります。 ○pが2のとき 代入していくとk=0になりますね。 以上から(p,k)=(3,1),(2,0)となりました! このように、「基本問題の解法はすぐに出ておくようにする」「誘導から常に考えていく(誘導と問題文の違いを認識し、見分けていく)」ことの重要性がわかったと思います。また、基本問題というのは、教科書や青チャートにある典型問題もそうですが、素数は2とそれ以外に分ける、といったような"応用問題でよく出てくるテクニック"もそうです!これは演習量を詰まないと中々インプットされないので、「演習量が大切」なのも再認識できるでしょう。 また、1問に時間をかけて思考していくこともとても大切です!最終的にその標準問題の解き方を覚えられると役には立ちますが、思考力というのは思考する時間を取らないと中々伸びません。1問に10分は考える時間を取りましょう! めちゃくちゃ長くなって申し訳ないですが、参考になれば幸いです!! 2:["$","main",null,{"className":"px-4 pt-4 pb-4","children":["$","div",null,{"className":"max-w-3xl mx-auto 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Bまで)に関する勉強法の質問には答えることができます!\nいいなと思った回答にはクリップしてもらえると、モチベが上がります!!\n国立も受けました。"}]}],["$","div",null,{"children":["$","$L7",null,{"href":"https://ck.jp.ap.valuecommerce.com/servlet/referral?sid=3364577&pid=884970531&vc_url=http%3A%2F%2Fshingakunet.com%2F%3Fvos%3Dnrmnvccp0000100","rel":"nofollow","target":"_blank","children":["$","$L8",null,{"src":"/images/document_request_banner.jpg","width":3660,"height":1500,"sizes":"100vw","style":{"width":"100%","height":"auto"},"alt":"UniLink パンフレットバナー画像","className":"mt-4 rounded"}]}]}],["$","div",null,{"className":"pt-4","children":["$","$L17",null,{"id":"adsbygoogle-init-under-advice"}]}]]}],["$","div",null,{"className":"flex justify-between","children":[["$","h1",null,{"className":"text-xl font-semibold","children":["コメント(",0,")"]}],["$","$L18",null,{"adviceId":"4ynngGwBTqPwDZPucqT1"}]]}],["$","div",null,{"className":"mb-8","children":["$","div",null,{"className":"text-xs p-4","children":"コメントで回答者に感謝を伝えましょう!相談者以外も投稿できます。"}]}],["$","h1",null,{"className":"text-xl font-semibold","children":"よく一緒に読まれている人気の回答"}],["$","div",null,{"className":"mb-8","children":["$","div",null,{"className":"divide-y","children":[["$","div",null,{"children":["$","$L7",null,{"href":"/advice/blIxzYABTqPwDZPu4nsT","children":["$","div",null,{"className":"flex items-center py-4","children":[["$","div",null,{"className":"flex-1","children":[["$","div",null,{"className":"mb-1","children":"数学の解法を思い付くためには"}],["$","div",null,{"className":"text-xs text-caption line-clamp-2 mb-1","children":" ①問題文で与えられている情報と、②最終的に問われている内容とを区別して、①→②にどう持っていくかを考えることが、数学の問題を解く上での第一歩だと思います。しかし、無駄な思考要素で時間を必要以上に割いてしまうのも勿体無いので、実際に考えるときは、思考の道のりを最短化するために②→①の方向に逆算して考えましょう。②を求めるためにはaとbとcの方法があって、aの方法で解くとしたらa-1とa-2とa-3が分かればよくて、a-1が分かるために①の情報をどれか使えないか、a-2が分かるために①から必要な情報を何か導けないか、a-3が分かるためには①のどれをどう使えば良いか…という感じです。これが入試問題をはじめとする応用問題への取り組み方です。\n 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items-center py-4","children":[["$","div",null,{"className":"flex-1","children":[["$","div",null,{"className":"mb-1","children":"数ⅲで積分 焦ってます。"}],["$","div",null,{"className":"text-xs text-caption line-clamp-2 mb-1","children":"まずは基本的な計算が出来るようになりましょう。\nその為にも教科書の問題で良いので、部分積分や置換積分の章の問題をこなして「部分積分と置換積分のどちらをすれば良いか分かれば計算ができる」という状態にします。\nそしてここからが多くの人が悩む、どこをどう置換するのか?いつ部分積分や置換積分をするのか?という問題です。\n基本的に置換積分や部分積分の目的は複雑な関数の積分を、既知の積分に置き換えるor変形するという事です。上の計算問題をこなしていく内に、どんな形の積分なら計算できるか感覚的に分かると思います。\nそのように解ける形の積分を自分なりに頭の中で整理してどの形に変形できるかな?と考えます。\n基本的には難しい所や邪魔なところを置換するorxのべき乗やlogを消したいから部分積分する…といった理解でも正直問題はないです。中には双曲線関数など数学的に重要な例や深い視点に立てば自然な置換も存在しますが、これは誘導が着くはずなのであまり気にしなくて良いです。\n纏めると、まずはきちんと計算が出来るようになる事と計算が出来る積分形を自分なりにしっかり理解する事が肝要だと思います。\n拙い文章ですが、役に立てれば幸いです。"}],["$","div",null,{"className":"flex mb-1","children":[["$","svg",null,{"stroke":"currentColor","fill":"currentColor","strokeWidth":"0","viewBox":"0 0 24 24","className":"text-subPrimary 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items-center py-4","children":[["$","div",null,{"className":"flex-1","children":[["$","div",null,{"className":"mb-1","children":"すぐに解法が思いつくには"}],["$","div",null,{"className":"text-xs text-caption line-clamp-2 mb-1","children":"間違っていたらすみませんが、おそらく考えている途中「手が止まっている」のではないでしょうか?\n国公立レベルの問題なら数学が得意な人でも、必死に手を動かし色んな道をトライ&エラーを繰り返しながら、正解っぽい道筋を見つけます。\n\n過去問を初めて解く時って、自転車のコマを外された感覚に似ていると思います。バランスが取れず、どうしていいか分からない。\nでも「何も書くことがない」というのはありえませんから、コケてもいいので一生懸命漕ぐことから始めましょう。\n\n\n僕が意識していた考え方を紹介します。\n①どの単元の組み合わせで構成されているのか考える。\n数学が苦手な人にとって、初見の問題は無限の道筋があるように感じてしまい、脳が閉じてしまいます。単元を意識すると思考がスッキリして、その単元の知識を有効に使えるようになります。その上で、単元内のどの問題と似ているのか、どの公式が使えそうかなどを意識してください。\n\n②過去に似ている問題がなかったか?(①と重複するようですが)\n少し式の一部が似ているでも、直感的な雰囲気が似ているでも構いません。その問題のやり方と似た方法を試すと、うまくいくことが多いです。このアプリ内でもよく言われている、「抽象化してメモする」習慣はここで力を発揮します。普段からどういう問題のときどうするのかをパターン化しておけば、初見の問題でもほぼ困らないです。\n\n③行き詰まったら、落ち着いて情報を整理する\n自分がどの条件を使ったのか整理しましょう。\nこの式はどの条件とどの条件が含まれたものなのか。この点はどの条件とどの条件を満たすものなのか。他に満たすべき条件は?など。(文章だけだと伝わりづらいですが)\n\n\n\n上記は試験本番で意識することですが、普段の勉強から深く考える癖をつけてください。\n「数学は暗記だ」と高を括って、上っ面の勉強をしているだけでは、その問題しか解けるようになりません。\nなぜそう解くのか、どういうときにこの公式を使うのかを、根本からきちんと理解しているかどうかを、試験では問われています。\n(数学は暗記と豪語している人達は無意識にこのへんのことが出来ているんだと思います)"}],["$","div",null,{"className":"flex 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mb-1","children":"数学の問題をやり直す上で、解答や式変形を一字一句覚えるなんていうことがな必要ないことは言うまでもないことだとおもいます。\nなぜなら、数値、条件が全く同じ問題なんて人生でそう出会わないからです。\n\nでは、どうするのか?ということですが、僕が意識していた点はその問題の核となる部分を抽出し抽象化、一般化することです。\n\n要は1から10を得てほしいと言えばいいのでしょうか?\n\n\n具体的に説明すると、立体図形の問題で、ベクトルで解こうとしたけど、なかなか上手くいかなかった。\n\n\n解答にはベクトルによる解法が書かれておりその解法がなかなかテクニカルで簡潔である。\nしかし別解に座標を置いて計算でごり押しする解き方も書いてある。こちらの方法はなかなか、計算量が多そうだ。\n\n\nこういうことがあったとします。\n\nこういう時に、じゃあテクニカルな式変形を覚えようとしていてはなかなか数学力はつきません。\n\nこの問題の復習はいくつかやり方が考えられますが、この問題の核を抽出し一般化とは、以下のようなことです。\n\n1.確かにベクトルのやり方もいい。なので、頭に留めておこう。\n\n2.座標を置くやり方は計算量が多い一方、やっていることは素直である。なので、本当に思いつかなかったら、最終的に座標を置けばいいのではないか?\n\n3.角度といった条件は出来るだけベクトルで扱うのが良さそうだ。\n\n4.交線などは、座標を置き平面の方程式を立てて求めていくのが良さそうだ。\n\n\nなどなど得られることはたくさんあるはずです。\n\n\nこれはあくまで一例ですが、1つの問題から学べることは案外多いものです。\n無作為に問題数をこなすのではなく密度の濃い演習をこなすことをお勧めします!\n\nあくまで僕個人の意見ですので、何か参考になれば幸いです。\n"}],["$","div",null,{"className":"flex mb-1","children":[["$","svg",null,{"stroke":"currentColor","fill":"currentColor","strokeWidth":"0","viewBox":"0 0 24 24","className":"text-subPrimary 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items-center py-4","children":[["$","div",null,{"className":"flex-1","children":[["$","div",null,{"className":"mb-1","children":"わからない問題にかける時間について"}],["$","div",null,{"className":"text-xs text-caption line-clamp-2 mb-1","children":"それは分野によって異なります。\n例えば 微分積分の問題は15分程度考えてわからなかったら答えを見ても良いと思います。\nなぜなら 微積はわりとワンパターンなので覚えたら終いだからです。\nそれに比べて 整数問題はワンパターンでは解けません。なのでじっくり考えるべきです。 どうしてもわからない時はその問題を一旦解くのをやめて、時間をおいて考えてみてください。 意外とわかったりします。\n\n数学の偏差値を上げるためには 勉強の際 一問を一問で完結させないことがポイントです。 そのためには 問題を解いたら その類題も解いてみたり、難しい問題が出て来たら どこの発想がなくて解けなかったのかしっかり分析することがひつようです。\nそしてもし過去問演習や模試の復習でわからない問題が出て来たら、 解答をすぐに見るのではなく、 思考のフローチャートを書いてみてください。\n\n具体的にいうならば\n三角関数の問題を解く際\n㊀グラフ㊁加法定理㊂変換公式\n\n→㊂でいこう\nCosだけの式になったから\n㊀tで置換する㊁因数分解する㊂tanに変換してみる\nなどなどと 樹形図のように思考回路を記すんです。\nするとどの状況でどの発想が足りなかったのかが明確になり、次にも繋がる勉強になります。やってみてください。"}],["$","div",null,{"className":"flex mb-1","children":[["$","svg",null,{"stroke":"currentColor","fill":"currentColor","strokeWidth":"0","viewBox":"0 0 24 24","className":"text-subPrimary 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items-center py-4","children":[["$","div",null,{"className":"flex-1","children":[["$","div",null,{"className":"mb-1","children":"別解のやり方"}],["$","div",null,{"className":"text-xs text-caption line-clamp-2 mb-1","children":"こんにちは!\n\n結論ですが、問題集に掲載されている別解は全て吸収した方がいいです!なので手を動かすまたは、方針を頭の中で考えることをしましょう!\n以下にその理由を記していきます。\n\n理由\n別解を多く知っていると本番で正解できる可能性が高くなるからです。\nある問題に対して、解方①と②があるときに、解き方によって、計算量や考える量が変わって来てますが、問題によって①、②のどちらがの方が早く正確にできるかは違うので、両対応することでもし解方①で沼っても、②で解くことでその問題を正解できる可能性が高くなります。\n慶應経済では特になのですが、数学は時間が足りないのに高い正答率を求められるので、沼ったらすぐに解方を変えて正解することは足切り突破と合格にとても重要です。\n\n頑張って下さい!\n応援しています!!\n\n\nこの解答がいいなぁと思ったらファンになって頂けると幸いです。高評価もよろしくお願いします!"}],["$","div",null,{"className":"flex mb-1","children":[["$","svg",null,{"stroke":"currentColor","fill":"currentColor","strokeWidth":"0","viewBox":"0 0 24 24","className":"text-subPrimary mr-1","children":["$undefined",[["$","path","0",{"fill":"none","d":"M0 0h24v24H0V0z","children":[]}],["$","path","1",{"d":"M12 6c1.1 0 2 .9 2 2s-.9 2-2 2-2-.9-2-2 .9-2 2-2m0 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