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1a:I[6549,["51","static/chunks/795d4814-03346c8d233b4adb.js","212","static/chunks/212-70508e17017a12c2.js","231","static/chunks/231-5dc9f3acdba63b0c.js","54","static/chunks/54-f848f8ba1c362ca7.js","23","static/chunks/app/advice/%5Bid%5D/page-2c9c2b8245971fa7.js"],"CommentItemName"] 1b:I[3866,["51","static/chunks/795d4814-03346c8d233b4adb.js","212","static/chunks/212-70508e17017a12c2.js","231","static/chunks/231-5dc9f3acdba63b0c.js","54","static/chunks/54-f848f8ba1c362ca7.js","23","static/chunks/app/advice/%5Bid%5D/page-2c9c2b8245971fa7.js"],"AdOnAdviceList1"] 1c:T10fe,僕のやり方を語ろうと思う! 東大は受験しませんでしたが、東大に70人以上受かった学年での最後の定期考査で化学首位(まぐれ)だった僕の勉強法を語ろうと思います。参考になることがあれば嬉しいです。 まず、使っていた参考書についてです。高2までは高校での手厚い授業を受けつつ長期休暇に出る課題でセミナーをやっていました。高3の途中から、過去問演習に入ると、授業で扱わない問題や予習を自習中にやりました。(セミナー以外学校のオリジナルテキスト)学校の授業や課題と無関係にやっていた参考書は化重と阪大の過去問だけです。(共テ演習は含まない)高2の途中から化重を始め、阪大の過去問が忙しくなるまで3周しました。演習は、正直化重だけでいいです。新研究、新演習は難しいことが書かれていますが、あまり入試に出ないようなことが多く、また分厚すぎて一周に時間がかかると思い、やりませんでした。 次に、演習の前の理解をどうしたかについてです。僕の高校のオリジナルテキストには最後の方に、小テストが掲載されており、それが授業の小テストで出題される事になっていました。学校の復習としてその小テストの空欄を埋めることで知識を定着させることができていました。(別のテキストにも同じ小テストが載っているので、同じ範囲の小テストを大体3回ずつくらいやりました)それに加えて、電子辞書やWikiで物質名や偉大な化学者の名前などを検索したりして、知識を増やしたり、理解を深めたりもしました。どちらも結構オススメな勉強法です。小テストがなければ自分で作ってみるのもいいかもです。 最後に、問題の解き方についてです。理論の計算が苦手と言っていましたね。もしかしたら参考になるかもです。僕は小学校から1cm四方の方眼のあるノートを使っており、数学や社会、国語なども大抵そうしていました。化重を解く時もそうしていました。(なお大学でも継続)友人のノートを見るに、7mmくらいの間隔で引かれた横線の間にまあまあ無秩序に式を書いているようでした。逆に僕は結構厳密なルールに則りノートに問題を解いていました。そのルールをざっと紹介します。 1.ノートに印刷された縦線のうち、左から2本目をなぞり、左上の1マスに6/3みたいに日付を書く(それより左には注釈とか直しを書いたりする) 2.左から2列目に大問番号を書き、さらにその一個右に小問番号を書き、その下部問題の番号はどんどん右に書く (1️⃣(1)①ヘマトキシリン    ②エオジン   (2)細胞質がrRNAに富むから。 といった感じです。) 3.小問の記述は、その問題番号より左に出しゃばらない 4.分数があっても単位がややこしくても絶対2行使わない(式が長い時は折り返して2行もありえる) 5.数字と単位は別のマスに書き、どんだけ桁が多くても一マスに収める。ただし、演算記号(+-×÷)は一マス占めるので、有効数字で書く時は数に3マス使う このルールは、小学校の頃から変えていません。僕は結構異端だったようですが、あなたがこれを採用して異端者が1人増えたら嬉しいです(笑)。まあ、ここまで厳密にやるのも疲れるのでルールは自分で決めてください。アレンジ次第では、計算問題を自分に対してわかりやすく書けるようになったりするかもしれん、と思い紹介してみました。 色々書きましたが、あんまり参考書を浮気するのは良くないみたいなことも聞きましたし、自分の信じる参考書を何周もするのが望ましいと僕は思います。最後に、あなたが理論など苦手分野を克服し、東大に合格することを願っています。頑張ってください。応援しています。1d:Tc7d,こんにちは!  科学大の化学の記号はむずかしいですよね、   私は反応に伴う色の変化を全部表にして一回書いて見てました。使っているかわかりませんが、化学の新研究の系統分析のところに載っている表を書きながら覚えてましたね。そして自分で語呂合わせを作ってました。自分で考えた方が頭に残りやすいと思います。  記号問題でいうと、最初の方に周期表に関する記号問題があると思いますが、そこに出てくる金属元素は有名であるが5,6周期にあるものもたくさん出てきて、何族かわからないと芋づる式にその問題を落としてしまうことが多いと思います。なので、有名な金属元素については何周期であろうが何族かまで覚えとくと言いと思います。私は1,2,6,10,11,12,14族は語呂合わせを作るなりして覚えてました。  記号問題はおそらく以下のように採点されてます。 ・答えが1つの場合   正解と不正解を1つずつ解答→5点 ・答えが2つの場合   正解を1つのみ解答→6点   正解と不正解を1つずつ解答→5点  なので、私は極力記号で0点を取らないように自信がないのが2つあれば2つ書いてました。  東工大の化学20ヵ年を見てもらえばわかると思うのですが、記号問題に関しては意外と使い回しが多いです。記号問題のやり直しはしっかりした方がいいと思います。    化学基礎の範囲の記号問題は定番問題、無機化学の記号も決まったパターンが多いと思います。勉強すれば点数が結びついてくると思います。  有機化学の構造決定、有機化合物の特徴の記号問題は化学の新演習で得た知識のみで充分戦えると思います。合成高分子、タンパク質、アミノ酸については化学の新研究を読んでました。とくにマルトースの還元による反応物のモル比率は過去問で何回も見た記憶があります。やはり使い回しがあります。  化学は他の科目に比べて易しいイメージがありますが、高得点も取りにくいイメージがあります。化学は一問10点と意外と点数が大きいのに途中経過がないので、わかっていても計算ミス、凡ミスで点数が消し飛びます。  記号問題では正しいものを聞いているのか、間違っているものを聞いているのか、問題文の書き方のせいでこんがらがりやすいと思います。  私は選択肢の横に○×を書いてました。選択肢が間違っているから記号に斜線を引くと、選択肢が正しくないことを書いているのか、問題文が正しくないものを聞いているのに、選択肢に正しい文が書いているから斜線を引いているのかわからなくなってミスに繋がると思います。  いろいろ工夫をすることが大事だと思います!頑張ってください!2:["$","main",null,{"className":"px-4 pt-4 pb-4","children":["$","div",null,{"className":"max-w-3xl mx-auto w-full","children":[["$","div",null,{"className":"mb-8","children":["$","$L7",null,{"href":"https://unilink-app.onelink.me/isbO/h6xeh63x?advice=-9oWVGcBTqPwDZPuJdcN","target":"_blank","children":["$","$L8",null,{"src":"/images/web_to_app_banner.jpg","width":3660,"height":1500,"sizes":"100vw","style":{"width":"100%","height":"auto"},"alt":"UniLink WebToAppバナー画像","className":"mb-4 rounded"}]}]}],["$","h1",null,{"className":"text-xl font-semibold mb-2","children":"化学の数字「0」について"}],["$","div",null,{"className":"flex justify-between mb-4","children":[["$","div",null,{"className":"text-left text-xs text-caption","children":["クリップ(",2,") コメント(",1,")"]}],["$","div",null,{"className":"text-right text-xs text-caption","children":"11/27 7:33"}]]}],["$","div",null,{"className":"coach-mark mb-4","children":"UniLink利用者の80%以上は、難関大学を志望する受験生です。これまでのデータから、偏差値の高いユーザーほど毎日UniLinkアプリを起動することが分かっています。"}],["$","div",null,{"className":"mb-4","children":["$","$L13",null,{"clientImageUrl":"https://firebasestorage.googleapis.com/v0/b/unilink-48e75.appspot.com/o/images%2Fs_0237494A37214D599740C30EEB234DC5.jpg?alt=media&token=29d52510-3d9c-4c45-8ae7-c77b411d12c9","clientUserName":"ホタル","infoString":"高2 熊本県 九州大学文学部(60)志望","adviceId":"-9oWVGcBTqPwDZPuJdcN"}]}],["$","div",null,{"className":"mb-8","children":[["$","div",null,{"className":"leading-loose whitespace-pre-wrap","children":[["$","div","consultation-part-0",{"children":[null,"こんにちは!今試験に向けた化学の問題を解いてるのですが数字の0に悩まさせています…。\n問題で言うと「①28.0Lの酸素O2の物質量は何molか」の答えは「1.25mol」に対して「②5.60LのアンモニアNH3の物質量は何molか」の答えは「0.250mol」でわざわざ最後に0を付ける時とつけない時の違いがわかりません。また同じような問題で答えが「0.500mol」など0が2個ついて来るものもあり、どのような仕組みで付け足されているのかが分かりません。\n\nそこを教えていただけないでしょうか?お願いします!"]}]]}],["$","div",null,{"className":"pt-4","children":["$","$L14",null,{}]}],null]}],["$","h1",null,{"className":"text-xl font-semibold mb-2","children":"回答"}],["$","div",null,{"className":"mb-4","children":["$","$L15",null,{"adviserImageUrl":null,"adviserName":"たぬぽん","adviserDepartment":"名古屋大学医学部","adviceId":"-9oWVGcBTqPwDZPuJdcN"}]}],["$","div",null,{"className":"coach-mark mb-4","children":"すべての回答者は、学生証などを使用してUniLinkによって審査された東大・京大・慶應・早稲田・一橋・東工大・旧帝大のいずれかに所属する現役難関大生です。加えて、実際の回答をUniLinkが確認して一定の水準をクリアした合格者だけが登録できる仕組みとなっています。"}],["$","div",null,{"className":"mb-8","children":[["$","div",null,{"className":"leading-loose whitespace-pre-wrap mb-4","children":[["$","div","advice-part-0",{"children":[null,"有効数字、というものです。ものすごく適当にいうと、問題文に出てくる数字と小数点以下の桁数を揃えればいいというものですが、実はかなり難しいです。\n\n教科書の巻末に説明が載っていると思いますので見てみてください。"]}]]}],["$","div",null,{"className":"mb-4","children":["$","$L16",null,{"adviserImageUrl":null,"adviserName":"たぬぽん","adviserDepartment":"名古屋大学医学部","adviceId":"-9oWVGcBTqPwDZPuJdcN","numberOfFan":86,"clipsAvg":6.697478991596639,"adviceRateAvg":4.451327433628318,"profile":"名古屋大学医学部医学科 現役合格\n東大の理科二類を目指して勉強していましたが、受験直前に医師になりたいと思い、医学部を受験しました。\n国立理系学部を目指す人の力になりたいです。"}]}],["$","div",null,{"children":["$","$L7",null,{"href":"https://ck.jp.ap.valuecommerce.com/servlet/referral?sid=3364577&pid=884970531&vc_url=http%3A%2F%2Fshingakunet.com%2F%3Fvos%3Dnrmnvccp0000100","rel":"nofollow","target":"_blank","children":["$","$L8",null,{"src":"/images/document_request_banner.jpg","width":3660,"height":1500,"sizes":"100vw","style":{"width":"100%","height":"auto"},"alt":"UniLink パンフレットバナー画像","className":"mt-4 rounded"}]}]}],["$","div",null,{"className":"pt-4","children":["$","$L17",null,{"id":"adsbygoogle-init-under-advice"}]}]]}],["$","div",null,{"className":"flex justify-between","children":[["$","h1",null,{"className":"text-xl font-semibold","children":["コメント(",1,")"]}],["$","$L18",null,{"adviceId":"-9oWVGcBTqPwDZPuJdcN"}]]}],["$","div",null,{"className":"mb-8","children":["$","div",null,{"className":"divide-y","children":[["$","div",null,{"className":"flex py-4","children":[["$","div",null,{"className":"mr-2","children":["$","$L19",null,{"avatarUrl":"https://firebasestorage.googleapis.com/v0/b/unilink-48e75.appspot.com/o/images%2Fs_0237494A37214D599740C30EEB234DC5.jpg?alt=media&token=29d52510-3d9c-4c45-8ae7-c77b411d12c9","contributorName":"ホタル","adviceId":"-9oWVGcBTqPwDZPuJdcN"}]}],["$","div",null,{"className":"flex-1","children":[["$","div",null,{"className":"flex justify-between","children":[["$","div",null,{"className":"mb-2","children":["$","$L1a",null,{"contributorName":"ホタル","adviceId":"-9oWVGcBTqPwDZPuJdcN"}]}],["$","div",null,{"className":"text-xs text-caption","children":"11/27 9:03"}]]}],["$","div",null,{"className":"text-xs whitespace-pre-wrap","children":"巻末ページ、載っていました!ココを見てしっかり勉強しようと思います!\n回答して下さったのが早くてとても助かりました!本当にありがとうございます😆"}]]}]]}]]}]}],["$","h1",null,{"className":"text-xl font-semibold","children":"よく一緒に読まれている人気の回答"}],["$","div",null,{"className":"mb-8","children":["$","div",null,{"className":"divide-y","children":[["$","div",null,{"children":["$","$L7",null,{"href":"/advice/dw1CgmoBTqPwDZPu43m1","children":["$","div",null,{"className":"flex items-center py-4","children":[["$","div",null,{"className":"flex-1","children":[["$","div",null,{"className":"mb-1","children":"化学基礎からが全くわからない"}],["$","div",null,{"className":"text-xs text-caption line-clamp-2 mb-1","children":"こんにちは。\n\nmolの計算がよくわからない為に、その後の計算(中和やph、電池の問題など)も解けないという推測のもとに回答しますね。そうではなく、単元ごとに意味のわからない部分があると言うことであれば、個別にご質問なさると良いと思います。\n\nまず、モルを難しく考えすぎてはいないですか?\n6.02×10^23個=1 mol にしよう!と決めただけです。12個で1ダースと同じですね。\nそして、同じ原子を6.02×10^23個集めると、[その原子の原子量]g になります。\n同じ原子を6.02×10^23個集めたときの重さ、といちいち書くのは面倒なので、モル質量と呼びましょう。単位は1molで○gを分数にして g/mol ですね。\n\n炭素の原子量が12とします。いま、炭素が24 gあります。炭素の原子は何molありますか? 簡単ですね、2 molです。個数でいえば2×6.02×10^23個ですね!\n(分子の時は少し気をつけて下さい。水素の原子量を1とします。水素ガスが4 gあります。このとき水素原子は4 mol存在しますが、水素ガス(分子)は2 molです。)\n\nこのくらいは分かってる!とお思いかも知れませんが、mol計算が苦手な方は単位変換が苦手な印象です。計算の時、単位同士も掛け算、割り算していますか? もっとハイレベルな部分でわからないと言うことでしたら申し訳ありません…\n\nmolができれば、phや化学式も解けるはずです。\n電気分解などは多少慣れが必要ですが、一個の原子から何個の電子が出るのかを知っていれば後は比の計算ですから、こちらも大丈夫だと思います。\n\n最後に参考書ですが、私自身はあまり役に立ったと思えたことがありません。読んだ時は分かった気になるのですが…。結局、自分の言葉で説明できるように頭を使って理解するしかないと思います。参考書はその補助に使うものだと考えて、頑張ってください!"}],["$","div",null,{"className":"flex mb-1","children":[["$","svg",null,{"stroke":"currentColor","fill":"currentColor","strokeWidth":"0","viewBox":"0 0 24 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items-center py-4","children":[["$","div",null,{"className":"flex-1","children":[["$","div",null,{"className":"mb-1","children":"有効数字がわからない"}],["$","div",null,{"className":"text-xs text-caption line-clamp-2 mb-1","children":"はじめまして、ご質問にお答えさせていただきます、東京大学理科I類の者です。\n\n10^-1の場合はわざわざその表記にせず、0.112のように書いてあげれば良いです。\n\n有効数字は誤差を含みながらも、知りたい位まで(例えば実験などで機械が読み取れるであろう数値の限界)示れば良いです。\n\nそれを1.12×10^-1と答えようが、0.112と答えようがそこで点数が引かれるということは、大学入試においてはありえません。あるとすれば、表記の指定がある場合なので問題文はしっかり読んだほうがいいです。\n\nただ、基本的に問題文などに出てくる数値の表記に合わせてあげれば大丈夫なので、心配だというのであれば、合わせて書けばよろしいかと思います!\n"}],["$","div",null,{"className":"flex mb-1","children":[["$","svg",null,{"stroke":"currentColor","fill":"currentColor","strokeWidth":"0","viewBox":"0 0 24 24","className":"text-subPrimary mr-1","children":["$undefined",[["$","path","0",{"fill":"none","d":"M0 0h24v24H0V0z","children":[]}],["$","path","1",{"d":"M12 6c1.1 0 2 .9 2 2s-.9 2-2 2-2-.9-2-2 .9-2 2-2m0 10c2.7 0 5.8 1.29 6 2H6c.23-.72 3.31-2 6-2m0-12C9.79 4 8 5.79 8 8s1.79 4 4 4 4-1.79 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mr-2","children":0}],["$","svg",null,{"stroke":"currentColor","fill":"currentColor","strokeWidth":"0","viewBox":"0 0 24 24","className":"text-subPrimary mr-1","children":["$undefined",[["$","path","0",{"fill":"none","d":"M0 0h24v24H0z","children":[]}],["$","path","1",{"d":"M16.5 3c-1.74 0-3.41.81-4.5 2.09C10.91 3.81 9.24 3 7.5 3 4.42 3 2 5.42 2 8.5c0 3.78 3.4 6.86 8.55 11.54L12 21.35l1.45-1.32C18.6 15.36 22 12.28 22 8.5 22 5.42 19.58 3 16.5 3zm-4.4 15.55-.1.1-.1-.1C7.14 14.24 4 11.39 4 8.5 4 6.5 5.5 5 7.5 5c1.54 0 3.04.99 3.57 2.36h1.87C13.46 5.99 14.96 5 16.5 5c2 0 3.5 1.5 3.5 3.5 0 2.89-3.14 5.74-7.9 10.05z","children":[]}]]],"style":{"color":"$undefined"},"height":16,"width":16,"xmlns":"http://www.w3.org/2000/svg"}],["$","div",null,{"className":"text-xs mr-2","children":2}]]}],["$","div",null,{"className":"text-xs rounded-lg border border-text px-4","children":"化学"}]]}]]}],["$","div",null,{"className":"ml-3","children":["$","div",null,{"className":"bg-caption w-20 h-20 rounded-sm overflow-hidden","children":["$","div",null,{"className":"w-full h-full 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items-center py-4","children":[["$","div",null,{"className":"flex-1","children":[["$","div",null,{"className":"mb-1","children":"理解できない"}],["$","div",null,{"className":"text-xs text-caption line-clamp-2 mb-1","children":"\nこんにちは!東工大一年のたまちゃんです。\n物理や化学には有効数字というものがあります。\n問題を見ていないので、よくわからないのですが、問題文の中に出てくる数字も3×10^3などのように表されていないでしょうか?\n6×10^4は有効数字一桁であり、6.0+10^4は有効数字二桁、6.00×10^4は有効数字三桁となります。\nまた400は有効数字三桁、40は有効数字二桁です。\n解答をする際の原則として、問題文の中に出てくる値の有効数字に合わせるというものがあります。これが守られていないと減点対象となります。\nですから、問題文の中に出てくる値が有効数字一桁であるから、400だと減点されてしまいます。\n有効数字に関しての説明は難しいので、ネットなどで検索してみて下さい。\n拙い説明で申し訳ありません。"}],["$","div",null,{"className":"flex mb-1","children":[["$","svg",null,{"stroke":"currentColor","fill":"currentColor","strokeWidth":"0","viewBox":"0 0 24 24","className":"text-subPrimary mr-1","children":["$undefined",[["$","path","0",{"fill":"none","d":"M0 0h24v24H0V0z","children":[]}],["$","path","1",{"d":"M12 6c1.1 0 2 .9 2 2s-.9 2-2 2-2-.9-2-2 .9-2 2-2m0 10c2.7 0 5.8 1.29 6 2H6c.23-.72 3.31-2 6-2m0-12C9.79 4 8 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items-center py-4","children":[["$","div",null,{"className":"flex-1","children":[["$","div",null,{"className":"mb-1","children":"計算問題が全く解けない"}],["$","div",null,{"className":"text-xs text-caption line-clamp-2 mb-1","children":"こんにちは!\n北大志望ということで、お答えさせていただきます!\n\n①ゴールから逆算する事\n例えばpHを求める問題の時\npHを求めたい→pHは溶液の水素の濃度→H+ のmolと溶液の量が分かればいい。\nなどのように、ゴールから逆を辿る事で見えやすくなることがあります。\n必ず過程の1つ1つは基礎計算問題と同じです!\n\n②図を用いること\n 棒グラフや表などを意識的に使ってみてください!\n視覚化することで、どのような計算を実行すべきか分かりやすくなります!\n例えば、逆滴定の考えなどに棒グラフはとても有効です!\n\n以上2点が僕の意識してた事です。\n\n最初は誰も出来ません。\n問題演習を進めて行きながら、毎度色々な工夫をしてみてください!きっとあなたにピッタリな方法が見つかると思います!\n\n喜びの春を迎えることを、心より期待しております!\n"}],["$","div",null,{"className":"flex mb-1","children":[["$","svg",null,{"stroke":"currentColor","fill":"currentColor","strokeWidth":"0","viewBox":"0 0 24 24","className":"text-subPrimary mr-1","children":["$undefined",[["$","path","0",{"fill":"none","d":"M0 0h24v24H0V0z","children":[]}],["$","path","1",{"d":"M12 6c1.1 0 2 .9 2 2s-.9 2-2 2-2-.9-2-2 .9-2 2-2m0 10c2.7 0 5.8 1.29 6 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items-center py-4","children":[["$","div",null,{"className":"flex-1","children":[["$","div",null,{"className":"mb-1","children":"鉛蓄電池 充電後の電解液濃度を求めるには"}],["$","div",null,{"className":"text-xs text-caption line-clamp-2 mb-1","children":"こんにちは!\n北海道大学1年のひなたです!\n\n早速本題に入ります。\n\n質問文からどの物質のどんな濃度を求めるかわからないのでここでは溶質Aの質量パーセント濃度を求めるとします。\n他の濃度の求め方は最後に記述しときます。\n\nまず、「質量パーセント濃度」の定義を確認しましょう。\n濃度というのは溶液100g中に含まれる溶質の質量gとういうことですね!式にすると\n\n(溶質の質量g / 溶液の質量g) × 100\n\nつまり、溶液と溶質の質量を求めばいいのです!\n\nまず溶質から考えましょう!\n元々あった物質量から足し算引き算をすれば良いだけです。反応して他のものになったならその分引き算をし、何かが反応してその物質になったなら足し算をすれば良い。鉛蓄電池では反応式から求めることが多いですので単位は全てmolで合わせてその後にgにした方が楽です。\n次に溶液を考えましょう!\n問題にもよりますが一番大事なのはやっぱり変化量を考えることです。質量が増えたならならその分引き算をし、何かが反応して質量が増えたら足し算をすれば良い。問題文をヒントにして満遍なく考えましょう。(具体的な考え方はいろんな問題があるので一概に言えないです、すみません)\n\n二つの値を求めて計算すればおしまいです。\n\n他の濃度も同じことやります。\nまず定義を考えて、求めたいものを明確にする。\nそして問題文よりその変化を計算して濃度を求める。問題文から必ず求めれるので頑張ってください!\n\n大事なのは求めたいものをはっきりさせるのと問題文から何が変化したかを考えることです!\n\n以上です。理論化学を苦手にしている人が多いですが理解すれば安定します。ゴールをはっきりし、何が起こってるか理解すれば化学は怖くないです!頑張ってください!"}],["$","div",null,{"className":"flex mb-1","children":[["$","svg",null,{"stroke":"currentColor","fill":"currentColor","strokeWidth":"0","viewBox":"0 0 24 24","className":"text-subPrimary mr-1","children":["$undefined",[["$","path","0",{"fill":"none","d":"M0 0h24v24H0V0z","children":[]}],["$","path","1",{"d":"M12 6c1.1 0 2 .9 2 2s-.9 2-2 2-2-.9-2-2 .9-2 2-2m0 10c2.7 0 5.8 1.29 6 2H6c.23-.72 3.31-2 6-2m0-12C9.79 4 8 5.79 8 8s1.79 4 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items-center py-4","children":[["$","div",null,{"className":"flex-1","children":[["$","div",null,{"className":"mb-1","children":"物理と化学についてです!"}],["$","div",null,{"className":"text-xs text-caption line-clamp-2 mb-1","children":"はじめまして!やきそばといいます。\n質問について\n①演習量について物理化学それぞれ分けて、\n②微積を用いた物理について、\n回答していきます。\n\n①まず物理ですが、先生の仰る通りテキストを完璧にすることが重要だと思います。物理は定義や基本の原理原則を抑えていないと、どれだけ演習をしても伸びにくい科目です。まずはテキストで原理原則などを理解してみてください。演習は、テキストの復習としてリードαで感覚を掴んだ後、名問の森に移るなどがおすすめですが、微積物理であれば新物理入門問題演習という問題集がおすすめです。\n 次に化学ですが、理論・無機・有機全ての分野で演習量がものを言う科目です。授業の後に基本的な問題集(リードαやセミナーなど)で復習して、重要問題集、そしてそれが8割程度できるようになったら化学の新演習などでたくさんの形式の問題に触れるといいと思います。\n\n②微積物理ですが、一番重要なのは数式の意味を理解すること、です。なぜ運動方程式を積分するとエネルギーの関係式になるのか、なぜモーメントの関係式を積分すると角運動量の関係式になるのか、など意味や理由が分からないと、どの問題でどのような操作をするのか(微分や積分をするのか、しないのか)が分からないのでぜひ理解してください。\n慣れも必要ですが、慣れるためと言って理解を怠って問題演習ばかりしていると、微積を利用する良さが消えてしまうので気をつけてください。私が利用していた新物理入門問題演習には、問題の前に軽く式の関係性が書かれていて非常に良かったのでおすすめです。\n\n他に気になることがあればメッセージ送ってください!\n限りある時間で工夫して勉強頑張ってください、応援してます!\n"}],["$","div",null,{"className":"flex mb-1","children":[["$","svg",null,{"stroke":"currentColor","fill":"currentColor","strokeWidth":"0","viewBox":"0 0 24 24","className":"text-subPrimary mr-1","children":["$undefined",[["$","path","0",{"fill":"none","d":"M0 0h24v24H0V0z","children":[]}],["$","path","1",{"d":"M12 6c1.1 0 2 .9 2 2s-.9 2-2 2-2-.9-2-2 .9-2 2-2m0 10c2.7 0 5.8 1.29 6 2H6c.23-.72 3.31-2 6-2m0-12C9.79 4 8 5.79 8 8s1.79 4 4 4 4-1.79 4-4-1.79-4-4-4zm0 10c-2.67 0-8 1.34-8 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items-center py-4","children":[["$","div",null,{"className":"flex-1","children":[["$","div",null,{"className":"mb-1","children":"中和滴定に電離度がなぜ関係ないのか"}],["$","div",null,{"className":"text-xs text-caption line-clamp-2 mb-1","children":"それは確かに私も不思議に思っていました。\n\n私は化学の専門家ではないので、あくまで一つの考え方として見て下さい。詳しいことは、化学の先生などにうかがったほうがいいと思います。\n\n後々習うとは思いますが、物質は電離するとき、電離平衡というバランスをとります。たとえばアンモニアでは、\nNH3 H2O ⇌NH4 OH-\nとなります。\n矢印が両方向にあることからも分かると思いますが、反応は右にも左にも進みます。NH3とNH4 ,OH-の濃度の比が一定になるように反応が起こります。\n\n塩酸を加えると、H とOH-が反応して、H2Oが生成します。すると、OH-の濃度は減少するわけです。そうなると先ほどの電離式の左右の比が崩れてしまうため、それを補うように反応が右に進みます。すると、アンモニアがさらに電離します。\nこれが続いていくと、アンモニアは続々と電離していき、最終的には全て電離することになります。\n\nこう考えると、少し納得がいく気がします。\n\nちなみに、電離度というのは、先ほどの電離式のそれぞれの濃度の比から導き出された値になります。高3になると、その算出の仕方も学ぶと思いますので、楽しみにしておいて下さい。"}],["$","div",null,{"className":"flex mb-1","children":[["$","svg",null,{"stroke":"currentColor","fill":"currentColor","strokeWidth":"0","viewBox":"0 0 24 24","className":"text-subPrimary 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