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1c:Tc93,数学と化学に関しては私も現役の時は心当たりがあります。特に数学はセンス的な要素が強いと思っていたので、解ける解けないの差が激しかったです。

さて、少しひねった問題が来ると解けないのが悩みということですが、まず、最低限の勉強ができていることが大事です。おそらくそこらへんはテスト期間で補っているので大丈夫かと思います。

その中で同じような問題で少しひねっている問題というのはどうすればいいかわからないと思うかもしれませんが、解き方としてはひねる前の解き方と同じようなのに気づくことはできているでしょうか？そのような問題の模範解答をじっくり吟味しているでしょうか？その時解けなかった問題はしょうがないですが、そのあとのフィードバックが大事です。そして、この解法やったことがあるなと感じることが大切です。

具体的に述べるのは難しいですが、例えば二次方程式の2解が正の値をとるための条件は
f(0)>0
軸>0
判別式≧0
で必要十分ですよね。これは大丈夫でしょうか？

これの少しひねった問題が例えば二次方程式の解が0<x<1の範囲で持つ条件はどうでしょうか？
これは場合分けが必要ですが、そのうち2解がともに0<x<1の範囲の時はどのような条件かというと
f(0)>0
f(1)>0
0<軸<1
判別式≧0
で必要十分です。これと先ほどの上の条件と比較すると同じような感じですよね？つまり端点のみに具体的な数字の条件があるときにこのような条件で進めていくのがセオリーです。

上の解法を知識ゼロから解けと言われたら厳しいものがあるかと思いますが、一通り通っていることなら問題を見たときに「あっ、この問題はこの解法かな？」と瞬時に判断できるはずです。その感覚が大事です。「あー、これどうすればいいんだっけ…？」みたいな感じになっているのは良くないです。

これは勉強する時は問題を解き始める前に一瞬立ち止まって考えください。これを意識するしないとでは雲泥の差です。これは私自身、現役の時には気づかなかったことですが、浪人してからはこのことを意識するだけで、解ける問題のレパートリーが増えました。

闇雲にただ問題をこなすだけなら、むしろその場しのぎになってしまいます。それなら、数学の問題とかは時間がないのなら問題をみてこのような解法でいけばいいかなと思えるなら解かなくていいです。

要は、解き方に“意識“して問題演習を行ってください。時間のかける方はこっちの方です。

模試の前とかは、全国模試であれば定期テストなどでできなかった問題の教科書レベルの類題を確認する感じでいいと思います。高校生は部活等で時間がないと思われますので。1d:Tcbe,こんにちは！東工大一年のたまちゃんです。
物理のオススメとしては、物理のエッセンスです。物理のエッセンスは問題も割と多く載せてあるので、高校2年のうちはこれだけでも大丈夫だと思います。それで不安ならば、基礎問題精講や良問の風、発展をしたいなら名門の森などをやれば良いと思います。まぁ、エッセンスと良問の風はほとんど同レベルですので、良問の風を使うなら、エッセンスで学んだことを問題演習でアウトプットする用になると思います。
化学は鎌田・福間シリーズ(大学受験Doシリーズ)くらいしかわからないです。すみません…。この参考書も問題が割と多かったと思うので、これだけでも十分だと思いますが、演習もしたいのであれば、基礎問題精講、CanPassなどがオススメです。解説が詳しめなので。ただ、CanPassは少し難しめ。

次は物理を学ぶ際のポイントについて、自分なりに思っていることを書きます。
まず、力の方向(力の矢印の向き)がわかって、運動方程式を立てるのが普通の力学の問題です。これが出来ていないなら、問題は解けません。これは基礎中の基礎ですので、疎かにしないでください。
また、次元にも注意を払うと、計算ミスに気づけることもあります。次元は単位のことです。例えば、計算をして答えが(m+M^2)g となったとしましょう。この答えは100%間違いです。なぜかわかりますか？
次元(単位)が違うものを足したり引いたりは出来ないからです。mの単位はkgですが、M^2の単位は(kg)^2ですから、足すことはできません。ですから、この答えはあり得ません。計算してこの答えになった時点で、やり直さなければならないのです。こういうチェックをしていると、あり得ない答えの時に気付けます。(尚、掛け算、割り算は単位が違ってもできます。)
ですから、次元に普段から注意する癖をつけておくことで、模試や本番の時に計算ミスに気付けます。

化学に関しては、理論化学ですと、計算問題がほとんどです。計算はモルで行うことが多いと思います。今、何の計算をしているのかを理解しながら勉強して下さい。何と何をイコールで結んでいるのかなど。また、熱力学の際、〜エネルギーが出てくると思いますが、エネルギーがつくものはマイナスと覚えておいて下さい。

スマホに関しては、私はよくわからないです笑
私はスマホの電源を切ったり、あと30分したら休憩しよう などと思って頑張ってましたが…。
それでも私もスマホを使いすぎることもしばしばありました。なので、あまり特効薬のようなものは無いです。すみません…。

物理と化学は理系にとってとても重要ですので、頑張ってください！応援しています！
長文失礼しました。2:["$","main",null,{"className":"px-4 pt-4 pb-4","children":["$","div",null,{"className":"max-w-3xl mx-auto w-full","children":[["$","div",null,{"className":"mb-8","children":["$","$L7",null,{"href":"https://unilink-app.onelink.me/isbO/h6xeh63x?advice=-9oWVGcBTqPwDZPuJdcN","target":"_blank","children":["$","$L8",null,{"src":"/images/web_to_app_banner.jpg","width":3660,"height":1500,"sizes":"100vw","style":{"width":"100%","height":"auto"},"alt":"UniLink WebToAppバナー画像","className":"mb-4 rounded"}]}]}],["$","h1",null,{"className":"text-xl font-semibold mb-2","children":"化学の数字「0」について"}],["$","div",null,{"className":"flex justify-between mb-4","children":[["$","div",null,{"className":"text-left text-xs text-caption","children":["クリップ(",2,") コメント(",1,")"]}],["$","div",null,{"className":"text-right text-xs text-caption","children":"11/27 16:33"}]]}],["$","div",null,{"className":"coach-mark 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mb-1","children":"こんにちは。\n\nmolの計算がよくわからない為に、その後の計算(中和やph、電池の問題など)も解けないという推測のもとに回答しますね。そうではなく、単元ごとに意味のわからない部分があると言うことであれば、個別にご質問なさると良いと思います。\n\nまず、モルを難しく考えすぎてはいないですか？\n6.02×10^23個＝1 mol にしよう！と決めただけです。12個で1ダースと同じですね。\nそして、同じ原子を6.02×10^23個集めると、[その原子の原子量]g になります。\n同じ原子を6.02×10^23個集めたときの重さ、といちいち書くのは面倒なので、モル質量と呼びましょう。単位は1molで○gを分数にして g/mol ですね。\n\n炭素の原子量が12とします。いま、炭素が24 gあります。炭素の原子は何molありますか？ 簡単ですね、2 molです。個数でいえば2×6.02×10^23個ですね！\n(分子の時は少し気をつけて下さい。水素の原子量を1とします。水素ガスが4 gあります。このとき水素原子は4 mol存在しますが、水素ガス(分子)は2 molです。)\n\nこのくらいは分かってる！とお思いかも知れませんが、mol計算が苦手な方は単位変換が苦手な印象です。計算の時、単位同士も掛け算、割り算していますか？ もっとハイレベルな部分でわからないと言うことでしたら申し訳ありません…\n\nmolができれば、phや化学式も解けるはずです。\n電気分解などは多少慣れが必要ですが、一個の原子から何個の電子が出るのかを知っていれば後は比の計算ですから、こちらも大丈夫だと思います。\n\n最後に参考書ですが、私自身はあまり役に立ったと思えたことがありません。読んだ時は分かった気になるのですが…。結局、自分の言葉で説明できるように頭を使って理解するしかないと思います。参考書はその補助に使うものだと考えて、頑張ってください！"}],["$","div",null,{"className":"flex mb-1","children":[["$","svg",null,{"stroke":"currentColor","fill":"currentColor","strokeWidth":"0","viewBox":"0 0 24 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items-center py-4","children":[["$","div",null,{"className":"flex-1","children":[["$","div",null,{"className":"mb-1","children":"有効数字がわからない"}],["$","div",null,{"className":"text-xs text-caption line-clamp-2 mb-1","children":"はじめまして、ご質問にお答えさせていただきます、東京大学理科I類の者です。\n\n10^-1の場合はわざわざその表記にせず、0.112のように書いてあげれば良いです。\n\n有効数字は誤差を含みながらも、知りたい位まで(例えば実験などで機械が読み取れるであろう数値の限界)示れば良いです。\n\nそれを1.12×10^-1と答えようが、0.112と答えようがそこで点数が引かれるということは、大学入試においてはありえません。あるとすれば、表記の指定がある場合なので問題文はしっかり読んだほうがいいです。\n\nただ、基本的に問題文などに出てくる数値の表記に合わせてあげれば大丈夫なので、心配だというのであれば、合わせて書けばよろしいかと思います！\n"}],["$","div",null,{"className":"flex mb-1","children":[["$","svg",null,{"stroke":"currentColor","fill":"currentColor","strokeWidth":"0","viewBox":"0 0 24 24","className":"text-subPrimary mr-1","children":["$undefined",[["$","path","0",{"fill":"none","d":"M0 0h24v24H0V0z","children":[]}],["$","path","1",{"d":"M12 6c1.1 0 2 .9 2 2s-.9 2-2 2-2-.9-2-2 .9-2 2-2m0 10c2.7 0 5.8 1.29 6 2H6c.23-.72 3.31-2 6-2m0-12C9.79 4 8 5.79 8 8s1.79 4 4 4 4-1.79 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items-center py-4","children":[["$","div",null,{"className":"flex-1","children":[["$","div",null,{"className":"mb-1","children":"理解できない"}],["$","div",null,{"className":"text-xs text-caption line-clamp-2 mb-1","children":"\nこんにちは！東工大一年のたまちゃんです。\n物理や化学には有効数字というものがあります。\n問題を見ていないので、よくわからないのですが、問題文の中に出てくる数字も3×10^3などのように表されていないでしょうか？\n6×10^4は有効数字一桁であり、6.0+10^4は有効数字二桁、6.00×10^4は有効数字三桁となります。\nまた400は有効数字三桁、40は有効数字二桁です。\n解答をする際の原則として、問題文の中に出てくる値の有効数字に合わせるというものがあります。これが守られていないと減点対象となります。\nですから、問題文の中に出てくる値が有効数字一桁であるから、400だと減点されてしまいます。\n有効数字に関しての説明は難しいので、ネットなどで検索してみて下さい。\n拙い説明で申し訳ありません。"}],["$","div",null,{"className":"flex mb-1","children":[["$","svg",null,{"stroke":"currentColor","fill":"currentColor","strokeWidth":"0","viewBox":"0 0 24 24","className":"text-subPrimary mr-1","children":["$undefined",[["$","path","0",{"fill":"none","d":"M0 0h24v24H0V0z","children":[]}],["$","path","1",{"d":"M12 6c1.1 0 2 .9 2 2s-.9 2-2 2-2-.9-2-2 .9-2 2-2m0 10c2.7 0 5.8 1.29 6 2H6c.23-.72 3.31-2 6-2m0-12C9.79 4 8 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items-center py-4","children":[["$","div",null,{"className":"flex-1","children":[["$","div",null,{"className":"mb-1","children":"計算問題が全く解けない"}],["$","div",null,{"className":"text-xs text-caption line-clamp-2 mb-1","children":"こんにちは！\n北大志望ということで、お答えさせていただきます！\n\n①ゴールから逆算する事\n例えばpHを求める問題の時\npHを求めたい→pHは溶液の水素の濃度→H+ のmolと溶液の量が分かればいい。\nなどのように、ゴールから逆を辿る事で見えやすくなることがあります。\n必ず過程の1つ1つは基礎計算問題と同じです！\n\n②図を用いること\n 棒グラフや表などを意識的に使ってみてください！\n視覚化することで、どのような計算を実行すべきか分かりやすくなります！\n例えば、逆滴定の考えなどに棒グラフはとても有効です！\n\n以上2点が僕の意識してた事です。\n\n最初は誰も出来ません。\n問題演習を進めて行きながら、毎度色々な工夫をしてみてください！きっとあなたにピッタリな方法が見つかると思います！\n\n喜びの春を迎えることを、心より期待しております！\n"}],["$","div",null,{"className":"flex mb-1","children":[["$","svg",null,{"stroke":"currentColor","fill":"currentColor","strokeWidth":"0","viewBox":"0 0 24 24","className":"text-subPrimary mr-1","children":["$undefined",[["$","path","0",{"fill":"none","d":"M0 0h24v24H0V0z","children":[]}],["$","path","1",{"d":"M12 6c1.1 0 2 .9 2 2s-.9 2-2 2-2-.9-2-2 .9-2 2-2m0 10c2.7 0 5.8 1.29 6 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items-center py-4","children":[["$","div",null,{"className":"flex-1","children":[["$","div",null,{"className":"mb-1","children":"化学式 イオン式 書き方"}],["$","div",null,{"className":"text-xs text-caption line-clamp-2 mb-1","children":"こんにちは！東工大一年のたまちゃんです。\n質問の意図がイマイチわからないのですが、私が思ったことを書きます。\n周期表の第3周期を例にとりますが、第1族のナトリウムは+1のイオンになりやすいです。2族のマグネシウムは+2のイオンになりやすいです。これは最外殻原子の数がそれぞれ1個と2個のためです。同様にして13族は+3になりやすいです。しかし、最外殻電子が3個ということは+3になりやすいと同時に-5にもなりやすいということになります。最外殻原子が3つならば、そこに5つ電子を加えれば、合計8個となり閉殻となるためです。よって14族は+4,-4になりやすいです。これは典型元素では、成立しますが、遷移元素では成立しません。\nこれが分かると、少し覚えやすくなるかもしれないです。(知っていたらすみません)\n例えばH2OはHは+1になりやすく、Oは-2になりやすいのでトータル±0となります。CO2なら、Cは+4になりやすく、Oは-2となりますので、トータル±0となります。H2SO4なら、Hは+1になりやすく、Oは-2になりやすいです。Sも-2になりやすいのですが、裏を返せば、+6になりやすいという事です。Sを+6とするとトータル±0となります。\nこの方法は例外もあるのですが、酸化数を調べる時に用いる方法です。\nただ、イオンなどはやっていくうちに覚えられるものです。声に出したりして覚えましょう。\n硫酸なら「エイチツーエスオーフォー」と声に出して覚えましょう。自分でリズムを刻みながら声に出すと、より覚えやすくなるかもです笑\n意外とすぐに覚えるものなので、心配なさらなくて大丈夫だと思います。\n"}],["$","div",null,{"className":"flex 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items-center py-4","children":[["$","div",null,{"className":"flex-1","children":[["$","div",null,{"className":"mb-1","children":"物理と化学についてです！"}],["$","div",null,{"className":"text-xs text-caption line-clamp-2 mb-1","children":"はじめまして！やきそばといいます。\n質問について\n①演習量について物理化学それぞれ分けて、\n②微積を用いた物理について、\n回答していきます。\n\n①まず物理ですが、先生の仰る通りテキストを完璧にすることが重要だと思います。物理は定義や基本の原理原則を抑えていないと、どれだけ演習をしても伸びにくい科目です。まずはテキストで原理原則などを理解してみてください。演習は、テキストの復習としてリードαで感覚を掴んだ後、名問の森に移るなどがおすすめですが、微積物理であれば新物理入門問題演習という問題集がおすすめです。\n   次に化学ですが、理論・無機・有機全ての分野で演習量がものを言う科目です。授業の後に基本的な問題集(リードαやセミナーなど)で復習して、重要問題集、そしてそれが8割程度できるようになったら化学の新演習などでたくさんの形式の問題に触れるといいと思います。\n\n②微積物理ですが、一番重要なのは数式の意味を理解すること、です。なぜ運動方程式を積分するとエネルギーの関係式になるのか、なぜモーメントの関係式を積分すると角運動量の関係式になるのか、など意味や理由が分からないと、どの問題でどのような操作をするのか(微分や積分をするのか、しないのか)が分からないのでぜひ理解してください。\n慣れも必要ですが、慣れるためと言って理解を怠って問題演習ばかりしていると、微積を利用する良さが消えてしまうので気をつけてください。私が利用していた新物理入門問題演習には、問題の前に軽く式の関係性が書かれていて非常に良かったのでおすすめです。\n\n他に気になることがあればメッセージ送ってください！\n限りある時間で工夫して勉強頑張ってください、応援してます！\n"}],["$","div",null,{"className":"flex mb-1","children":[["$","svg",null,{"stroke":"currentColor","fill":"currentColor","strokeWidth":"0","viewBox":"0 0 24 24","className":"text-subPrimary mr-1","children":["$undefined",[["$","path","0",{"fill":"none","d":"M0 0h24v24H0V0z","children":[]}],["$","path","1",{"d":"M12 6c1.1 0 2 .9 2 2s-.9 2-2 2-2-.9-2-2 .9-2 2-2m0 10c2.7 0 5.8 1.29 6 2H6c.23-.72 3.31-2 6-2m0-12C9.79 4 8 5.79 8 8s1.79 4 4 4 4-1.79 4-4-1.79-4-4-4zm0 10c-2.67 0-8 1.34-8 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items-center py-4","children":[["$","div",null,{"className":"flex-1","children":[["$","div",null,{"className":"mb-1","children":"中和滴定に電離度がなぜ関係ないのか"}],["$","div",null,{"className":"text-xs text-caption line-clamp-2 mb-1","children":"それは確かに私も不思議に思っていました。\n\n私は化学の専門家ではないので、あくまで一つの考え方として見て下さい。詳しいことは、化学の先生などにうかがったほうがいいと思います。\n\n後々習うとは思いますが、物質は電離するとき、電離平衡というバランスをとります。たとえばアンモニアでは、\nNH3 H2O ⇌NH4  OH-\nとなります。\n矢印が両方向にあることからも分かると思いますが、反応は右にも左にも進みます。NH3とNH4 ,OH-の濃度の比が一定になるように反応が起こります。\n\n塩酸を加えると、H とOH-が反応して、H2Oが生成します。すると、OH-の濃度は減少するわけです。そうなると先ほどの電離式の左右の比が崩れてしまうため、それを補うように反応が右に進みます。すると、アンモニアがさらに電離します。\nこれが続いていくと、アンモニアは続々と電離していき、最終的には全て電離することになります。\n\nこう考えると、少し納得がいく気がします。\n\nちなみに、電離度というのは、先ほどの電離式のそれぞれの濃度の比から導き出された値になります。高3になると、その算出の仕方も学ぶと思いますので、楽しみにしておいて下さい。"}],["$","div",null,{"className":"flex mb-1","children":[["$","svg",null,{"stroke":"currentColor","fill":"currentColor","strokeWidth":"0","viewBox":"0 0 24 24","className":"text-subPrimary 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items-center py-4","children":[["$","div",null,{"className":"flex-1","children":[["$","div",null,{"className":"mb-1","children":"中和滴定での標準液の調整"}],["$","div",null,{"className":"text-xs text-caption line-clamp-2 mb-1","children":"初めまして\n\n質問の意図は、ビーカーで最初1モル溶かしてその後メスフラスコに移動させるなら、完全にビーカーから移動させるのは不可能でどうしても水滴が少しビーカーに残ってしまう、その中にシュウ酸が含まれているから、結局メスフラスコに入っているシュウ酸は1モルより若干少ないのでは？というものと解釈して進めます 違ったらごめんなさい\n\n基本的に化学の問題や話の中で、溶液を移動したら、などという文言があれば、それは【簡単のため】100%移動したことになります もちろんこれは現実世界とは少し異なりますが、そもそも大帝の問題で理想気体として話を進めている時点で高校化学の大半は現実世界とは少し異なる都合のいい世界での話をしているので、そこは割り切るのがいいと思います\n\nあまりスッキリしない解答だったかもしれませんが、残りの受験勉強も頑張ってください🙏"}],["$","div",null,{"className":"flex mb-1","children":[["$","svg",null,{"stroke":"currentColor","fill":"currentColor","strokeWidth":"0","viewBox":"0 0 24 24","className":"text-subPrimary mr-1","children":["$undefined",[["$","path","0",{"fill":"none","d":"M0 0h24v24H0V0z","children":[]}],["$","path","1",{"d":"M12 6c1.1 0 2 .9 2 2s-.9 2-2 2-2-.9-2-2 .9-2 2-2m0 10c2.7 0 5.8 1.29 6 2H6c.23-.72 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